Answer Back Factfile 500 - Arithmetic (UK) (Face A) (1985) (Extension) [Original] [TAPE].cdt

[STRUCTURE]

Answer Back Factfile 500 - Arithmetic (UK) (Face A) (1985) (Extension) [Original] [TAPE].cdt


Creator : ZXTape!
Total of blocks : 25
Blocks format : [P]PAUSE[/P] (1), [P]TURBO LOADING DATA[/P] (24)[/STRUCTURE]
Catalogue
CheckData
BLOCKSTOTAL
PAUSE1
TURBO LOADING DATA24
TOTAL25

SUM OF ALL DATA1 233 575
Sum of data for Turbo Loading - Turbo Loading size 1 byte1 233 575- 01 233 575
Sum of data for Pure Data - Pure Data size 3 bytes (sum = 262)0- 00
 
Result 1 233 575- 01 233 575
BLOCKTYPE BLOCKSUMDATAUsed bits
in last byte		Last
byte		DATA
0000PAUSE 
0001TURBO LOADING DATA2 7338FF263
0002TURBO LOADING DATA119 4888FF2069
0003TURBO LOADING DATA2 4428FF263
0004TURBO LOADING DATA97 1448FF1811
0005TURBO LOADING DATA2 5758FF263
0006TURBO LOADING DATA95 4298FF1811
0007TURBO LOADING DATA2 4718FF263
0008TURBO LOADING DATA126 9418FF1811
0009TURBO LOADING DATA2 0718FF263
0010TURBO LOADING DATA150 2478FF2069
0011TURBO LOADING DATA2 4808FF263
0012TURBO LOADING DATA19 2608FF263
0013TURBO LOADING DATA2 5298FF263
0014TURBO LOADING DATA113 2108FF2069
0015TURBO LOADING DATA2 5348FF263
0016TURBO LOADING DATA89 0038FF1553
0017TURBO LOADING DATA1 9548FF263
0018TURBO LOADING DATA104 6418FF2069
0019TURBO LOADING DATA2 0058FF263
0020TURBO LOADING DATA5 5238FF263
0021TURBO LOADING DATA2 3468FF263
0022TURBO LOADING DATA130 2528FF2069
0023TURBO LOADING DATA2 6808FF263
0024TURBO LOADING DATA153 6178FF2069

CATALOGUE
BLOCKFILENAMEFILE BLOCKFIRST BLOCKLAST BLOCKFILE TYPESTARTLENGTHEXECUTIONLENGTH FILE
0001AR11YESYESBinaire&6000&07E5&0000&07E5
0003AR21YESYESBinaire&6000&0656&0000&0656
0005AR31YESYESBinaire&6000&06CA&0000&06CA
0007AR41YESYESBinaire&6000&06E0&0000&06E0
0009AR51YES-Binaire&6000&0800&0000&08FC
0011AR52-YESBinaire&6800&00FC&0000&08FC
0013AR61YESYESBinaire&6000&07B3&0000&07B3
0015AR71YESYESBinaire&6000&05CC&0000&05CC
0017AR81YES-Binaire&6000&0800&0000&0876
0019AR82-YESBinaire&6800&0076&0000&0876
0021AR91YESYESBinaire&6000&0781&0000&0781
0023AR101YESYESBinaire&6000&07CF&0000&07CF

ZXTape! Major Version : 01 Minor Version : 0D
next* BLOCK 0000 : PAUSE
Total size : 3 bytes
Pause : 15848ms
previousnext* BLOCK 0001 : TURBO LOADING DATA
HEADER
Block Name : AR1
Block Number : 1
Block first : YES
Block last : YES
File type : Binaire
File adress start : &6000
File adress length : &07E5
File adress execution : &0000
File length file : &07E5

Length of PILOT pulse : 2531
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1327
Length of ONE bit pulse : 2493
Length of PILOT tone : 4099
Used bits in last byte : 8 OK
Pause After this block : 23ms
Data : 263 bytes
Total size : 282 bytes

Sum DATA : 2 733		000000: 2C 41 52 31 00 00 00 00 00 00 00 00 00 00 00 00 ,AR1............ 000010: 00 01 FF 02 E5 07 00 60 FF E5 07 00 00 00 00 00 .......`........ 000020: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000030: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000040: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000050: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000060: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000070: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000080: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000090: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000A0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000B0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000C0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000D0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000E0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000F0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000100: 00 E0 A8 FF FF FF FF .......
previousnext* BLOCK 0002 : TURBO LOADING DATA
DATA
Length of PILOT pulse : 2531
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1369
Length of ONE bit pulse : 2424
Length of PILOT tone : 4099
Used bits in last byte : 8 OK
Pause After this block : 13470ms
Data : 2069 bytes
Total size : 2088 bytes

Sum DATA : 119 488		000000: 16 41 52 31 00 00 00 00 00 00 00 00 19 E4 07 00 .AR1............ 000010: 42 65 67 69 6E 6E 69 6E 67 20 41 64 64 69 74 69 Beginning Additi 000020: 6F 6E 20 20 20 20 20 20 20 00 00 00 00 00 00 00 on ....... 000030: 00 3B 00 20 20 20 20 20 20 20 20 20 20 20 20 20 .;. 000040: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000050: 20 20 20 20 20 20 39 20 2B 20 34 20 3D 20 3F 1B 9 + 4 = ?. 000060: 31 33 1B 31 32 1B 31 34 1B 31 35 1B 24 00 41 64 13.12.14.15.$.Ad 000070: 64 20 31 20 74 65 6E 20 61 6E 64 20 35 20 75 6E d 1 ten and 5 un 000080: 69 74 73 1B 31 35 1B 35 31 1B 32 30 1B 31 30 1B its.15.51.20.10. 000090: 5C 00 57 68 61 74 20 69 73 20 74 68 65 20 6D 69 \.What is the mi 0000A0: 73 73 69 6E 67 20 6E 75 6D 62 65 72 3F 20 20 20 ssing number? 0000B0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0000C0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0000D0: 20 20 20 38 20 2B 20 3F 20 3D 20 31 38 20 20 20 8 + ? = 18 0000E0: 20 1B 31 30 1B 31 32 1B 38 1B 39 1B 6A 00 57 68 .10.12.8.9.j.Wh 0000F0: 61 74 20 6E 75 6D 62 65 72 73 20 63 6F 6D 65 20 at numbers come 000100: 6E C5 D4 65 78 74 3F 20 20 20 20 20 20 20 20 20 n..ext? 000110: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000120: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 31 1 000130: 2C 20 32 2C 20 33 2C 20 3F 2C 20 3F 2E 1B 34 20 , 2, 3, ?, ?..4 000140: 61 6E 64 20 35 1B 36 20 61 6E 64 20 37 1B 38 20 and 5.6 and 7.8 000150: 61 6E 64 20 39 1B 20 1B 61 00 49 66 20 41 6E 6E and 9. .a.If Ann 000160: 20 68 61 64 20 34 20 6F 72 61 6E 67 65 73 20 61 had 4 oranges a 000170: 6E 64 20 4A 61 6E 65 20 68 61 64 20 36 20 6F 72 nd Jane had 6 or 000180: 61 6E 67 65 73 20 68 6F 77 20 6D 61 6E 79 20 6F anges how many o 000190: 72 61 6E 67 65 73 64 69 64 20 74 68 65 79 20 68 rangesdid they h 0001A0: 61 76 65 20 61 6C 74 6F 67 65 74 68 65 72 3F 1B ave altogether?. 0001B0: 31 30 1B 38 1B 37 1B 36 1B 3C 00 20 20 20 20 20 10.8.7.6.<. 0001C0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0001D0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 31 34 14 0001E0: 20 2B 20 32 20 3D 20 3F 1B 31 36 1B 31 35 1B 31 + 2 = ?.16.15.1 0001F0: 38 1B 31 37 1B 24 00 41 64 64 20 31 20 74 65 6E 8.17.$.Add 1 ten 000200: 20 61 6E AE C9 64 20 37 20 75 6E 69 74 73 1B 31 an..d 7 units.1 000210: 37 1B 31 35 1B 31 30 1B 37 31 1B 5F 00 46 69 6E 7.15.10.71._.Fin 000220: 64 20 74 68 65 20 6D 69 73 73 69 6E 67 20 6E 75 d the missing nu 000230: 6D 62 65 72 3A 20 20 20 20 20 20 20 20 20 20 20 mber: 000240: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000250: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 34 20 4 000260: 2B 20 3F 20 3D 20 36 20 20 20 20 20 20 20 20 20 + ? = 6 000270: 20 1B 32 1B 33 1B 31 1B 34 1B 73 00 57 68 61 74 .2.3.1.4.s.What 000280: 20 6E 75 6D 62 65 72 73 20 63 6F 6D 65 20 6E 65 numbers come ne 000290: 78 74 3F 20 20 20 20 20 20 20 20 20 20 20 20 20 xt? 0002A0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0002B0: 20 20 20 20 20 20 20 20 20 20 20 31 31 2C 20 31 11, 1 0002C0: 32 2C 20 31 33 2C 20 3F 2C 20 3F 2E 1B 31 34 20 2, 13, ?, ?..14 0002D0: 61 6E 64 20 31 35 1B 31 36 20 61 6E 64 20 31 37 and 15.16 and 17 0002E0: 1B 31 38 20 61 6E 64 20 31 39 1B 20 1B 58 00 50 .18 and 19. .X.P 0002F0: 65 74 65 72 20 68 61 73 20 74 77 6F 20 63 6F 6E eter has two con 000300: 6B 65 72 73 20 FF 4D 61 6E 64 20 20 20 20 20 66 kers .Mand f 000310: 69 6E 64 73 20 74 68 72 65 65 20 6D 6F 72 65 2E inds three more. 000320: 20 48 6F 77 20 6D 61 6E 79 20 20 20 20 64 6F 65 How many doe 000330: 73 20 68 65 20 6E 6F 77 20 68 61 76 65 3F 1B 35 s he now have?.5 000340: 1B 36 1B 34 1B 37 1B 3C 00 20 20 20 20 20 20 20 .6.4.7.<. 000350: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000360: 20 20 20 20 20 20 20 20 20 20 20 20 35 20 2B 20 5 + 000370: 31 31 20 3D 20 3F 1B 31 36 1B 31 35 1B 31 37 1B 11 = ?.16.15.17. 000380: 31 34 1B 23 00 41 64 64 20 31 20 74 65 6E 20 61 14.#.Add 1 ten a 000390: 6E 64 20 32 20 75 6E 69 74 73 1B 31 32 1B 31 34 nd 2 units.12.14 0003A0: 1B 32 31 1B 33 1B 5A 00 57 68 61 74 20 69 73 20 .21.3.Z.What is 0003B0: 74 68 65 20 6D 69 73 73 69 6E 67 20 6E 75 6D 62 the missing numb 0003C0: 65 72 3F 20 20 20 20 20 20 20 20 20 20 20 20 20 er? 0003D0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0003E0: 20 20 20 20 20 20 20 20 20 36 20 2B 20 3F 20 3D 6 + ? = 0003F0: 20 31 35 20 20 20 1B 39 1B 31 30 1B 38 1B 37 1B 15 .9.10.8.7. 000400: 77 00 57 68 61 74 20 B7 1D 6E 75 6D 62 65 72 73 w.What ..numbers 000410: 20 63 6F 6D 65 20 6E 65 78 74 3F 20 20 20 20 20 come next? 000420: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000430: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000440: 20 20 20 36 2C 20 37 2C 20 38 2C 20 3F 2C 20 3F 6, 7, 8, ?, ? 000450: 2E 1B 39 20 61 6E 64 20 31 30 1B 31 31 20 61 6E ..9 and 10.11 an 000460: 64 20 31 32 1B 31 33 20 61 6E 64 20 31 34 1B 31 d 12.13 and 14.1 000470: 31 20 61 6E 64 20 31 33 1B 71 00 53 61 6C 6C 79 1 and 13.q.Sally 000480: 20 68 61 73 20 31 20 68 61 6D 73 74 65 72 2C 20 has 1 hamster, 000490: 35 20 20 20 20 20 20 20 20 67 6F 6C 64 66 69 73 5 goldfis 0004A0: 68 20 61 6E 64 20 33 20 72 61 62 62 69 74 73 2E h and 3 rabbits. 0004B0: 20 48 6F 77 20 20 20 6D 61 6E 79 20 70 65 74 73 How many pets 0004C0: 20 64 6F 65 73 20 73 68 65 20 68 61 76 65 20 20 does she have 0004D0: 20 20 20 20 20 61 6C 74 6F 67 65 74 68 65 72 3F altogether? 0004E0: 1B 39 1B 37 1B 38 1B 31 30 1B 3A 00 20 20 20 20 .9.7.8.10.:. 0004F0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000500: 20 20 20 20 20 20 20 20 20 35 1D 20 20 20 20 31 5. 1 000510: 38 20 2B 20 31 20 3D 20 3F 1B 31 39 1B 32 30 1B 8 + 1 = ?.19.20. 000520: 31 37 1B 31 38 1B 3A 00 20 20 20 20 20 20 20 20 17.18.:. 000530: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000540: 20 20 20 20 20 20 20 20 20 20 20 34 20 2B 20 37 4 + 7 000550: 20 3D 20 3F 1B 31 31 1B 31 30 1B 39 1B 31 32 1B = ?.11.10.9.12. 000560: 59 00 46 69 6E 64 20 74 68 65 20 6D 69 73 73 69 Y.Find the missi 000570: 6E 67 20 6E 75 6D 62 65 72 3A 20 20 20 20 20 20 ng number: 000580: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000590: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0005A0: 20 20 20 31 20 2B 20 3F 20 3D 20 37 20 20 20 20 1 + ? = 7 0005B0: 1B 36 1B 35 1B 37 1B 34 1B 3A 00 20 20 20 20 20 .6.5.7.4.:. 0005C0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0005D0: 20 20 20 20 20 20 20 20 20 20 20 20 20 38 20 2B 8 + 0005E0: 20 36 20 3D 20 3F 1B 31 34 1B 31 32 1B 31 36 1B 6 = ?.14.12.16. 0005F0: 31 35 1B 50 00 53 69 6D 6F 6E 20 68 61 64 20 39 15.P.Simon had 9 000600: 20 6D 61 72 62 6C 65 73 20 61 6E 37 D9 64 20 77 marbles an7.d w 000610: 6F 6E 20 20 20 74 77 6F 20 6D 6F 72 65 2E 20 48 on two more. H 000620: 6F 77 20 6D 61 6E 79 20 64 6F 65 73 20 68 65 20 ow many does he 000630: 6E 6F 77 68 61 76 65 3F 1B 31 31 1B 31 30 1B 31 nowhave?.11.10.1 000640: 32 1B 31 33 1B 39 00 20 20 20 20 20 20 20 20 20 2.13.9. 000650: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000660: 20 20 20 20 20 20 20 20 20 20 39 20 2B 20 30 20 9 + 0 000670: 3D 20 3F 1B 39 1B 38 1B 31 30 1B 31 31 1B 24 00 = ?.9.8.10.11.$. 000680: 41 64 64 20 32 20 74 65 6E 73 20 61 6E 64 20 34 Add 2 tens and 4 000690: 20 75 6E 69 74 73 1B 32 34 1B 36 1B 34 32 1B 32 units.24.6.42.2 0006A0: 32 1B 58 00 46 69 6E 64 20 74 68 65 20 6D 69 73 2.X.Find the mis 0006B0: 73 69 6E 67 20 6E 75 6D 62 65 72 3A 20 20 20 20 sing number: 0006C0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0006D0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0006E0: 20 20 20 20 20 33 20 2B 20 3F 20 3D 20 38 20 20 3 + ? = 8 0006F0: 20 1B 35 1B 36 1B 34 1B 37 1B 7A 00 46 69 6E 64 .5.6.4.7.z.Find 000700: 20 74 68 65 20 6D 69 73 73 69 6E 67 20 80 99 6E the missing ..n 000710: 75 6D 62 65 72 73 3A 20 20 20 20 20 20 20 20 20 umbers: 000720: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000730: 20 20 20 20 20 20 20 20 20 20 20 20 20 31 34 2C 14, 000740: 20 31 35 2C 20 3F 2C 20 3F 2C 20 31 38 1B 31 36 15, ?, ?, 18.16 000750: 20 61 6E 64 20 31 37 1B 31 38 20 61 6E 64 20 31 and 17.18 and 1 000760: 39 1B 31 39 20 61 6E 64 20 32 30 1B 31 35 20 61 9.19 and 20.15 a 000770: 6E 64 20 31 38 1B 7D 00 46 6F 75 72 20 63 68 69 nd 18.}.Four chi 000780: 6C 64 72 65 6E 20 73 61 74 20 61 74 20 6F 6E 65 ldren sat at one 000790: 20 74 61 62 6C 65 61 6E 64 20 66 69 76 65 20 63 tableand five c 0007A0: 68 69 6C 64 72 65 6E 20 73 61 74 20 61 74 20 20 hildren sat at 0007B0: 20 20 20 20 61 6E 6F 74 68 65 72 2E 20 48 6F 77 another. How 0007C0: 20 6D 61 6E 79 20 63 68 69 6C 64 72 65 6E 20 20 many children 0007D0: 20 20 77 65 72 65 20 74 68 65 72 65 20 61 6C 74 were there alt 0007E0: 6F 67 65 74 68 65 72 3F 1B 39 1B 31 30 1B 38 1B ogether?.9.10.8. 0007F0: 31 31 1B 1C 00 00 00 00 00 00 00 00 00 00 00 00 11.............. 000800: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 37 ...............7 000810: 71 FF FF FF FF q....
previousnext* BLOCK 0003 : TURBO LOADING DATA
HEADER
Block Name : AR2
Block Number : 1
Block first : YES
Block last : YES
File type : Binaire
File adress start : &6000
File adress length : &0656
File adress execution : &0000
File length file : &0656

Length of PILOT pulse : 2523
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1324
Length of ONE bit pulse : 2469
Length of PILOT tone : 4099
Used bits in last byte : 8 OK
Pause After this block : 22ms
Data : 263 bytes
Total size : 282 bytes

Sum DATA : 2 442		000000: 2C 41 52 32 00 00 00 00 00 00 00 00 00 00 00 00 ,AR2............ 000010: 00 01 FF 02 56 06 00 60 FF 56 06 00 00 00 00 00 ....V..`.V...... 000020: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000030: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000040: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000050: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000060: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000070: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000080: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000090: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000A0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000B0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000C0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000D0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000E0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000F0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000100: 00 A9 DB FF FF FF FF .......
previousnext* BLOCK 0004 : TURBO LOADING DATA
DATA
Length of PILOT pulse : 2521
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1364
Length of ONE bit pulse : 2422
Length of PILOT tone : 4099
Used bits in last byte : 8 OK
Pause After this block : 13415ms
Data : 1811 bytes
Total size : 1830 bytes

Sum DATA : 97 144		000000: 16 41 52 32 00 00 00 00 00 00 00 00 19 55 06 00 .AR2.........U.. 000010: 42 65 67 69 6E 6E 69 6E 67 20 53 75 62 74 72 61 Beginning Subtra 000020: 63 74 69 6F 6E 20 20 20 20 00 00 00 00 00 00 00 ction ....... 000030: 00 39 00 20 20 20 20 20 20 20 20 20 20 20 20 20 .9. 000040: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000050: 20 20 20 20 20 20 31 38 20 2D 20 31 30 20 3D 20 18 - 10 = 000060: 3F 1B 38 1B 39 1B 37 1B 36 1B 39 00 57 68 61 74 ?.8.9.7.6.9.What 000070: 20 69 73 20 74 68 65 20 64 69 66 66 65 72 65 6E is the differen 000080: 63 65 20 20 20 20 20 20 20 20 62 65 74 77 65 65 ce betwee 000090: 6E 20 38 20 61 6E 64 20 34 3F 1B 34 1B 35 1B 36 n 8 and 4?.4.5.6 0000A0: 1B 33 1B 21 00 35 20 74 61 6B 65 20 61 77 61 79 .3.!.5 take away 0000B0: 20 32 20 6C 65 61 76 65 73 20 3F 1B 33 1B 34 1B 2 leaves ?.3.4. 0000C0: 37 1B 32 1B 5A 00 46 69 6E 64 20 74 68 65 20 6D 7.2.Z.Find the m 0000D0: 69 73 73 69 6E 67 20 6E 75 6D 62 65 72 3A 20 20 issing number: 0000E0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0000F0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000100: 20 4E 83 20 20 20 20 20 33 20 2D 20 3F 20 3D 20 N. 3 - ? = 000110: 32 20 20 20 20 20 20 1B 31 1B 32 1B 33 1B 34 1B 2 .1.2.3.4. 000120: 55 00 4A 61 6E 65 20 62 6F 75 67 68 74 20 36 20 U.Jane bought 6 000130: 70 65 6E 63 69 6C 73 20 61 6E 64 20 67 61 76 65 pencils and gave 000140: 34 20 74 6F 20 68 65 72 20 66 72 69 65 6E 64 73 4 to her friends 000150: 2E 20 48 6F 77 20 6D 61 6E 79 20 64 69 64 73 68 . How many didsh 000160: 65 20 68 61 76 65 20 6C 65 66 74 3F 1B 32 1B 33 e have left?.2.3 000170: 1B 34 1B 31 1B 36 00 20 20 20 20 20 20 20 20 20 .4.1.6. 000180: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000190: 20 20 20 20 20 20 20 20 20 39 20 2D 20 33 20 3D 9 - 3 = 0001A0: 20 3F 1B 36 1B 37 1B 35 1B 34 1B 3E 00 57 68 61 ?.6.7.5.4.>.Wha 0001B0: 74 20 69 73 20 74 68 65 20 64 69 66 66 65 72 65 t is the differe 0001C0: 6E 63 65 20 20 20 20 20 20 20 20 62 65 74 77 65 nce betwe 0001D0: 65 6E 20 31 34 20 61 6E 64 20 33 3F 1B 31 31 1B en 14 and 3?.11. 0001E0: 31 32 1B 31 30 1B 31 37 1B 40 00 20 20 20 20 20 12.10.17.@. 0001F0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000200: 20 20 20 2D CF 20 20 20 20 20 20 39 20 74 61 6B -. 9 tak 000210: 65 20 61 77 61 79 20 32 20 6C 65 61 76 65 73 20 e away 2 leaves 000220: 3F 1B 37 1B 38 1B 31 31 1B 36 1B 5A 00 57 68 61 ?.7.8.11.6.Z.Wha 000230: 74 20 69 73 20 74 68 65 20 6D 69 73 73 69 6E 67 t is the missing 000240: 20 6E 75 6D 62 65 72 3F 20 20 20 20 20 20 20 20 number? 000250: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000260: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 39 20 9 000270: 2D 20 3F 20 3D 20 34 20 20 20 20 20 1B 35 1B 36 - ? = 4 .5.6 000280: 1B 34 1B 37 1B 21 00 43 6F 75 6E 74 20 62 61 63 .4.7.!.Count bac 000290: 6B 20 36 20 66 72 6F 6D 20 31 36 1B 31 30 1B 39 k 6 from 16.10.9 0002A0: 1B 31 32 1B 38 1B 36 00 20 20 20 20 20 20 20 20 .12.8.6. 0002B0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0002C0: 20 20 20 20 20 20 20 20 20 20 37 20 2D 20 34 20 7 - 4 0002D0: 3D 20 3F 1B 33 1B 34 1B 32 1B 35 1B 3C 00 57 68 = ?.3.4.2.5.<.Wh 0002E0: 61 74 20 69 73 20 74 68 65 20 64 69 66 66 65 72 at is the differ 0002F0: 65 6E 63 65 20 20 20 20 20 20 20 20 62 65 74 77 ence betw 000300: 65 65 6E 20 31 2B AA 39 20 61 6E 64 20 38 3F 1B een 1+.9 and 8?. 000310: 31 31 1B 38 1B 39 1B 31 30 1B 22 00 38 20 74 61 11.8.9.10.".8 ta 000320: 6B 65 20 61 77 61 79 20 32 20 6C 65 61 76 65 73 ke away 2 leaves 000330: 20 3F 1B 36 1B 37 1B 31 30 1B 35 1B 36 00 20 20 ?.6.7.10.5.6. 000340: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000350: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000360: 36 20 2D 20 3F 20 3D 20 30 1B 36 1B 30 1B 35 1B 6 - ? = 0.6.0.5. 000370: 32 1B 55 00 41 20 66 61 72 6D 65 72 20 68 61 64 2.U.A farmer had 000380: 20 31 38 20 73 68 65 65 70 20 62 75 74 20 68 65 18 sheep but he 000390: 20 20 73 6F 6C 64 20 74 68 72 65 65 2E 20 48 6F sold three. Ho 0003A0: 77 20 6D 61 6E 79 20 64 69 64 20 68 65 20 20 20 w many did he 0003B0: 68 61 76 65 20 6C 65 66 74 3F 1B 31 35 1B 31 37 have left?.15.17 0003C0: 1B 31 33 1B 31 34 1B 3C 00 20 20 20 20 20 20 20 .13.14.<. 0003D0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0003E0: 20 20 20 20 20 20 20 20 20 20 20 20 31 35 20 2D 15 - 0003F0: 20 31 20 3D 20 3F 1B 31 34 1B 31 35 1B 31 36 1B 1 = ?.14.15.16. 000400: 31 33 1B 5B 00 57 68 72 2D 61 74 20 69 73 20 74 13.[.Whr-at is t 000410: 68 65 20 6D 69 73 73 69 6E 67 20 6E 75 6D 62 65 he missing numbe 000420: 72 3F 20 20 20 20 20 20 20 20 20 20 20 20 20 20 r? 000430: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000440: 20 20 20 20 20 20 20 20 31 37 20 2D 20 3F 20 3D 17 - ? = 000450: 20 31 31 20 20 20 20 1B 36 1B 37 1B 35 1B 34 1B 11 .6.7.5.4. 000460: 3E 00 57 68 61 74 20 69 73 20 74 68 65 20 64 69 >.What is the di 000470: 66 66 65 72 65 6E 63 65 20 20 20 20 20 20 20 20 fference 000480: 62 65 74 77 65 65 6E 20 31 37 20 61 6E 64 20 35 between 17 and 5 000490: 3F 1B 31 32 1B 31 33 1B 31 35 1B 31 30 1B 59 00 ?.12.13.15.10.Y. 0004A0: 57 68 61 74 20 6E 75 6D 62 65 72 20 69 73 20 6D What number is m 0004B0: 69 73 73 69 6E 67 20 66 72 6F 6D 20 20 20 74 68 issing from th 0004C0: 69 73 20 6E 75 6D 62 65 72 20 73 65 6E 74 65 6E is number senten 0004D0: 63 65 3F 20 20 20 20 20 20 20 20 20 20 20 20 20 ce? 0004E0: 31 36 20 2D 20 3F 20 3D 20 31 31 20 20 20 1B 35 16 - ? = 11 .5 0004F0: 1B 34 1B 38 1B 32 1B 54 00 50 68 69 6C 69 70 20 .4.8.2.T.Philip 000500: 68 61 64 20 31 35 20 6D 6F 49 41 64 65 6C 20 63 had 15 moIAdel c 000510: 61 72 73 20 62 75 74 20 20 68 65 20 6C 6F 73 74 ars but he lost 000520: 20 34 2E 20 48 6F 77 20 6D 61 6E 79 20 64 69 64 4. How many did 000530: 20 68 65 20 20 20 20 68 61 76 65 20 6C 65 66 74 he have left 000540: 3F 1B 31 31 1B 39 1B 31 33 1B 31 32 1B 3C 00 20 ?.11.9.13.12.<. 000550: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000560: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000570: 20 20 31 39 20 2D 20 36 20 3D 20 3F 1B 31 33 1B 19 - 6 = ?.13. 000580: 31 35 1B 31 32 1B 31 34 1B 39 00 57 68 61 74 20 15.12.14.9.What 000590: 69 73 20 74 68 65 20 64 69 66 66 65 72 65 6E 63 is the differenc 0005A0: 65 20 20 20 20 20 20 20 20 62 65 74 77 65 65 6E e between 0005B0: 20 36 20 61 6E 64 20 35 3F 1B 31 1B 33 1B 32 1B 6 and 5?.1.3.2. 0005C0: 35 1B 24 00 31 31 20 74 61 6B 65 20 61 77 61 79 5.$.11 take away 0005D0: 20 31 20 6C 65 61 76 65 73 20 3F 1B 31 30 1B 31 1 leaves ?.10.1 0005E0: 31 1B 38 1B 39 1B 5C 00 57 68 61 74 20 6E 75 6D 1.8.9.\.What num 0005F0: 62 65 72 20 69 73 20 6D 69 73 73 69 6E 67 3F 20 ber is missing? 000600: 20 20 20 20 20 20 20 20 20 20 20 B8 25 20 20 20 .% 000610: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000620: 20 20 20 20 20 20 20 20 20 20 20 31 38 20 2D 20 18 - 000630: 3F 20 3D 20 31 33 20 20 20 20 20 1B 35 1B 36 1B ? = 13 .5.6. 000640: 37 1B 34 1B 1E 00 43 6F 75 6E 74 20 62 61 63 6B 7.4...Count back 000650: 20 34 20 66 72 6F 6D 20 39 1B 35 1B 37 1B 38 1B 4 from 9.5.7.8. 000660: 34 1B 1C 00 00 00 00 00 00 00 00 00 00 00 00 00 4............... 000670: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000680: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000690: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0006A0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0006B0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0006C0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0006D0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0006E0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0006F0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000700: 00 00 00 00 00 00 00 00 00 00 00 00 00 B7 6D FF ..............m. 000710: FF FF FF ...
previousnext* BLOCK 0005 : TURBO LOADING DATA
HEADER
Block Name : AR3
Block Number : 1
Block first : YES
Block last : YES
File type : Binaire
File adress start : &6000
File adress length : &06CA
File adress execution : &0000
File length file : &06CA

Length of PILOT pulse : 2523
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1323
Length of ONE bit pulse : 2473
Length of PILOT tone : 4099
Used bits in last byte : 8 OK
Pause After this block : 24ms
Data : 263 bytes
Total size : 282 bytes

Sum DATA : 2 575		000000: 2C 41 52 33 00 00 00 00 00 00 00 00 00 00 00 00 ,AR3............ 000010: 00 01 FF 02 CA 06 00 60 FF CA 06 00 00 00 00 00 .......`........ 000020: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000030: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000040: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000050: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000060: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000070: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000080: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000090: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000A0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000B0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000C0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000D0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000E0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000F0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000100: 00 72 AE FF FF FF FF .r.....
previousnext* BLOCK 0006 : TURBO LOADING DATA
DATA
Length of PILOT pulse : 2522
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1363
Length of ONE bit pulse : 2426
Length of PILOT tone : 4097
Used bits in last byte : 8 OK
Pause After this block : 13405ms
Data : 1811 bytes
Total size : 1830 bytes

Sum DATA : 95 429		000000: 16 41 52 33 00 00 00 00 00 00 00 00 19 C9 06 00 .AR3............ 000010: 42 65 67 69 6E 6E 69 6E 67 20 4D 75 6C 74 69 70 Beginning Multip 000020: 6C 69 63 61 74 69 6F 6E 20 00 00 00 00 00 00 00 lication ....... 000030: 00 39 00 20 20 20 20 20 20 20 20 20 20 20 20 20 .9. 000040: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000050: 20 20 20 20 20 32 20 78 20 35 20 3D 20 3F 1B 31 2 x 5 = ?.1 000060: 30 1B 31 35 1B 32 30 1B 35 1B 59 00 57 68 61 74 0.15.20.5.Y.What 000070: 20 69 73 20 74 68 65 20 6D 69 73 73 69 6E 67 20 is the missing 000080: 6E 75 6D 62 65 72 3F 20 20 20 20 20 20 20 20 20 number? 000090: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0000A0: 20 20 20 20 20 20 20 20 20 20 20 20 33 2C 20 36 3, 6 0000B0: 2C 20 39 2C 20 3F 1B 31 32 1B 31 30 1B 31 35 1B , 9, ?.12.10.15. 0000C0: 31 33 1B 27 00 4D 61 6B 65 20 33 20 66 69 76 65 13.'.Make 3 five 0000D0: 20 74 69 6D 65 73 20 62 69 67 67 65 72 2E 1B 31 times bigger..1 0000E0: 35 1B 31 32 1B 39 1B 31 38 1B 36 00 20 20 20 20 5.12.9.18.6. 0000F0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000100: 20 08 EF 20 20 20 20 20 20 20 20 20 20 20 20 20 .. 000110: 33 20 78 20 32 20 3D 20 3F 1B 36 1B 34 1B 39 1B 3 x 2 = ?.6.4.9. 000120: 38 1B 72 00 46 69 6C 6C 20 69 6E 20 74 68 65 20 8.r.Fill in the 000130: 6D 69 73 73 69 6E 67 20 6E 75 6D 62 65 72 73 20 missing numbers 000140: 69 6E 74 68 65 20 74 61 62 6C 65 20 6F 66 20 32 inthe table of 2 000150: 27 73 3A 20 20 20 20 20 20 20 20 20 20 20 20 20 's: 000160: 20 20 31 32 2C 20 31 34 2C 20 3F 2C 20 31 38 2C 12, 14, ?, 18, 000170: 20 3F 2E 1B 31 36 20 61 6E 64 20 32 30 1B 31 30 ?..16 and 20.10 000180: 20 61 6E 64 20 32 32 1B 31 34 20 61 6E 64 20 31 and 22.14 and 1 000190: 38 1B 20 1B 29 00 4D 61 6B 65 20 35 20 74 68 72 8. .).Make 5 thr 0001A0: 65 65 20 74 69 6D 65 73 20 62 69 67 67 65 72 2E ee times bigger. 0001B0: 1B 31 35 1B 31 30 1B 31 32 1B 31 38 1B 3A 00 20 .15.10.12.18.:. 0001C0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0001D0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0001E0: 20 37 20 78 20 33 20 3D 20 3F 1B 32 31 1B 31 34 7 x 3 = ?.21.14 0001F0: 1B 31 39 1B 32 33 1B 37 00 20 20 20 20 20 20 20 .19.23.7. 000200: 20 20 20 17 60 20 20 20 20 20 20 20 20 20 20 20 .` 000210: 20 20 20 20 20 20 20 20 20 20 20 20 20 34 20 78 4 x 000220: 20 32 20 3D 20 3F 1B 38 1B 31 30 1B 36 1B 37 1B 2 = ?.8.10.6.7. 000230: 7A 00 46 69 6C 6C 20 69 6E 20 74 68 65 20 6E 65 z.Fill in the ne 000240: 78 74 20 74 77 6F 20 6E 75 6D 62 65 72 73 20 20 xt two numbers 000250: 69 6E 20 74 68 65 20 74 61 62 6C 65 20 6F 66 20 in the table of 000260: 35 27 73 3A 20 20 20 20 20 20 20 20 20 20 20 20 5's: 000270: 20 35 2C 20 31 30 2C 20 31 35 2C 20 3F 2C 20 3F 5, 10, 15, ?, ? 000280: 2E 1B 32 30 20 61 6E 64 20 32 35 1B 32 31 20 61 ..20 and 25.21 a 000290: 6E 64 20 32 36 1B 33 30 20 61 6E 64 20 33 35 1B nd 26.30 and 35. 0002A0: 31 38 20 61 6E 64 20 32 33 1B 3A 00 20 20 20 20 18 and 23.:. 0002B0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0002C0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 35 20 5 0002D0: 78 20 35 20 3D 20 3F 1B 32 35 1B 33 30 1B 32 30 x 5 = ?.25.30.20 0002E0: 1B 32 36 1B 28 00 4D 61 6B 65 20 66 69 76 65 20 .26.(.Make five 0002F0: 36 20 74 69 6D 65 73 20 62 69 67 67 65 72 2E 1B 6 times bigger.. 000300: 33 30 1B 33 33 1E CE 1B 33 35 1B 34 30 1B 38 00 30.33...35.40.8. 000310: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000320: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000330: 20 20 33 20 78 20 33 20 3D 20 3F 1B 39 1B 31 32 3 x 3 = ?.9.12 000340: 1B 36 1B 31 35 1B 3A 00 20 20 20 20 20 20 20 20 .6.15.:. 000350: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000360: 20 20 20 20 20 20 20 20 20 20 39 20 78 20 35 20 9 x 5 000370: 3D 20 3F 1B 34 35 1B 33 36 1B 35 34 1B 35 30 1B = ?.45.36.54.50. 000380: 77 00 46 69 6C 6C 20 69 6E 20 74 68 65 20 6D 69 w.Fill in the mi 000390: 73 73 69 6E 67 20 6E 75 6D 62 65 72 73 20 69 6E ssing numbers in 0003A0: 74 68 65 20 74 61 62 6C 65 20 6F 66 20 32 27 73 the table of 2's 0003B0: 3A 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 : 0003C0: 20 36 2C 20 38 2C 20 3F 2C 20 3F 2C 20 31 34 1B 6, 8, ?, ?, 14. 0003D0: 31 30 20 61 6E 64 20 31 32 1B 39 20 61 6E 64 20 10 and 12.9 and 0003E0: 31 31 1B 31 31 20 61 6E 64 20 31 33 1B 31 36 20 11.11 and 13.16 0003F0: 61 6E 64 20 31 38 1B 27 00 4D 61 6B 65 20 33 20 and 18.'.Make 3 000400: 73 69 78 20 74 69 6D 2D F2 65 73 20 62 69 67 67 six tim-.es bigg 000410: 65 72 2E 1B 31 38 1B 31 35 1B 32 30 1B 32 31 1B er..18.15.20.21. 000420: 36 00 20 20 20 20 20 20 20 20 20 20 20 20 20 20 6. 000430: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000440: 20 20 20 20 32 20 78 20 33 20 3D 20 3F 1B 36 1B 2 x 3 = ?.6. 000450: 39 1B 38 1B 34 1B 7B 00 57 68 61 74 20 61 72 65 9.8.4.{.What are 000460: 20 74 68 65 20 6E 65 78 74 20 74 77 6F 20 6E 75 the next two nu 000470: 6D 62 65 72 73 20 69 6E 20 74 68 65 20 74 61 62 mbers in the tab 000480: 6C 65 20 6F 66 20 33 27 73 3F 20 20 20 20 20 20 le of 3's? 000490: 20 20 20 20 20 20 20 31 38 2C 20 32 31 2C 20 32 18, 21, 2 0004A0: 34 2C 20 3F 2C 20 3F 2E 1B 32 37 20 61 6E 64 20 4, ?, ?..27 and 0004B0: 33 30 1B 32 36 20 61 6E 64 20 32 39 1B 32 38 20 30.26 and 29.28 0004C0: 61 6E 64 20 33 31 1B 32 39 20 61 6E 64 20 33 32 and 31.29 and 32 0004D0: 1B 39 00 20 20 20 20 20 20 20 20 20 20 20 20 20 .9. 0004E0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0004F0: 20 20 20 20 20 34 20 78 20 33 20 3D 20 3F 1B 31 4 x 3 = ?.1 000500: 32 1B 31 33 1B 39 1B 31 35 84 25 1B 39 00 20 20 2.13.9.15.%.9. 000510: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000520: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 38 8 000530: 20 78 20 32 20 3D 20 3F 1B 31 36 1B 31 34 1B 31 x 2 = ?.16.14.1 000540: 38 1B 32 30 1B 5F 00 57 68 61 74 20 69 73 20 74 8.20._.What is t 000550: 68 65 20 6D 69 73 73 69 6E 67 20 6E 75 6D 62 65 he missing numbe 000560: 72 20 69 6E 20 74 68 65 20 74 61 62 6C 65 20 6F r in the table o 000570: 66 20 35 27 73 3F 20 20 20 20 20 20 20 20 20 20 f 5's? 000580: 20 20 20 20 20 20 33 30 2C 20 33 35 2C 20 34 30 30, 35, 40 000590: 2C 20 3F 2C 20 35 30 1B 34 35 1B 35 35 1B 34 32 , ?, 50.45.55.42 0005A0: 1B 34 38 1B 3A 00 20 20 20 20 20 20 20 20 20 20 .48.:. 0005B0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0005C0: 20 20 20 20 20 20 20 20 39 20 78 20 33 20 3D 20 9 x 3 = 0005D0: 3F 1B 32 37 1B 33 30 1B 32 34 1B 32 38 1B 3A 00 ?.27.30.24.28.:. 0005E0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0005F0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000600: 20 20 36 20 78 20 32 20 3D 20 3F 0F 9D 1B 31 32 6 x 2 = ?...12 000610: 1B 31 38 1B 31 34 1B 31 36 1B 29 00 4D 61 6B 65 .18.14.16.).Make 000620: 20 33 20 65 69 67 68 74 20 74 69 6D 65 73 20 62 3 eight times b 000630: 69 67 67 65 72 2E 1B 32 34 1B 32 31 1B 32 37 1B igger..24.21.27. 000640: 32 33 1B 59 00 57 68 61 74 20 69 73 20 74 68 65 23.Y.What is the 000650: 20 6D 69 73 73 69 6E 67 20 6E 75 6D 62 65 72 20 missing number 000660: 69 6E 20 74 68 65 20 74 61 62 6C 65 20 6F 66 20 in the table of 000670: 32 27 73 3F 20 20 20 20 20 20 20 20 20 20 20 20 2's? 000680: 20 20 20 20 20 32 2C 20 34 2C 20 3F 2C 20 38 2C 2, 4, ?, 8, 000690: 20 31 30 1B 36 1B 33 1B 39 1B 37 1B 3A 00 20 20 10.6.3.9.7.:. 0006A0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0006B0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0006C0: 39 20 78 20 32 20 3D 20 3F 1B 31 38 1B 31 36 1B 9 x 2 = ?.18.16. 0006D0: 31 39 1B 32 30 1B 1C 00 00 00 00 00 00 00 00 00 19.20........... 0006E0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0006F0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000700: 00 00 00 00 00 00 00 00 00 00 00 00 00 E9 E4 FF ................ 000710: FF FF FF ...
previousnext* BLOCK 0007 : TURBO LOADING DATA
HEADER
Block Name : AR4
Block Number : 1
Block first : YES
Block last : YES
File type : Binaire
File adress start : &6000
File adress length : &06E0
File adress execution : &0000
File length file : &06E0

Length of PILOT pulse : 2520
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1322
Length of ONE bit pulse : 2479
Length of PILOT tone : 4099
Used bits in last byte : 8 OK
Pause After this block : 23ms
Data : 263 bytes
Total size : 282 bytes

Sum DATA : 2 471		000000: 2C 41 52 34 00 00 00 00 00 00 00 00 00 00 00 00 ,AR4............ 000010: 00 01 FF 02 E0 06 00 60 FF E0 06 00 00 00 00 00 .......`........ 000020: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000030: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000040: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000050: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000060: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000070: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000080: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000090: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000A0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000B0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000C0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000D0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000E0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000F0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000100: 00 44 47 FF FF FF FF .DG....
previousnext* BLOCK 0008 : TURBO LOADING DATA
DATA
Length of PILOT pulse : 2519
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1375
Length of ONE bit pulse : 2429
Length of PILOT tone : 4099
Used bits in last byte : 8 OK
Pause After this block : 13447ms
Data : 1811 bytes
Total size : 1830 bytes

Sum DATA : 126 941		000000: 16 41 52 34 00 00 00 00 00 00 00 00 19 DF 06 00 .AR4............ 000010: 42 65 67 69 6E 6E 69 6E 67 20 44 69 76 69 73 69 Beginning Divisi 000020: 6F 6E 20 20 20 20 20 20 20 00 00 00 00 00 00 00 on ....... 000030: 00 42 00 20 20 20 20 20 20 20 20 20 20 20 20 20 .B. 000040: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000050: 20 38 20 64 69 76 69 64 65 64 20 62 79 20 32 20 8 divided by 2 000060: 65 71 75 61 6C 73 20 3F 1B 34 1B 31 36 1B 36 1B equals ?.4.16.6. 000070: 31 30 1B 25 00 31 35 20 64 69 76 69 64 65 64 20 10.%.15 divided 000080: 62 79 20 35 20 65 71 75 61 6C 73 20 3F 20 20 1B by 5 equals ? . 000090: 33 1B 34 1B 32 1B 35 1B 2C 00 48 6F 77 20 6D 61 3.4.2.5.,.How ma 0000A0: 6E 79 20 74 68 72 65 65 73 20 61 72 65 20 74 68 ny threes are th 0000B0: 65 72 65 20 69 6E 20 20 31 32 3F 1B 34 1B 33 1B ere in 12?.4.3. 0000C0: 35 1B 36 1B 5C 00 53 68 61 72 65 20 36 20 63 61 5.6.\.Share 6 ca 0000D0: 6B 65 73 20 65 71 75 61 6C 6C 79 20 62 65 74 77 kes equally betw 0000E0: 65 65 6E 20 33 20 63 68 69 6C 64 72 65 6E 2E 20 een 3 children. 0000F0: 20 48 6F 77 20 6D 61 6E 79 20 63 61 6B 65 73 20 How many cakes 000100: 20 BD E3 20 64 6F 65 73 20 65 61 63 68 20 63 68 .. does each ch 000110: 69 6C 64 20 68 61 76 65 3F 1B 32 1B 33 1B 34 1B ild have?.2.3.4. 000120: 36 1B 41 00 20 20 20 20 20 20 20 20 20 20 20 20 6.A. 000130: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000140: 20 20 31 36 20 64 69 76 69 64 65 64 20 62 79 20 16 divided by 000150: 32 20 65 71 75 61 6C 73 20 3F 1B 38 1B 39 1B 36 2 equals ?.8.9.6 000160: 1B 37 1B 24 00 31 30 20 64 69 76 69 64 65 64 20 .7.$.10 divided 000170: 62 79 20 32 20 65 71 75 61 6C 73 20 3F 20 1B 35 by 2 equals ? .5 000180: 1B 36 1B 34 1B 33 1B 32 00 48 6F 77 20 6D 61 6E .6.4.3.2.How man 000190: 79 20 74 77 6F 73 20 61 72 65 20 74 68 65 72 65 y twos are there 0001A0: 20 69 6E 20 20 20 20 66 6F 75 72 74 65 65 6E 3F in fourteen? 0001B0: 1B 37 1B 38 1B 36 1B 35 1B 5C 00 53 68 61 72 65 .7.8.6.5.\.Share 0001C0: 20 31 35 20 63 6F 6E 6B 65 72 73 20 65 71 75 61 15 conkers equa 0001D0: 6C 6C 79 20 20 20 20 20 20 62 65 74 77 65 65 6E lly between 0001E0: 20 35 20 63 68 69 6C 64 72 65 6E 2E 20 48 6F 77 5 children. How 0001F0: 20 6D 61 6E 79 20 20 64 6F 65 73 20 65 61 63 68 many does each 000200: 20 63 68 8F 6C 69 6C 64 20 68 61 76 65 3F 1B 33 ch.lild have?.3 000210: 1B 34 1B 35 1B 32 1B 41 00 20 20 20 20 20 20 20 .4.5.2.A. 000220: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000230: 20 20 20 20 20 20 20 32 31 20 64 69 76 69 64 65 21 divide 000240: 64 20 62 79 20 33 20 65 71 75 61 6C 73 20 3F 1B d by 3 equals ?. 000250: 37 1B 36 1B 38 1B 39 1B 40 00 20 20 20 20 20 20 7.6.8.9.@. 000260: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000270: 20 20 20 20 20 20 20 20 39 20 64 69 76 69 64 65 9 divide 000280: 64 20 62 79 20 33 20 65 71 75 61 6C 73 20 3F 1B d by 3 equals ?. 000290: 33 1B 34 1B 32 1B 35 1B 30 00 48 6F 77 20 6D 61 3.4.2.5.0.How ma 0002A0: 6E 79 20 66 69 76 65 73 20 61 72 65 20 74 68 65 ny fives are the 0002B0: 72 65 20 69 6E 20 20 20 74 77 65 6E 74 79 3F 1B re in twenty?. 0002C0: 34 1B 35 1B 33 1B 36 1B 5C 00 53 68 61 72 65 20 4.5.3.6.\.Share 0002D0: 36 20 70 65 6E 63 69 6C 73 20 65 71 75 61 6C 6C 6 pencils equall 0002E0: 79 20 20 20 20 20 20 20 62 65 74 77 65 65 6E 20 y between 0002F0: 32 20 63 68 69 6C 64 72 65 6E 2E 20 48 6F 77 20 2 children. How 000300: 6D 61 6E 79 20 6F 38 20 64 6F 65 73 20 65 61 63 many o8 does eac 000310: 68 20 63 68 69 6C 64 20 68 61 76 65 3F 1B 33 1B h child have?.3. 000320: 34 1B 32 1B 36 1B 41 00 20 20 20 20 20 20 20 20 4.2.6.A. 000330: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000340: 20 20 20 20 20 20 32 35 20 64 69 76 69 64 65 64 25 divided 000350: 20 62 79 20 35 20 65 71 75 61 6C 73 20 3F 1B 35 by 5 equals ?.5 000360: 1B 36 1B 34 1B 37 1B 32 00 48 6F 77 20 6D 61 6E .6.4.7.2.How man 000370: 79 20 74 68 72 65 65 73 20 61 72 65 20 74 68 65 y threes are the 000380: 72 65 20 69 6E 20 20 65 69 67 68 74 65 65 6E 3F re in eighteen? 000390: 1B 36 1B 35 1B 37 1B 34 1B 24 00 32 35 20 64 69 .6.5.7.4.$.25 di 0003A0: 76 69 64 65 64 20 62 79 20 35 20 65 71 75 61 6C vided by 5 equal 0003B0: 73 20 3F 20 1B 35 1B 36 1B 34 1B 37 1B 5C 00 53 s ? .5.6.4.7.\.S 0003C0: 68 61 72 65 20 31 36 20 6D 61 72 62 6C 65 73 20 hare 16 marbles 0003D0: 65 71 75 61 6C 6C 79 20 20 20 20 20 20 62 65 74 equally bet 0003E0: 77 65 65 6E 20 34 20 63 68 69 6C 64 72 65 6E 2E ween 4 children. 0003F0: 20 48 6F 77 20 6D 61 6E 79 20 20 64 6F 65 73 20 How many does 000400: 65 61 63 68 20 63 68 C6 C0 69 6C 64 20 68 61 76 each ch..ild hav 000410: 65 3F 1B 34 1B 35 1B 36 1B 33 1B 40 00 20 20 20 e?.4.5.6.3.@. 000420: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000430: 20 20 20 20 20 20 20 20 20 20 20 32 20 64 69 76 2 div 000440: 69 64 65 64 20 62 79 20 32 20 65 71 75 61 6C 73 ided by 2 equals 000450: 20 3F 1B 31 1B 32 1B 34 1B 20 1B 26 00 31 36 20 ?.1.2.4. .&.16 000460: 64 69 76 69 64 65 64 20 62 79 20 32 20 65 71 75 divided by 2 equ 000470: 61 6C 73 20 3F 20 20 20 1B 38 1B 39 1B 37 1B 36 als ? .8.9.7.6 000480: 1B 31 00 48 6F 77 20 6D 61 6E 79 20 74 77 6F 73 .1.How many twos 000490: 20 61 72 65 20 74 68 65 72 65 20 69 6E 20 20 20 are there in 0004A0: 20 74 77 65 6E 74 79 3F 1B 31 30 1B 38 1B 37 1B twenty?.10.8.7. 0004B0: 39 1B 5C 00 53 68 61 72 65 20 33 30 20 70 65 6E 9.\.Share 30 pen 0004C0: 6E 69 65 73 20 65 71 75 61 6C 6C 79 20 20 20 20 nies equally 0004D0: 20 20 62 65 74 77 65 65 6E 20 35 20 63 68 69 6C between 5 chil 0004E0: 64 72 65 6E 2E 20 48 6F 77 20 6D 61 6E 79 20 20 dren. How many 0004F0: 64 6F 65 73 20 65 61 63 68 20 63 68 69 6C 64 20 does each child 000500: 68 61 76 65 3F 1B 36 1B 37 6D 04 1B 38 1B 35 1B have?.6.7m..8.5. 000510: 35 00 48 6F 77 20 6D 61 6E 79 20 74 68 72 65 65 5.How many three 000520: 73 20 61 72 65 20 74 68 65 72 65 20 69 6E 20 20 s are there in 000530: 74 77 65 6E 74 79 20 66 6F 75 72 3F 1B 38 1B 39 twenty four?.8.9 000540: 1B 37 1B 36 1B 70 00 31 39 20 64 69 76 69 64 65 .7.6.p.19 divide 000550: 64 20 62 79 20 35 20 20 20 20 20 20 20 20 20 20 d by 5 000560: 20 20 20 20 20 20 20 20 20 20 20 20 20 3D 20 3F = ? 000570: 20 72 65 6D 61 69 6E 64 65 72 20 3F 1B 33 20 72 remainder ?.3 r 000580: 65 6D 61 69 6E 64 65 72 20 34 1B 34 20 72 65 6D emainder 4.4 rem 000590: 61 69 6E 64 65 72 20 31 1B 33 20 72 65 6D 61 69 ainder 1.3 remai 0005A0: 6E 64 65 72 20 32 1B 34 20 72 65 6D 61 69 6E 64 nder 2.4 remaind 0005B0: 65 72 20 33 1B 6D 00 31 37 20 64 69 76 69 64 65 er 3.m.17 divide 0005C0: 64 20 62 79 20 33 20 65 71 75 61 6C 73 20 20 20 d by 3 equals 0005D0: 20 20 20 20 20 20 20 20 20 20 20 20 3F 20 72 65 ? re 0005E0: 6D 61 69 6E 64 65 72 20 3F 1B 35 20 72 65 6D 61 mainder ?.5 rema 0005F0: 69 6E 64 65 72 20 32 1B 36 20 72 65 6D 61 69 6E inder 2.6 remain 000600: 64 65 72 20 31 1B 35 20 72 65 6D 46 0F 61 69 6E der 1.5 remF.ain 000610: 64 65 72 20 31 1B 34 20 72 65 6D 61 69 6E 64 65 der 1.4 remainde 000620: 72 20 31 1B 6C 00 31 33 20 64 69 76 69 64 65 64 r 1.l.13 divided 000630: 20 62 79 20 35 20 65 71 75 61 6C 73 20 20 20 20 by 5 equals 000640: 20 20 20 20 20 20 20 20 20 20 3F 20 72 65 6D 61 ? rema 000650: 69 6E 64 65 72 20 3F 1B 32 20 72 65 6D 61 69 6E inder ?.2 remain 000660: 64 65 72 20 33 1B 33 20 72 65 6D 61 69 6E 64 65 der 3.3 remainde 000670: 72 20 32 1B 32 20 72 65 6D 61 69 6E 64 65 72 20 r 2.2 remainder 000680: 34 1B 33 20 72 65 6D 61 69 6E 64 65 72 20 31 1B 4.3 remainder 1. 000690: 5C 00 53 68 61 72 65 20 31 38 20 74 6F 79 20 73 \.Share 18 toy s 0006A0: 6F 6C 64 69 65 72 73 20 65 71 75 61 6C 6C 79 20 oldiers equally 0006B0: 62 65 74 77 65 65 6E 20 33 20 63 68 69 6C 64 72 between 3 childr 0006C0: 65 6E 2E 20 48 6F 77 20 6D 61 6E 79 20 20 64 6F en. How many do 0006D0: 65 73 20 65 61 63 68 20 63 68 69 6C 64 20 68 61 es each child ha 0006E0: 76 65 3F 1B 36 1B 35 1B 37 1B 38 1B 1C 00 00 00 ve?.6.5.7.8..... 0006F0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000700: 00 00 00 00 00 00 00 00 00 00 00 00 00 94 CE FF ................ 000710: FF FF FF ...
previousnext* BLOCK 0009 : TURBO LOADING DATA
HEADER
Block Name : AR5
Block Number : 1
Block first : YES
File type : Binaire
File adress start : &6000
File adress length : &0800
File adress execution : &0000
File length file : &08FC

Length of PILOT pulse : 2518
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1320
Length of ONE bit pulse : 2470
Length of PILOT tone : 4099
Used bits in last byte : 8 OK
Pause After this block : 22ms
Data : 263 bytes
Total size : 282 bytes

Sum DATA : 2 071		000000: 2C 41 52 35 00 00 00 00 00 00 00 00 00 00 00 00 ,AR5............ 000010: 00 01 00 02 00 08 00 60 FF FC 08 00 00 00 00 00 .......`........ 000020: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000030: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000040: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000050: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000060: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000070: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000080: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000090: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000A0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000B0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000C0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000D0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000E0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000F0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000100: 00 99 20 FF FF FF FF .. ....
previousnext* BLOCK 0010 : TURBO LOADING DATA
DATA
Length of PILOT pulse : 2518
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1377
Length of ONE bit pulse : 2432
Length of PILOT tone : 4099
Used bits in last byte : 8 OK
Pause After this block : 2710ms
Data : 2069 bytes
Total size : 2088 bytes

Sum DATA : 150 247		000000: 16 41 52 35 00 00 00 00 00 00 00 00 19 FB 08 00 .AR5............ 000010: 4C 75 63 6B 79 20 44 69 70 20 20 20 20 20 20 20 Lucky Dip 000020: 20 20 20 20 20 20 20 20 20 00 00 00 00 00 00 00 ....... 000030: 00 35 00 48 6F 77 20 69 73 20 74 77 65 6E 74 79 .5.How is twenty 000040: 2D 74 77 6F 20 77 72 69 74 74 65 6E 20 69 6E 20 -two written in 000050: 20 6E 75 6D 62 65 72 73 3F 1B 32 32 1B 31 32 1B numbers?.22.12. 000060: 33 32 1B 32 30 1B 30 00 48 6F 77 20 6D 61 6E 79 32.20.0.How many 000070: 20 64 61 79 73 20 61 72 65 20 74 68 65 72 65 20 days are there 000080: 69 6E 20 61 20 20 77 65 65 6B 3F 1B 37 1B 31 34 in a week?.7.14 000090: 1B 36 1B 31 30 1B 5A 00 48 6F 77 20 6D 61 6E 79 .6.10.Z.How many 0000A0: 20 74 65 6E 73 20 6F 72 20 75 6E 69 74 73 20 69 tens or units i 0000B0: 73 20 74 68 65 20 38 20 77 6F 72 74 68 20 69 6E s the 8 worth in 0000C0: 20 74 68 65 20 6E 75 6D 62 65 72 20 31 38 3F 1B the number 18?. 0000D0: 38 20 75 6E 69 74 73 1B 38 20 74 65 6E 73 1B 31 8 units.8 tens.1 0000E0: 38 20 74 65 6E 73 1B 31 38 20 75 6E 69 74 73 1B 8 tens.18 units. 0000F0: 27 00 57 68 61 74 20 6E 75 6D 62 65 72 20 63 6F '.What number co 000100: 6D E5 43 65 73 20 62 65 66 6F 72 65 20 39 3F 1B m.Ces before 9?. 000110: 38 1B 37 1B 31 30 1B 36 1B 77 00 50 75 74 20 69 8.7.10.6.w.Put i 000120: 6E 20 74 68 65 20 63 6F 72 72 65 63 74 20 73 79 n the correct sy 000130: 6D 62 6F 6C 20 20 20 20 20 28 3C 20 6F 72 20 3E mbol (< or > 000140: 29 20 69 6E 20 74 68 69 73 20 6E 75 6D 62 65 72 ) in this number 000150: 20 20 20 20 20 20 20 73 65 6E 74 65 6E 63 65 3A sentence: 000160: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000170: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000180: 31 34 20 3F 20 31 33 1B 3E 1B 3C 1B 20 1B 20 1B 14 ? 13.>.<. . . 000190: 6B 00 48 6F 77 20 6D 61 6E 79 20 74 65 6E 73 20 k.How many tens 0001A0: 61 6E 64 20 75 6E 69 74 73 20 69 73 20 20 20 20 and units is 0001B0: 74 68 65 20 6E 75 6D 62 65 72 20 32 36 20 77 6F the number 26 wo 0001C0: 72 74 68 3F 1B 32 20 74 65 6E 73 20 61 6E 64 20 rth?.2 tens and 0001D0: 36 20 75 6E 69 74 73 1B 36 20 74 65 6E 73 20 61 6 units.6 tens a 0001E0: 6E 64 20 32 20 75 6E 69 74 73 1B 32 36 20 74 65 nd 2 units.26 te 0001F0: 6E 73 1B 38 20 75 6E 69 74 73 1B 7C 00 49 6E 20 ns.8 units.|.In 000200: 74 68 65 99 C9 20 66 6F 6C 6C 6F 77 69 6E 67 20 the.. following 000210: 6C 69 73 74 20 6F 66 20 65 76 65 6E 20 6E 75 6D list of even num 000220: 62 65 72 73 20 6F 6E 65 20 6E 75 6D 62 65 72 20 bers one number 000230: 69 73 20 6F 64 64 2E 20 20 20 20 57 68 69 63 68 is odd. Which 000240: 20 6F 6E 65 3F 20 20 20 20 20 20 20 20 20 20 20 one? 000250: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000260: 20 20 20 32 2C 20 34 2C 20 36 2C 20 38 2C 20 39 2, 4, 6, 8, 9 000270: 1B 39 1B 34 1B 38 1B 36 1B 77 00 49 6E 20 74 68 .9.4.8.6.w.In th 000280: 65 20 66 6F 6C 6C 6F 77 69 6E 67 20 6C 69 73 74 e following list 000290: 20 6F 66 20 6F 64 64 20 20 6E 75 6D 62 65 72 73 of odd numbers 0002A0: 20 6F 6E 65 20 69 73 20 65 76 65 6E 2E 20 57 68 one is even. Wh 0002B0: 69 63 68 20 20 20 20 6F 6E 65 3F 20 20 20 20 20 ich one? 0002C0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0002D0: 20 20 20 20 20 20 20 20 20 20 31 2C 20 33 2C 20 1, 3, 0002E0: 35 2C 20 36 2C 20 39 1B 36 1B 33 1B 39 1B 31 1B 5, 6, 9.6.3.9.1. 0002F0: 34 00 48 6F 77 20 69 73 20 73 69 78 74 65 65 6E 4.How is sixteen 000300: 20 77 72 69 74 C8 E8 74 65 6E 20 69 6E 20 20 20 writ..ten in 000310: 20 20 6E 75 6D 62 65 72 73 3F 1B 31 36 1B 36 31 numbers?.16.61 000320: 1B 36 1B 32 36 1B 35 00 48 6F 77 20 6D 61 6E 79 .6.26.5.How many 000330: 20 6D 69 6E 75 74 65 73 20 61 72 65 20 74 68 65 minutes are the 000340: 72 65 20 69 6E 20 61 6E 20 68 6F 75 72 3F 1B 36 re in an hour?.6 000350: 30 1B 33 30 1B 32 34 1B 31 32 1B 5A 00 48 6F 77 0.30.24.12.Z.How 000360: 20 6D 61 6E 79 20 74 65 6E 73 20 6F 72 20 75 6E many tens or un 000370: 69 74 73 20 69 73 20 74 68 65 20 32 20 77 6F 72 its is the 2 wor 000380: 74 68 20 69 6E 20 74 68 65 20 6E 75 6D 62 65 72 th in the number 000390: 20 32 38 3F 1B 32 20 74 65 6E 73 1B 32 20 75 6E 28?.2 tens.2 un 0003A0: 69 74 73 1B 32 30 20 74 65 6E 73 1B 32 30 20 75 its.20 tens.20 u 0003B0: 6E 69 74 73 1B 2A 00 57 68 61 74 20 6E 75 6D 62 nits.*.What numb 0003C0: 65 72 20 63 6F 6D 65 73 20 62 65 66 6F 72 65 20 er comes before 0003D0: 32 30 3F 1B 31 39 1B 31 35 1B 32 39 1B 39 1B 7D 20?.19.15.29.9.} 0003E0: 00 57 68 61 74 20 69 73 20 74 68 65 20 63 6F 72 .What is the cor 0003F0: 72 65 63 74 20 73 79 6D 62 6F 6C 20 20 20 20 28 rect symbol ( 000400: 3E 20 6F 72 20 3C 29 DA 87 20 74 6F 20 63 6F 6D > or <).. to com 000410: 70 6C 65 74 65 20 74 68 69 73 20 20 20 20 20 6E plete this n 000420: 75 6D 62 65 72 20 73 65 6E 74 65 6E 63 65 3A 20 umber sentence: 000430: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000440: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 39 9 000450: 20 3F 20 31 30 1B 3C 1B 3E 1B 20 1B 20 1B 56 00 ? 10.<.>. . .V. 000460: 48 6F 77 20 6D 61 6E 79 20 6D 69 6E 75 74 65 73 How many minutes 000470: 20 61 72 65 20 74 68 65 72 65 20 20 20 20 62 65 are there be 000480: 74 77 65 65 6E 20 31 31 2E 30 30 20 61 2E 6D 2E tween 11.00 a.m. 000490: 20 61 6E 64 20 20 20 20 20 20 20 20 31 32 2E 30 and 12.0 0004A0: 30 20 6E 6F 6F 6E 3F 1B 36 30 1B 33 30 1B 31 1B 0 noon?.60.30.1. 0004B0: 31 32 30 1B 85 00 49 6E 20 74 68 65 20 66 6F 6C 120...In the fol 0004C0: 6C 6F 77 69 6E 67 20 6C 69 73 74 20 6F 66 20 65 lowing list of e 0004D0: 76 65 6E 20 6E 75 6D 62 65 72 73 20 6F 6E 65 20 ven numbers one 0004E0: 6E 75 6D 62 65 72 20 69 73 20 6F 64 64 2E 20 20 number is odd. 0004F0: 20 20 57 68 69 63 68 20 6F 6E 65 3F 20 20 20 20 Which one? 000500: 20 20 20 20 20 20 20 20 20 92 BC 20 20 20 20 20 .. 000510: 20 20 20 20 20 20 20 20 20 20 20 20 31 32 2C 20 12, 000520: 31 33 2C 20 31 34 2C 20 31 36 2C 20 31 38 1B 31 13, 14, 16, 18.1 000530: 33 1B 31 36 1B 31 38 1B 31 32 1B 7D 00 57 68 61 3.16.18.12.}.Wha 000540: 74 20 69 73 20 74 68 65 20 63 6F 72 72 65 63 74 t is the correct 000550: 20 73 79 6D 62 6F 6C 20 20 20 20 28 3C 20 6F 72 symbol (< or 000560: 20 3E 29 20 74 6F 20 63 6F 6D 70 6C 65 74 65 20 >) to complete 000570: 74 68 69 73 20 20 20 20 20 6E 75 6D 62 65 72 20 this number 000580: 73 65 6E 74 65 6E 63 65 3A 20 20 20 20 20 20 20 sentence: 000590: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0005A0: 20 20 20 20 20 20 20 20 32 30 20 3F 20 31 30 1B 20 ? 10. 0005B0: 3E 1B 3C 1B 20 1B 20 1B 85 00 49 6E 20 74 68 65 >.<. . ...In the 0005C0: 20 66 6F 6C 6C 6F 77 69 6E 67 20 6C 69 73 74 20 following list 0005D0: 6F 66 20 6F 64 64 20 20 6E 75 6D 62 65 72 73 2C of odd numbers, 0005E0: 20 6F 6E 65 20 6E 75 6D 62 65 72 20 69 73 20 65 one number is e 0005F0: 76 65 6E 2E 20 20 57 68 69 63 68 20 6F 6E 65 3F ven. Which one? 000600: 20 20 20 20 20 20 20 20 20 20 20 37 A2 20 20 20 7. 000610: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000620: 31 35 2C 20 31 37 2C 20 31 38 2C 20 31 39 2C 20 15, 17, 18, 19, 000630: 32 31 1B 31 38 1B 32 31 1B 31 35 1B 31 37 1B 66 21.18.21.15.17.f 000640: 00 48 6F 77 20 6D 61 6E 79 20 74 65 6E 73 20 61 .How many tens a 000650: 6E 64 20 75 6E 69 74 73 20 69 73 20 74 68 65 6E nd units is then 000660: 75 6D 62 65 72 20 31 33 20 77 6F 72 74 68 3F 1B umber 13 worth?. 000670: 31 20 74 65 6E 20 61 6E 64 20 33 20 75 6E 69 74 1 ten and 3 unit 000680: 73 1B 33 20 74 65 6E 73 20 61 6E 64 20 31 20 75 s.3 tens and 1 u 000690: 6E 69 74 1B 31 33 20 75 6E 69 74 73 1B 31 33 20 nit.13 units.13 0006A0: 74 65 6E 73 1B 34 00 48 6F 77 20 69 73 20 65 6C tens.4.How is el 0006B0: 65 76 65 6E 20 77 72 69 74 74 65 6E 20 69 6E 20 even written in 0006C0: 20 20 20 20 20 6E 75 6D 62 65 72 73 3F 1B 31 31 numbers?.11 0006D0: 1B 31 1B 32 31 1B 31 37 1B 36 00 48 6F 77 20 6D .1.21.17.6.How m 0006E0: 61 6E 79 20 73 65 63 6F 6E 64 73 20 61 72 65 20 any seconds are 0006F0: 74 68 65 72 65 20 69 6E 20 61 20 6D 69 6E 75 74 there in a minut 000700: 65 3F 1B 36 30 1B 32 34 1B 33 30 1B 37 DD CC 32 e?.60.24.30.7..2 000710: 1B 58 00 48 6F 77 20 6D 61 6E 79 20 74 65 6E 73 .X.How many tens 000720: 20 6F 72 20 75 6E 69 74 73 20 69 73 20 74 68 65 or units is the 000730: 20 31 20 77 6F 72 74 68 20 69 6E 20 74 68 65 20 1 worth in the 000740: 6E 75 6D 62 65 72 20 31 36 3F 1B 31 20 74 65 6E number 16?.1 ten 000750: 1B 31 20 75 6E 69 74 1B 31 30 20 75 6E 69 74 73 .1 unit.10 units 000760: 1B 31 30 20 74 65 6E 73 1B 7D 00 57 68 61 74 20 .10 tens.}.What 000770: 69 73 20 74 68 65 20 63 6F 72 72 65 63 74 20 73 is the correct s 000780: 79 6D 62 6F 6C 20 20 20 20 28 3C 20 6F 72 20 3E ymbol (< or > 000790: 29 20 74 6F 20 63 6F 6D 70 6C 65 74 65 20 74 68 ) to complete th 0007A0: 69 73 20 20 20 20 20 6E 75 6D 62 65 72 20 73 65 is number se 0007B0: 6E 74 65 6E 63 65 3F 20 20 20 20 20 20 20 20 20 ntence? 0007C0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0007D0: 20 20 20 20 20 20 31 38 20 3F 20 32 30 1B 3C 1B 18 ? 20.<. 0007E0: 3E 1B 20 1B 20 1B 7C 00 48 6F 77 20 6D 61 6E 79 >. . .|.How many 0007F0: 20 74 65 6E 73 20 6F 72 20 75 6E 69 74 73 20 69 tens or units i 000800: 73 20 74 68 65 20 6E 75 6D 62 65 72 20 31 37 5B s the number 17[ 000810: EC FF FF FF FF .....
previousnext* BLOCK 0011 : TURBO LOADING DATA
HEADER
Block Name : AR5
Block Number : 2
Block last : YES
File type : Binaire
File adress start : &6800
File adress length : &00FC
File adress execution : &0000
File length file : &08FC

Length of PILOT pulse : 2521
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1322
Length of ONE bit pulse : 2469
Length of PILOT tone : 4099
Used bits in last byte : 8 OK
Pause After this block : 23ms
Data : 263 bytes
Total size : 282 bytes

Sum DATA : 2 480		000000: 2C 41 52 35 00 00 00 00 00 00 00 00 00 00 00 00 ,AR5............ 000010: 00 02 FF 02 FC 00 00 68 00 FC 08 00 00 00 00 00 .......h........ 000020: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000030: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000040: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000050: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000060: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000070: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000080: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000090: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000A0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000B0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000C0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000D0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000E0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000F0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000100: 00 82 D3 FF FF FF FF .......
previousnext* BLOCK 0012 : TURBO LOADING DATA
DATA
Length of PILOT pulse : 2523
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1381
Length of ONE bit pulse : 2434
Length of PILOT tone : 4099
Used bits in last byte : 8 OK
Pause After this block : 13518ms
Data : 263 bytes
Total size : 282 bytes

Sum DATA : 19 260		000000: 16 20 77 6F 72 74 68 3F 1B 31 20 74 65 6E 20 61 . worth?.1 ten a 000010: 6E 64 20 37 20 75 6E 69 74 73 1B 37 20 74 65 6E nd 7 units.7 ten 000020: 73 20 61 6E 64 20 31 20 75 6E 69 74 1B 31 30 20 s and 1 unit.10 000030: 74 65 6E 73 20 61 6E 64 20 37 20 75 6E 69 74 73 tens and 7 units 000040: 1B 31 20 74 65 6E 20 61 6E 64 20 31 37 20 75 6E .1 ten and 17 un 000050: 69 74 73 1B 2B 00 57 68 61 74 20 6E 75 6D 62 65 its.+.What numbe 000060: 72 20 63 6F 6D 65 73 20 62 65 66 6F 72 65 20 31 r comes before 1 000070: 35 3F 1B 31 34 1B 31 36 1B 31 30 1B 31 32 1B 7D 5?.14.16.10.12.} 000080: 00 57 68 61 74 20 69 73 20 74 68 65 20 63 6F 72 .What is the cor 000090: 72 65 63 74 20 73 79 6D 62 6F 6C 20 20 20 20 28 rect symbol ( 0000A0: 3C 20 6F 72 20 3E 29 20 74 6F 20 63 6F 6D 70 6C < or >) to compl 0000B0: 65 74 65 20 74 68 69 73 20 20 20 20 20 6E 75 6D ete this num 0000C0: 62 65 72 20 73 65 6E 74 65 6E 63 65 3F 20 20 20 ber sentence? 0000D0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0000E0: 20 20 20 20 20 20 20 20 20 20 20 20 32 35 20 3F 25 ? 0000F0: 20 32 36 1B 3C 1B 3E 1B 20 1B 20 1B 1C 00 00 00 26.<.>. . ..... 000100: 00 53 29 FF FF FF FF .S)....
previousnext* BLOCK 0013 : TURBO LOADING DATA
HEADER
Block Name : AR6
Block Number : 1
Block first : YES
Block last : YES
File type : Binaire
File adress start : &6000
File adress length : &07B3
File adress execution : &0000
File length file : &07B3

Length of PILOT pulse : 2523
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1323
Length of ONE bit pulse : 2475
Length of PILOT tone : 4099
Used bits in last byte : 8 OK
Pause After this block : 23ms
Data : 263 bytes
Total size : 282 bytes

Sum DATA : 2 529		000000: 2C 41 52 36 00 00 00 00 00 00 00 00 00 00 00 00 ,AR6............ 000010: 00 01 FF 02 B3 07 00 60 FF B3 07 00 00 00 00 00 .......`........ 000020: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000030: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000040: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000050: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000060: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000070: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000080: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000090: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000A0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000B0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000C0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000D0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000E0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000F0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000100: 00 F5 26 FF FF FF FF ..&....
previousnext* BLOCK 0014 : TURBO LOADING DATA
DATA
Length of PILOT pulse : 2521
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1364
Length of ONE bit pulse : 2428
Length of PILOT tone : 4099
Used bits in last byte : 8 OK
Pause After this block : 13463ms
Data : 2069 bytes
Total size : 2088 bytes

Sum DATA : 113 210		000000: 16 41 52 36 00 00 00 00 00 00 00 00 19 B2 07 00 .AR6............ 000010: 41 64 64 69 74 69 6F 6E 20 2D 20 54 55 20 20 20 Addition - TU 000020: 20 20 20 20 20 20 20 20 20 00 00 00 00 00 00 00 ....... 000030: 00 37 00 20 20 20 20 20 20 20 20 20 20 20 20 20 .7. 000040: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000050: 20 31 30 20 2B 20 37 20 3D 20 3F 1B 31 37 1B 31 10 + 7 = ?.17.1 000060: 35 1B 31 36 1B 31 38 1B 67 00 57 68 61 74 20 61 5.16.18.g.What a 000070: 72 65 20 74 68 65 20 6D 69 73 73 69 6E 67 20 6E re the missing n 000080: 75 6D 62 65 72 73 3F 20 20 20 20 20 20 20 20 20 umbers? 000090: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0000A0: 20 20 20 20 20 20 20 20 20 37 20 2B 20 3F 20 3D 7 + ? = 0000B0: 20 31 34 20 3D 20 3F 20 2B 20 37 20 20 20 1B 37 14 = ? + 7 .7 0000C0: 2C 37 1B 38 2C 38 1B 35 2C 35 1B 36 2C 36 1B 44 ,7.8,8.5,5.6,6.D 0000D0: 00 57 68 61 74 20 69 73 20 74 68 65 20 6D 69 73 .What is the mis 0000E0: 73 69 6E 67 20 6E 75 6D 62 65 72 3F 20 20 20 20 sing number? 0000F0: 20 39 20 2B 20 38 20 3D 20 3F 20 3D 20 38 20 2B 9 + 8 = ? = 8 + 000100: 20 C8 84 39 20 20 20 20 1B 31 37 1B 31 35 1B 31 ..9 .17.15.1 000110: 36 1B 31 38 1B 5A 00 46 69 6E 64 20 74 68 65 20 6.18.Z.Find the 000120: 6D 69 73 73 69 6E 67 20 6E 75 6D 62 65 72 3A 20 missing number: 000130: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000140: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000150: 20 20 20 20 20 20 20 3F 20 2B 20 36 20 3D 20 39 ? + 6 = 9 000160: 20 20 20 20 20 20 1B 33 1B 34 1B 35 1B 32 1B 76 .3.4.5.2.v 000170: 00 46 69 6C 6C 20 69 6E 20 74 68 65 20 6E 65 78 .Fill in the nex 000180: 74 20 6E 75 6D 62 65 72 73 20 69 6E 20 20 20 74 t numbers in t 000190: 68 69 73 20 73 65 71 75 65 6E 63 65 3A 20 20 20 his sequence: 0001A0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 32 2 0001B0: 2C 20 35 2C 20 38 2C 20 3F 2C 20 3F 1B 31 31 20 , 5, 8, ?, ?.11 0001C0: 61 6E 64 20 31 34 1B 31 30 20 61 6E 64 20 31 33 and 14.10 and 13 0001D0: 1B 31 32 20 61 6E 64 20 31 35 1B 31 30 20 61 6E .12 and 15.10 an 0001E0: 64 20 31 32 1B 37 00 20 20 20 20 20 20 20 20 20 d 12.7. 0001F0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000200: 20 20 20 B4 CE 20 20 36 30 20 2B 20 36 20 3D 20 .. 60 + 6 = 000210: 3F 1B 36 36 1B 36 33 1B 36 38 1B 36 35 1B 2B 00 ?.66.63.68.65.+. 000220: 53 69 78 20 74 65 6E 73 20 70 6C 75 73 20 74 68 Six tens plus th 000230: 72 65 65 20 75 6E 69 74 73 20 3D 20 3F 1B 36 33 ree units = ?.63 000240: 1B 39 1B 33 36 1B 36 39 1B 57 00 50 6C 61 63 65 .9.36.69.W.Place 000250: 20 74 68 65 20 63 6F 72 72 65 63 74 20 73 69 67 the correct sig 000260: 6E 20 28 3C 2C 20 3E 2E 20 6F 72 20 3D 29 20 69 n (<, >. or =) i 000270: 6E 20 74 68 69 73 20 6E 75 6D 62 65 72 20 73 65 n this number se 000280: 6E 74 65 6E 63 65 3A 20 20 20 34 20 2B 20 35 20 ntence: 4 + 5 000290: 3F 20 37 20 2B 20 32 1B 3D 1B 3C 1B 3E 1B 20 1B ? 7 + 2.=.<.>. . 0002A0: 42 00 20 20 20 20 20 20 20 20 20 20 20 20 20 20 B. 0002B0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0002C0: 20 20 20 31 38 70 20 2B 20 31 31 70 20 3D 20 3F 18p + 11p = ? 0002D0: 70 1B 32 39 70 1B 32 37 70 1B 32 38 70 1B 33 30 p.29p.27p.28p.30 0002E0: 70 1B 2C 00 35 30 70 20 2B 20 31 34 70 20 2B 20 p.,.50p + 14p + 0002F0: 33 70 20 2B 20 31 70 20 3D 20 3F 70 20 1B 36 38 3p + 1p = ?p .68 000300: 70 1B 36 36 70 98 0D 1B 36 37 70 1B 37 30 70 1B p.66p...67p.70p. 000310: 61 00 57 68 61 74 20 69 73 20 74 68 65 20 6D 69 a.What is the mi 000320: 73 73 69 6E 67 20 6E 75 6D 62 65 72 3F 20 20 20 ssing number? 000330: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000340: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000350: 20 20 20 35 33 20 2B 20 3F 20 3D 20 38 37 20 20 53 + ? = 87 000360: 20 20 20 20 1B 33 34 1B 33 36 1B 33 32 1B 33 31 .34.36.32.31 000370: 1B 40 00 46 69 6C 6C 20 69 6E 20 74 68 65 20 6D .@.Fill in the m 000380: 69 73 73 69 6E 67 20 6E 75 6D 62 65 72 3A 20 20 issing number: 000390: 20 20 20 31 30 2C 20 32 30 2C 20 33 30 2C 20 3F 10, 20, 30, ? 0003A0: 2C 20 35 30 1B 34 30 1B 34 35 1B 36 30 1B 37 30 , 50.40.45.60.70 0003B0: 1B 41 00 20 20 20 20 20 20 20 20 20 20 20 20 20 .A. 0003C0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0003D0: 20 31 33 20 2B 20 34 31 20 2B 20 32 33 20 2B 20 13 + 41 + 23 + 0003E0: 32 20 3D 20 3F 1B 37 39 1B 37 34 1B 37 35 1B 37 2 = ?.79.74.75.7 0003F0: 31 1B 88 00 49 20 62 75 79 20 61 20 70 65 6E 20 1...I buy a pen 000400: 77 68 69 63 68 20 63 78 0A 6F 73 74 73 20 33 31 which cx.osts 31 000410: 70 2C 20 61 62 6F 6F 6B 20 77 68 69 63 68 20 63 p, abook which c 000420: 6F 73 74 73 20 35 30 70 20 61 6E 64 20 61 20 20 osts 50p and a 000430: 20 20 72 75 62 62 65 72 20 77 68 69 63 68 20 63 rubber which c 000440: 6F 73 74 73 20 31 37 70 2E 20 48 6F 77 20 20 20 osts 17p. How 000450: 6D 75 63 68 20 64 6F 20 49 20 73 70 65 6E 64 20 much do I spend 000460: 61 6C 74 6F 67 65 74 68 65 72 3F 1B 39 38 70 1B altogether?.98p. 000470: 38 37 70 1B 39 34 70 1B 39 30 70 1B 60 00 57 68 87p.94p.90p.`.Wh 000480: 61 74 20 69 73 20 74 68 65 20 6D 69 73 73 69 6E at is the missin 000490: 67 20 6E 75 6D 62 65 72 3F 20 20 20 20 20 20 20 g number? 0004A0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0004B0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 3F ? 0004C0: 20 2B 20 32 36 20 3D 20 34 39 20 20 20 20 20 1B + 26 = 49 . 0004D0: 32 33 1B 32 32 1B 32 31 1B 32 34 1B 3D 00 20 20 23.22.21.24.=. 0004E0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0004F0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000500: 20 33 37 20 2B 20 32 31 20 6D 46 3D 20 3F 1B 35 37 + 21 mF= ?.5 000510: 38 1B 35 39 1B 36 30 1B 35 36 1B 7E 00 57 68 61 8.59.60.56.~.Wha 000520: 74 20 61 72 65 20 74 68 65 20 6E 65 78 74 20 6E t are the next n 000530: 75 6D 62 65 72 73 20 69 6E 20 20 74 68 69 73 20 umbers in this 000540: 73 65 71 75 65 6E 63 65 3A 20 20 20 20 20 20 20 sequence: 000550: 20 20 20 20 20 20 20 20 20 20 20 36 35 2C 20 37 65, 7 000560: 30 2C 20 37 35 2C 20 38 30 2C 20 3F 2C 20 3F 1B 0, 75, 80, ?, ?. 000570: 38 35 20 61 6E 64 20 39 30 1B 39 35 20 61 6E 64 85 and 90.95 and 000580: 20 31 30 30 1B 38 34 20 61 6E 64 20 38 39 1B 38 100.84 and 89.8 000590: 31 20 61 6E 64 20 38 36 1B 3D 00 20 20 20 20 20 1 and 86.=. 0005A0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0005B0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 37 38 78 0005C0: 20 2B 20 32 31 20 3D 20 3F 1B 39 39 1B 39 38 1B + 21 = ?.99.98. 0005D0: 39 36 1B 39 34 1B 28 00 41 64 64 20 66 6F 75 72 96.94.(.Add four 0005E0: 20 74 65 6E 73 20 61 6E 64 20 39 20 75 6E 69 74 tens and 9 unit 0005F0: 73 1B 34 39 1B 39 34 1B 31 33 1B 36 32 1B 45 00 s.49.94.13.62.E. 000600: 20 20 20 20 20 20 20 20 20 20 20 E9 AE 20 20 20 .. 000610: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000620: 31 33 63 6D 20 2B 20 36 63 6D 20 3D 20 3F 63 6D 13cm + 6cm = ?cm 000630: 1B 31 39 63 6D 1B 32 30 63 6D 1B 31 38 63 6D 1B .19cm.20cm.18cm. 000640: 32 31 63 6D 1B 59 00 50 6C 61 63 65 20 74 68 65 21cm.Y.Place the 000650: 20 63 6F 72 72 65 63 74 20 73 69 67 6E 20 28 3C correct sign (< 000660: 2C 20 3E 2C 20 6F 72 20 3D 29 20 69 6E 20 74 68 , >, or =) in th 000670: 69 73 20 6E 75 6D 62 65 72 20 73 65 6E 74 65 6E is number senten 000680: 63 65 3A 20 20 31 37 20 2B 20 32 32 20 3F 20 33 ce: 17 + 22 ? 3 000690: 34 20 2B 20 34 1B 3E 1B 3C 1B 3D 1B 20 1B 46 00 4 + 4.>.<.=. .F. 0006A0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0006B0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0006C0: 37 33 70 20 2B 20 34 70 20 2B 20 31 31 70 20 3D 73p + 4p + 11p = 0006D0: 20 3F 70 1B 38 38 70 1B 38 37 70 1B 38 39 70 1B ?p.88p.87p.89p. 0006E0: 38 36 70 1B 5F 00 46 69 6C 6C 20 69 6E 20 74 68 86p._.Fill in th 0006F0: 65 20 6D 69 73 73 69 6E 67 20 6E 75 6D 62 65 72 e missing number 000700: 73 3A 20 20 20 20 33 34 2C 20 33 38 2C D1 42 20 s: 34, 38,.B 000710: 3F 2C 20 3F 2C 20 35 30 2C 20 35 34 1B 34 32 20 ?, ?, 50, 54.42 000720: 61 6E 64 20 34 36 1B 34 30 20 61 6E 64 20 34 34 and 46.40 and 44 000730: 1B 34 31 20 61 6E 64 20 34 35 1B 34 34 20 61 6E .41 and 45.44 an 000740: 64 20 34 38 1B 3C 00 20 20 20 20 20 20 20 20 20 d 48.<. 000750: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000760: 20 20 20 20 20 36 32 20 2B 20 34 20 2B 20 31 31 62 + 4 + 11 000770: 20 3D 20 3F 1B 37 37 1B 37 39 1B 37 33 1B 38 31 = ?.77.79.73.81 000780: 1B 40 00 20 20 20 20 20 20 20 20 20 20 20 20 20 .@. 000790: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0007A0: 20 37 31 20 2B 20 33 20 2B 20 31 20 2B 20 31 34 71 + 3 + 1 + 14 0007B0: 20 3D 20 3F 1B 38 39 1B 39 32 1B 38 36 1B 39 30 = ?.89.92.86.90 0007C0: 1B 1C 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0007D0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0007E0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0007F0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000800: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 6F ...............o 000810: 45 FF FF FF FF E....
previousnext* BLOCK 0015 : TURBO LOADING DATA
HEADER
Block Name : AR7
Block Number : 1
Block first : YES
Block last : YES
File type : Binaire
File adress start : &6000
File adress length : &05CC
File adress execution : &0000
File length file : &05CC

Length of PILOT pulse : 2523
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1323
Length of ONE bit pulse : 2476
Length of PILOT tone : 4099
Used bits in last byte : 8 OK
Pause After this block : 22ms
Data : 263 bytes
Total size : 282 bytes

Sum DATA : 2 534		000000: 2C 41 52 37 00 00 00 00 00 00 00 00 00 00 00 00 ,AR7............ 000010: 00 01 FF 02 CC 05 00 60 FF CC 05 00 00 00 00 00 .......`........ 000020: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000030: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000040: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000050: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000060: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000070: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000080: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000090: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000A0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000B0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000C0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000D0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000E0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000F0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000100: 00 8E 63 FF FF FF FF ..c....
previousnext* BLOCK 0016 : TURBO LOADING DATA
DATA
Length of PILOT pulse : 2523
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1372
Length of ONE bit pulse : 2429
Length of PILOT tone : 4099
Used bits in last byte : 8 OK
Pause After this block : 13673ms
Data : 1553 bytes
Total size : 1572 bytes

Sum DATA : 89 003		000000: 16 41 52 37 00 00 00 00 00 00 00 00 19 CB 05 00 .AR7............ 000010: 53 75 62 74 72 61 63 74 69 6F 6E 20 2D 20 54 55 Subtraction - TU 000020: 20 20 20 20 20 20 20 20 20 00 00 00 00 00 00 00 ....... 000030: 00 3B 00 20 20 20 20 20 20 20 20 20 20 20 20 20 .;. 000040: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000050: 20 20 20 20 20 20 31 34 20 2D 20 33 20 3D 20 3F 14 - 3 = ? 000060: 1B 31 31 1B 31 32 1B 31 30 1B 39 1B 2B 00 46 72 .11.12.10.9.+.Fr 000070: 6F 6D 20 65 69 67 68 74 65 65 6E 20 74 61 6B 65 om eighteen take 000080: 20 61 77 61 79 20 73 69 78 2E 1B 31 32 1B 31 34 away six..12.14 000090: 1B 31 30 1B 31 33 1B 33 00 54 61 6B 65 20 65 6C .10.13.3.Take el 0000A0: 65 76 65 6E 20 61 77 61 79 20 66 72 6F 6D 20 20 even away from 0000B0: 20 20 20 20 20 20 20 73 65 76 65 6E 74 65 65 6E seventeen 0000C0: 2E 1B 36 1B 34 1B 35 1B 37 1B 22 00 46 72 6F 6D ..6.4.5.7.".From 0000D0: 20 32 35 20 73 75 62 74 72 61 63 74 20 31 34 2E 25 subtract 14. 0000E0: 1B 31 31 1B 31 35 1B 39 1B 31 30 1B 35 00 57 68 .11.15.9.10.5.Wh 0000F0: 61 74 20 6D 75 73 74 20 62 65 20 61 64 64 65 64 at must be added 000100: 20 E5 60 74 6F 20 34 33 20 74 6F 20 20 20 6D 61 .`to 43 to ma 000110: 6B 65 20 39 36 3F 1B 35 33 1B 34 37 1B 35 36 1B ke 96?.53.47.56. 000120: 34 39 1B 32 00 32 38 20 69 73 20 6C 65 73 73 20 49.2.28 is less 000130: 74 68 61 6E 20 34 39 20 62 79 20 68 6F 77 20 20 than 49 by how 000140: 20 20 20 6D 61 6E 79 3F 1B 32 31 1B 32 37 1B 31 many?.21.27.1 000150: 39 1B 32 34 1B 3D 00 20 20 20 20 20 20 20 20 20 9.24.=. 000160: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000170: 20 20 20 20 20 20 20 20 20 20 38 34 20 2D 20 36 84 - 6 000180: 33 20 3D 20 3F 1B 32 31 1B 32 34 1B 31 37 1B 32 3 = ?.21.24.17.2 000190: 39 1B 5E 00 46 69 6E 64 20 74 68 65 20 6D 69 73 9.^.Find the mis 0001A0: 73 69 6E 67 20 6E 75 6D 62 65 72 20 69 6E 20 20 sing number in 0001B0: 20 20 74 68 69 73 20 6E 75 6D 62 65 72 20 73 65 this number se 0001C0: 6E 74 65 6E 63 65 3A 20 20 20 20 20 20 20 20 20 ntence: 0001D0: 20 20 20 20 20 3F 20 2D 20 32 36 20 3D 20 35 31 ? - 26 = 51 0001E0: 20 20 20 1B 37 37 1B 37 31 1B 36 39 1B 38 31 1B .77.71.69.81. 0001F0: 5D 00 57 68 61 74 20 69 73 20 74 68 65 20 6D 69 ].What is the mi 000200: 73 73 69 23 F4 6E 67 20 6E 75 6D 62 65 72 3F 20 ssi#.ng number? 000210: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000220: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000230: 20 20 20 20 20 33 38 20 2D 20 3F 20 3D 20 36 20 38 - ? = 6 000240: 20 20 1B 33 32 1B 33 34 1B 33 30 1B 32 39 1B 23 .32.34.30.29.# 000250: 00 46 72 6F 6D 20 37 38 20 73 75 62 74 72 61 63 .From 78 subtrac 000260: 74 20 32 33 2E 1B 35 35 1B 34 37 1B 35 39 1B 36 t 23..55.47.59.6 000270: 35 1B 24 00 54 61 6B 65 20 61 77 61 79 20 68 61 5.$.Take away ha 000280: 6C 66 20 6F 66 20 38 34 2E 1B 34 32 1B 32 34 1B lf of 84..42.24. 000290: 33 36 1B 35 32 1B 32 00 43 6F 75 6E 74 20 62 61 36.52.2.Count ba 0002A0: 63 6B 20 73 65 76 65 6E 20 66 72 6F 6D 20 66 6F ck seven from fo 0002B0: 72 74 79 20 20 20 6E 69 6E 65 2E 1B 34 32 1B 34 rty nine..42.4 0002C0: 35 1B 34 33 1B 34 31 1B 37 00 57 68 61 74 20 69 5.43.41.7.What i 0002D0: 73 20 74 68 65 20 64 69 66 66 65 72 65 6E 63 65 s the difference 0002E0: 20 62 65 74 77 65 65 6E 39 38 20 61 6E 64 20 34 between98 and 4 0002F0: 37 3F 1B 35 31 1B 35 37 1B 34 39 1B 35 33 1B 44 7?.51.57.49.53.D 000300: 00 20 20 20 20 F8 09 20 20 20 20 20 20 20 20 20 . .. 000310: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000320: 20 20 20 20 31 31 63 6D 20 2D 20 36 63 6D 20 3D 11cm - 6cm = 000330: 20 3F 63 6D 1B 35 63 6D 1B 37 63 6D 1B 36 63 6D ?cm.5cm.7cm.6cm 000340: 1B 34 63 6D 1B 3D 00 20 20 20 20 20 20 20 20 20 .4cm.=. 000350: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000360: 20 20 20 20 20 20 20 20 20 20 3F 20 3D 20 32 37 ? = 27 000370: 20 2D 20 31 33 1B 31 34 1B 31 37 1B 31 31 1B 31 - 13.14.17.11.1 000380: 36 1B 39 00 46 72 6F 6D 20 65 69 67 68 74 79 20 6.9.From eighty 000390: 65 69 67 68 74 20 74 61 6B 65 20 61 77 61 79 20 eight take away 0003A0: 20 20 74 77 65 6E 74 79 20 66 69 76 65 2E 1B 36 twenty five..6 0003B0: 33 1B 35 36 1B 37 31 1B 36 39 1B 3C 00 20 20 20 3.56.71.69.<. 0003C0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0003D0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 36 6 0003E0: 36 20 2D 20 34 32 20 3D 20 3F 1B 32 34 1B 32 38 6 - 42 = ?.24.28 0003F0: 1B 33 30 1B 32 31 1B 22 00 46 72 6F 6D 20 37 32 .30.21.".From 72 000400: 20 73 75 62 74 72 61 4F 94 63 74 20 33 31 1B 34 subtraO.ct 31.4 000410: 31 1B 34 37 1B 33 37 1B 34 35 1B 32 00 36 32 20 1.47.37.45.2.62 000420: 69 73 20 6C 65 73 73 20 74 68 61 6E 20 38 38 20 is less than 88 000430: 2D 20 62 79 20 68 6F 77 20 20 20 6D 61 6E 79 3F - by how many? 000440: 1B 32 36 1B 32 32 1B 32 38 1B 32 34 1B 60 00 46 .26.22.28.24.`.F 000450: 69 6E 64 20 74 68 65 20 6D 69 73 73 69 6E 67 20 ind the missing 000460: 6E 75 6D 62 65 72 3A 20 20 20 20 20 20 20 20 20 number: 000470: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000480: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000490: 3F 20 2D 20 31 35 20 3D 20 34 31 20 20 20 20 20 ? - 15 = 41 0004A0: 1B 35 36 1B 35 34 1B 35 39 1B 36 34 1B 5F 00 57 .56.54.59.64._.W 0004B0: 68 61 74 20 69 73 20 74 68 65 20 6D 69 73 73 69 hat is the missi 0004C0: 6E 67 20 6E 75 6D 62 65 72 3F 20 20 20 20 20 20 ng number? 0004D0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0004E0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0004F0: 39 38 20 2D 20 3F 20 3D 20 31 32 20 20 20 20 1B 98 - ? = 12 . 000500: 38 36 1B 38 30 1B 38 34 1B FB C8 37 36 1B 23 00 86.80.84...76.#. 000510: 54 61 6B 65 20 61 77 61 79 20 68 61 6C 66 20 6F Take away half o 000520: 66 20 34 38 1B 32 34 1B 32 38 1B 32 32 1B 32 36 f 48.24.28.22.26 000530: 1B 31 00 43 6F 75 6E 74 20 62 61 63 6B 20 73 69 .1.Count back si 000540: 78 20 66 72 6F 6D 20 73 65 76 65 6E 74 79 20 20 x from seventy 000550: 20 6E 69 6E 65 1B 37 33 1B 37 32 1B 37 31 1B 37 nine.73.72.71.7 000560: 34 1B 37 00 57 68 61 74 20 69 73 20 74 68 65 20 4.7.What is the 000570: 64 69 66 66 65 72 65 6E 63 65 20 62 65 74 77 65 difference betwe 000580: 65 6E 32 37 20 61 6E 64 20 31 33 3F 1B 31 34 1B en27 and 13?.14. 000590: 31 33 1B 31 32 1B 31 35 1B 3D 00 20 20 20 20 20 13.12.15.=. 0005A0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0005B0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 33 37 37 0005C0: 20 2D 20 32 36 20 3D 20 3F 1B 31 31 1B 31 30 1B - 26 = ?.11.10. 0005D0: 31 32 1B 31 33 1B 1C 00 00 00 00 00 00 00 00 00 12.13........... 0005E0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0005F0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000600: 00 00 00 00 00 00 00 00 00 00 00 86 10 FF FF FF ................ 000610: FF .
previousnext* BLOCK 0017 : TURBO LOADING DATA
HEADER
Block Name : AR8
Block Number : 1
Block first : YES
File type : Binaire
File adress start : &6000
File adress length : &0800
File adress execution : &0000
File length file : &0876

Length of PILOT pulse : 2521
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1322
Length of ONE bit pulse : 2466
Length of PILOT tone : 4099
Used bits in last byte : 8 OK
Pause After this block : 22ms
Data : 263 bytes
Total size : 282 bytes

Sum DATA : 1 954		000000: 2C 41 52 38 00 00 00 00 00 00 00 00 00 00 00 00 ,AR8............ 000010: 00 01 00 02 00 08 00 60 FF 76 08 00 00 00 00 00 .......`.v...... 000020: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000030: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000040: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000050: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000060: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000070: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000080: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000090: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000A0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000B0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000C0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000D0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000E0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000F0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000100: 00 59 6E FF FF FF FF .Yn....
previousnext* BLOCK 0018 : TURBO LOADING DATA
DATA
Length of PILOT pulse : 2520
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1358
Length of ONE bit pulse : 2424
Length of PILOT tone : 4099
Used bits in last byte : 8 OK
Pause After this block : 2702ms
Data : 2069 bytes
Total size : 2088 bytes

Sum DATA : 104 641		000000: 16 41 52 38 00 00 00 00 00 00 00 00 19 75 08 00 .AR8.........u.. 000010: 4D 75 6C 74 69 70 6C 69 63 61 74 69 6F 6E 20 2D Multiplication - 000020: 20 54 55 20 20 20 20 20 20 00 00 00 00 00 00 00 TU ....... 000030: 00 54 00 57 68 61 74 20 69 73 20 74 68 65 20 6D .T.What is the m 000040: 69 73 73 69 6E 67 20 6E 75 6D 62 65 72 3F 20 20 issing number? 000050: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000060: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000070: 20 20 20 35 28 3F 29 20 3D 20 33 30 1B 36 1B 35 5(?) = 30.6.5 000080: 1B 34 1B 37 1B 5B 00 57 68 61 74 20 69 73 20 74 .4.7.[.What is t 000090: 68 65 20 6D 69 73 73 69 6E 67 20 6E 75 6D 62 65 he missing numbe 0000A0: 72 3F 20 20 20 20 20 20 20 20 20 20 20 20 20 20 r? 0000B0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0000C0: 20 20 20 20 20 20 20 20 38 20 78 20 3F 20 3D 20 8 x ? = 0000D0: 32 34 20 20 20 20 20 1B 33 1B 32 1B 34 1B 35 1B 24 .3.2.4.5. 0000E0: 5B 00 57 68 61 74 20 69 73 20 74 68 65 20 6D 69 [.What is the mi 0000F0: 73 73 69 6E 67 20 6E 75 6D 62 65 72 3F 20 20 20 ssing number? 000100: 20 43 39 20 20 20 20 20 20 20 20 20 20 20 20 20 C9 000110: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000120: 20 20 20 20 20 3F 28 32 29 20 3D 20 31 38 20 20 ?(2) = 18 000130: 20 20 20 1B 39 1B 38 1B 37 1B 31 30 1B 3A 00 20 .9.8.7.10.:. 000140: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000150: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000160: 20 34 20 78 20 34 20 3D 20 38 20 78 20 3F 1B 32 4 x 4 = 8 x ?.2 000170: 1B 34 1B 35 1B 33 1B 78 00 46 69 6C 6C 20 69 6E .4.5.3.x.Fill in 000180: 20 74 68 65 20 74 61 62 6C 65 20 6F 66 20 36 27 the table of 6' 000190: 73 3A 20 20 20 20 20 20 20 20 20 20 20 20 20 20 s: 0001A0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0001B0: 20 20 20 20 20 20 20 36 2C 20 31 32 2C 20 3F 2C 6, 12, ?, 0001C0: 20 32 34 2C 20 3F 1B 31 38 20 61 6E 64 20 33 30 24, ?.18 and 30 0001D0: 1B 31 36 20 61 6E 64 20 32 38 1B 32 30 20 61 6E .16 and 28.20 an 0001E0: 64 20 33 32 1B 32 32 20 61 6E 64 20 33 34 1B 3A d 32.22 and 34.: 0001F0: 00 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 . 000200: 20 20 20 DB 58 20 20 20 20 20 20 20 20 20 20 20 .X 000210: 20 20 20 20 20 34 20 78 20 35 20 3D 20 3F 1B 32 4 x 5 = ?.2 000220: 30 1B 31 36 1B 32 34 1B 31 35 1B 65 00 20 20 20 0.16.24.15.e. 000230: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000240: 20 20 20 20 20 20 20 20 20 20 20 34 20 2B 20 34 4 + 4 000250: 20 2B 20 34 20 2B 20 34 20 3D 20 3F 20 78 20 3F + 4 + 4 = ? x ? 000260: 20 3D 20 3F 1B 34 20 78 20 34 20 3D 20 31 36 1B = ?.4 x 4 = 16. 000270: 34 20 78 20 32 20 3D 20 38 1B 34 20 78 20 33 20 4 x 2 = 8.4 x 3 000280: 3D 20 31 32 1B 34 20 78 20 35 20 3D 20 32 30 1B = 12.4 x 5 = 20. 000290: 48 00 20 20 20 20 20 20 20 20 20 20 20 20 20 20 H. 0002A0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0002B0: 4D 61 6B 65 20 31 30 20 73 65 76 65 6E 20 74 69 Make 10 seven ti 0002C0: 6D 65 73 20 62 69 67 67 65 72 2E 1B 37 30 1B 36 mes bigger..70.6 0002D0: 30 1B 38 30 1B 37 37 1B 59 00 57 68 61 74 20 69 0.80.77.Y.What i 0002E0: 73 20 74 68 65 20 6D 69 73 73 69 6E 67 20 6E 75 s the missing nu 0002F0: 6D 62 65 72 3F 20 20 20 20 20 20 20 20 20 20 20 mber? 000300: 20 20 20 20 20 96 E3 20 20 20 20 20 20 20 20 20 .. 000310: 20 20 20 20 20 20 20 20 20 20 20 20 20 3F 20 78 ? x 000320: 20 38 20 3D 20 34 38 20 20 20 1B 36 1B 35 1B 37 8 = 48 .6.5.7 000330: 1B 38 1B 5A 00 46 69 6E 64 20 74 68 65 20 6D 69 .8.Z.Find the mi 000340: 73 73 69 6E 67 20 6E 75 6D 62 65 72 3A 20 20 20 ssing number: 000350: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000360: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000370: 20 20 20 20 20 34 28 3F 29 20 3D 20 33 36 20 20 4(?) = 36 000380: 20 20 20 20 1B 39 1B 38 1B 37 1B 36 1B 58 00 57 .9.8.7.6.X.W 000390: 68 61 74 20 69 73 20 74 68 65 20 6D 69 73 73 69 hat is the missi 0003A0: 6E 67 20 6E 75 6D 62 65 72 3F 20 20 20 20 20 20 ng number? 0003B0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0003C0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 39 9 0003D0: 20 78 20 3F 20 3D 20 35 34 20 20 20 1B 36 1B 37 x ? = 54 .6.7 0003E0: 1B 38 1B 34 1B 5A 00 46 69 6E 64 20 74 68 65 20 .8.4.Z.Find the 0003F0: 6D 69 73 73 69 6E 67 20 6E 75 6D 62 65 72 3A 20 missing number: 000400: 20 20 20 20 20 20 20 68 5B 20 20 20 20 20 20 20 h[ 000410: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000420: 20 20 20 20 20 20 20 20 20 20 3F 28 38 29 20 3D ?(8) = 000430: 20 38 30 20 20 20 1B 31 30 1B 39 1B 38 1B 31 31 80 .10.9.8.11 000440: 1B 78 00 46 69 6C 6C 20 69 6E 20 74 68 65 20 74 .x.Fill in the t 000450: 61 62 6C 65 20 6F 66 20 31 30 27 73 3A 20 20 20 able of 10's: 000460: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000470: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 35 5 000480: 30 2C 20 36 30 2C 20 3F 2C 20 38 30 2C 20 3F 1B 0, 60, ?, 80, ?. 000490: 37 30 20 61 6E 64 20 39 30 1B 36 35 20 61 6E 64 70 and 90.65 and 0004A0: 20 38 35 1B 36 30 20 61 6E 64 20 31 30 30 1B 37 85.60 and 100.7 0004B0: 35 20 61 6E 64 20 39 35 1B 3B 00 20 20 20 20 20 5 and 95.;. 0004C0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0004D0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 36 20 6 0004E0: 78 20 36 20 3D 20 3F 1B 33 36 1B 33 32 1B 34 30 x 6 = ?.36.32.40 0004F0: 1B 34 32 1B 7A 00 20 20 20 20 20 20 20 20 20 20 .42.z. 000500: 20 20 20 20 20 20 20 20 20 75 4F 20 20 20 20 20 uO 000510: 20 20 20 20 20 20 35 20 2B 20 35 20 2B 20 35 20 5 + 5 + 5 000520: 2B 20 35 20 2B 20 35 20 2B 20 35 20 20 20 20 20 + 5 + 5 + 5 000530: 20 20 20 20 20 20 20 20 3D 20 3F 20 78 20 3F 20 = ? x ? 000540: 3D 20 3F 1B 35 20 78 20 36 20 3D 20 33 30 1B 35 = ?.5 x 6 = 30.5 000550: 20 78 20 35 20 3D 20 32 35 1B 35 20 78 20 37 20 x 5 = 25.5 x 7 000560: 3D 20 33 35 1B 35 20 78 20 38 20 3D 20 34 30 1B = 35.5 x 8 = 40. 000570: 28 00 4D 61 6B 65 20 33 20 6E 69 6E 65 20 74 69 (.Make 3 nine ti 000580: 6D 65 73 20 62 69 67 67 65 72 2E 1B 32 37 1B 33 mes bigger..27.3 000590: 30 1B 32 34 1B 32 31 1B 59 00 57 68 61 74 20 69 0.24.21.Y.What i 0005A0: 73 20 74 68 65 20 6D 69 73 73 69 6E 67 20 6E 75 s the missing nu 0005B0: 6D 62 65 72 3F 20 20 20 20 20 20 20 20 20 20 20 mber? 0005C0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0005D0: 20 20 20 20 20 20 20 20 20 20 20 3F 20 78 20 37 ? x 7 0005E0: 20 3D 20 32 38 20 20 20 1B 34 1B 35 1B 36 1B 33 = 28 .4.5.6.3 0005F0: 1B 5B 00 46 69 6E 64 20 74 68 65 20 6D 69 73 73 .[.Find the miss 000600: 69 6E 67 20 6E 75 6D 62 65 72 3A 80 41 20 20 20 ing number:.A 000610: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000620: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000630: 20 20 20 20 20 20 31 30 28 3F 29 20 3D 20 36 30 10(?) = 60 000640: 20 20 20 20 20 1B 36 1B 35 1B 37 1B 34 1B 77 00 .6.5.7.4.w. 000650: 46 69 6C 6C 20 69 6E 20 74 68 65 20 74 61 62 6C Fill in the tabl 000660: 65 20 6F 66 20 34 27 73 3A 20 20 20 20 20 20 20 e of 4's: 000670: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000680: 20 20 20 20 20 20 20 20 20 20 20 20 31 36 2C 20 16, 000690: 32 30 2C 20 3F 2C 20 32 38 2C 20 3F 1B 32 34 20 20, ?, 28, ?.24 0006A0: 61 6E 64 20 33 32 1B 32 36 20 61 6E 64 20 33 34 and 32.26 and 34 0006B0: 1B 32 32 20 61 6E 64 20 33 30 1B 32 35 20 61 6E .22 and 30.25 an 0006C0: 64 20 33 33 1B 78 00 20 20 20 20 20 20 20 20 20 d 33.x. 0006D0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0006E0: 20 20 20 20 20 36 20 2B 20 36 20 2B 20 36 20 2B 6 + 6 + 6 + 0006F0: 20 36 20 2B 20 36 20 2B 20 36 20 2B 20 36 20 20 6 + 6 + 6 + 6 000700: 20 20 20 20 20 3D 20 3F 20 78 20 3F 20 79 43 3D = ? x ? yC= 000710: 20 3F 1B 36 20 78 20 37 20 3D 20 34 32 1B 36 20 ?.6 x 7 = 42.6 000720: 78 20 38 20 3D 20 34 38 1B 36 20 78 20 36 20 3D x 8 = 48.6 x 6 = 000730: 20 33 36 1B 36 20 78 20 33 20 3D 20 31 38 1B 3B 36.6 x 3 = 18.; 000740: 00 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 . 000750: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000760: 20 20 20 20 36 20 78 20 39 20 3D 20 3F 1B 35 34 6 x 9 = ?.54 000770: 1B 34 38 1B 35 36 1B 35 38 1B 58 00 57 68 61 74 .48.56.58.X.What 000780: 20 69 73 20 74 68 65 20 6D 69 73 73 69 6E 67 20 is the missing 000790: 6E 75 6D 62 65 72 3F 20 20 20 20 20 20 20 20 20 number? 0007A0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0007B0: 20 20 20 20 20 20 20 20 20 20 20 20 3F 28 34 29 ?(4) 0007C0: 20 3D 20 33 32 20 20 20 20 1B 38 1B 37 1B 39 1B = 32 .8.7.9. 0007D0: 36 1B 3C 00 20 20 20 20 20 20 20 20 20 20 20 20 6.<. 0007E0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0007F0: 20 20 20 20 20 20 20 39 20 78 20 31 30 20 3D 20 9 x 10 = 000800: 3F 1B 39 30 1B 39 39 1B 38 35 1B 38 30 1B 3B 29 ?.90.99.85.80.;) 000810: AF FF FF FF FF .....
previousnext* BLOCK 0019 : TURBO LOADING DATA
HEADER
Block Name : AR8
Block Number : 2
Block last : YES
File type : Binaire
File adress start : &6800
File adress length : &0076
File adress execution : &0000
File length file : &0876

Length of PILOT pulse : 2514
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1318
Length of ONE bit pulse : 2468
Length of PILOT tone : 4099
Used bits in last byte : 8 OK
Pause After this block : 24ms
Data : 263 bytes
Total size : 282 bytes

Sum DATA : 2 005		000000: 2C 41 52 38 00 00 00 00 00 00 00 00 00 00 00 00 ,AR8............ 000010: 00 02 FF 02 76 00 00 68 00 76 08 00 00 00 00 00 ....v..h.v...... 000020: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000030: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000040: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000050: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000060: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000070: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000080: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000090: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000A0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000B0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000C0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000D0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000E0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000F0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000100: 00 25 5E FF FF FF FF .%^....
previousnext* BLOCK 0020 : TURBO LOADING DATA
DATA
Length of PILOT pulse : 2513
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1328
Length of ONE bit pulse : 2435
Length of PILOT tone : 4099
Used bits in last byte : 8 OK
Pause After this block : 13663ms
Data : 263 bytes
Total size : 282 bytes

Sum DATA : 5 523		000000: 16 00 20 20 20 20 20 20 20 20 20 20 20 20 20 20 .. 000010: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000020: 20 20 20 20 20 35 20 78 20 38 20 3D 20 3F 1B 34 5 x 8 = ?.4 000030: 30 1B 33 38 1B 34 32 1B 34 35 1B 3B 00 20 20 20 0.38.42.45.;. 000040: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000050: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000060: 33 20 78 20 36 20 3D 20 3F 1B 31 38 1B 32 34 1B 3 x 6 = ?.18.24. 000070: 32 32 1B 31 36 1B 1C 00 00 00 00 00 00 00 00 00 22.16........... 000080: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000090: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000A0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000B0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000C0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000D0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000E0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000F0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000100: 00 45 21 FF FF FF FF .E!....
previousnext* BLOCK 0021 : TURBO LOADING DATA
HEADER
Block Name : AR9
Block Number : 1
Block first : YES
Block last : YES
File type : Binaire
File adress start : &6000
File adress length : &0781
File adress execution : &0000
File length file : &0781

Length of PILOT pulse : 2513
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1318
Length of ONE bit pulse : 2469
Length of PILOT tone : 4099
Used bits in last byte : 8 OK
Pause After this block : 24ms
Data : 263 bytes
Total size : 282 bytes

Sum DATA : 2 346		000000: 2C 41 52 39 00 00 00 00 00 00 00 00 00 00 00 00 ,AR9............ 000010: 00 01 FF 02 81 07 00 60 FF 81 07 00 00 00 00 00 .......`........ 000020: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000030: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000040: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000050: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000060: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000070: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000080: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000090: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000A0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000B0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000C0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000D0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000E0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000F0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000100: 00 A7 1E FF FF FF FF .......
previousnext* BLOCK 0022 : TURBO LOADING DATA
DATA
Length of PILOT pulse : 2513
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1361
Length of ONE bit pulse : 2428
Length of PILOT tone : 4099
Used bits in last byte : 8 OK
Pause After this block : 13694ms
Data : 2069 bytes
Total size : 2088 bytes

Sum DATA : 130 252		000000: 16 41 52 39 00 00 00 00 00 00 00 00 19 80 07 00 .AR9............ 000010: 44 69 76 69 73 69 6F 6E 20 2D 20 54 55 20 20 20 Division - TU 000020: 20 20 20 20 20 20 20 20 20 00 00 00 00 00 00 00 ....... 000030: 00 37 00 20 20 20 20 20 20 20 20 20 20 20 20 20 .7. 000040: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000050: 20 44 69 76 69 64 65 20 31 32 20 62 79 20 34 1B Divide 12 by 4. 000060: 33 1B 34 1B 36 1B 32 1B 3C 00 20 20 20 20 20 20 3.4.6.2.<. 000070: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000080: 20 20 20 20 20 20 20 20 34 38 20 64 69 76 69 64 48 divid 000090: 65 64 20 62 79 20 36 20 3D 20 3F 1B 38 1B 36 1B ed by 6 = ?.8.6. 0000A0: 39 1B 37 1B 4F 00 49 66 20 62 61 72 73 20 6F 66 9.7.O.If bars of 0000B0: 20 63 68 6F 63 6F 6C 61 74 65 20 63 6F 73 74 20 chocolate cost 0000C0: 36 70 20 20 65 61 63 68 2C 20 68 6F 77 20 6D 61 6p each, how ma 0000D0: 6E 79 20 63 61 6E 20 62 65 20 62 6F 75 67 68 74 ny can be bought 0000E0: 20 20 66 6F 72 20 35 34 70 3F 1B 39 1B 38 1B 37 for 54p?.9.8.7 0000F0: 1B 36 1B 5D 00 49 66 20 32 38 20 69 73 20 64 69 .6.].If 28 is di 000100: 76 1E 2D 69 64 65 64 20 69 6E 74 6F 20 73 75 62 v.-ided into sub 000110: 73 65 74 73 20 77 69 74 68 20 37 20 69 6E 20 65 sets with 7 in e 000120: 61 63 68 2C 20 68 6F 77 20 6D 61 6E 79 20 20 20 ach, how many 000130: 20 20 20 73 75 62 73 65 74 73 20 77 69 6C 6C 20 subsets will 000140: 74 68 65 72 65 20 62 65 3F 1B 34 1B 36 1B 33 1B there be?.4.6.3. 000150: 37 1B 8A 00 20 20 20 20 20 20 20 20 20 20 20 20 7... 000160: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000170: 20 20 32 39 20 64 69 76 69 64 65 64 20 62 79 20 29 divided by 000180: 34 20 65 71 75 61 6C 73 20 20 20 20 20 20 20 20 4 equals 000190: 20 20 20 20 20 20 3F 20 72 65 6D 61 69 6E 64 65 ? remainde 0001A0: 72 20 3F 1B 37 20 72 65 6D 61 69 6E 64 65 72 20 r ?.7 remainder 0001B0: 31 1B 36 20 72 65 6D 61 69 6E 64 65 72 20 32 1B 1.6 remainder 2. 0001C0: 38 20 72 65 6D 61 69 6E 64 65 72 20 33 1B 35 20 8 remainder 3.5 0001D0: 72 65 6D 61 69 6E 64 65 72 20 33 1B 3A 00 20 20 remainder 3.:. 0001E0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0001F0: 20 20 20 20 20 20 20 20 20 20 20 20 44 69 76 69 Divi 000200: 64 65 20 14 A6 39 30 20 62 79 20 31 30 20 1B 39 de ..90 by 10 .9 000210: 1B 38 1B 37 1B 31 30 1B 51 00 44 69 76 69 64 65 .8.7.10.Q.Divide 000220: 20 33 35 20 69 6E 74 6F 20 73 75 62 73 65 74 73 35 into subsets 000230: 20 77 69 74 68 20 20 20 66 69 76 65 20 69 6E 20 with five in 000240: 65 61 63 68 2E 20 48 6F 77 20 6D 61 6E 79 20 73 each. How many s 000250: 75 62 73 65 74 73 61 72 65 20 74 68 65 72 65 3F ubsetsare there? 000260: 1B 37 1B 36 1B 38 1B 35 1B 77 00 41 20 70 69 65 .7.6.8.5.w.A pie 000270: 63 65 20 6F 66 20 72 69 62 62 6F 6E 20 36 38 63 ce of ribbon 68c 000280: 6D 20 6C 6F 6E 67 20 69 73 63 75 74 20 69 6E 74 m long iscut int 000290: 6F 20 34 20 70 69 65 63 65 73 20 6F 66 20 65 71 o 4 pieces of eq 0002A0: 75 61 6C 20 20 20 20 6C 65 6E 67 74 68 2E 20 20 ual length. 0002B0: 48 6F 77 20 6C 6F 6E 67 20 69 73 20 65 61 63 68 How long is each 0002C0: 20 20 20 20 20 70 69 65 63 65 3F 1B 31 37 63 6D piece?.17cm 0002D0: 1B 31 34 63 6D 1B 31 39 63 6D 1B 31 35 63 6D 1B .14cm.19cm.15cm. 0002E0: 37 00 20 20 20 20 20 20 20 20 20 20 20 20 20 20 7. 0002F0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000300: 44 69 76 69 64 79 D9 65 20 33 30 20 62 79 20 36 Dividy.e 30 by 6 000310: 1B 35 1B 34 1B 36 1B 37 1B 40 00 20 20 20 20 20 .5.4.6.7.@. 000320: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000330: 20 20 20 20 20 20 20 20 20 34 34 20 64 69 76 69 44 divi 000340: 64 65 64 20 62 79 20 34 20 3D 20 3F 1B 31 31 1B ded by 4 = ?.11. 000350: 31 32 1B 31 30 1B 31 33 1B 42 00 49 66 20 72 75 12.10.13.B.If ru 000360: 62 62 65 72 73 20 63 6F 73 74 20 31 30 70 2C 20 bbers cost 10p, 000370: 68 6F 77 20 6D 61 6E 79 20 63 6F 75 6C 64 20 62 how many could b 000380: 65 20 62 6F 75 67 68 74 20 66 6F 72 20 35 30 70 e bought for 50p 000390: 3F 1B 35 1B 31 30 1B 37 1B 33 1B 38 00 48 6F 77 ?.5.10.7.3.8.How 0003A0: 20 6D 61 6E 79 20 73 65 74 73 20 6F 66 20 73 69 many sets of si 0003B0: 78 20 61 72 65 20 74 68 65 72 65 69 6E 20 74 77 x are therein tw 0003C0: 65 6E 74 79 2D 66 6F 75 72 3F 1B 34 1B 36 1B 38 enty-four?.4.6.8 0003D0: 1B 32 1B 22 00 57 68 61 74 20 69 73 20 68 61 6C .2.".What is hal 0003E0: 66 20 6F 66 20 34 32 3F 1B 32 31 1B 31 32 1B 32 f of 42?.21.12.2 0003F0: 34 1B 32 38 1B 35 00 57 68 61 74 20 69 73 20 61 4.28.5.What is a 000400: 20 71 75 61 72 74 65 BC F6 72 20 6F 66 20 6F 6E quarte..r of on 000410: 65 20 20 20 20 20 20 68 75 6E 64 72 65 64 3F 1B e hundred?. 000420: 32 35 1B 32 30 1B 35 30 1B 37 35 1B 24 00 57 68 25.20.50.75.$.Wh 000430: 61 74 20 69 73 20 68 61 6C 66 20 6F 66 20 73 69 at is half of si 000440: 78 74 65 65 6E 3F 1B 38 1B 31 32 1B 36 1B 37 1B xteen?.8.12.6.7. 000450: 6F 00 20 20 20 20 20 20 20 20 20 20 20 20 20 20 o. 000460: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000470: 33 39 20 64 69 76 69 64 65 64 20 62 79 20 36 20 39 divided by 6 000480: 3D 20 3F 20 72 3F 1B 36 20 72 65 6D 61 69 6E 64 = ? r?.6 remaind 000490: 65 72 20 33 1B 35 20 72 65 6D 61 69 6E 64 65 72 er 3.5 remainder 0004A0: 20 34 1B 36 20 72 65 6D 61 69 6E 64 65 72 20 35 4.6 remainder 5 0004B0: 1B 35 20 72 65 6D 61 69 6E 64 65 72 20 31 1B 3A .5 remainder 1.: 0004C0: 00 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 . 0004D0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 44 D 0004E0: 69 76 69 64 65 20 33 36 20 62 79 20 33 1B 31 32 ivide 36 by 3.12 0004F0: 1B 31 30 1B 39 1B 31 33 1B 3C 00 20 20 20 20 20 .10.9.13.<. 000500: 20 20 20 20 20 20 20 20 20 0A D3 20 20 20 20 20 .. 000510: 20 20 20 20 20 20 20 20 20 20 20 33 32 20 64 69 32 di 000520: 76 69 64 65 64 20 62 79 20 38 20 3D 20 3F 1B 34 vided by 8 = ?.4 000530: 1B 33 1B 35 1B 36 1B 51 00 32 37 20 64 69 76 69 .3.5.6.Q.27 divi 000540: 64 65 64 20 62 79 20 36 20 3D 20 3F 20 72 3F 1B ded by 6 = ? r?. 000550: 34 20 72 65 6D 61 69 6E 64 65 72 20 33 1B 33 20 4 remainder 3.3 000560: 72 65 6D 61 69 6E 64 65 72 20 35 1B 34 20 72 65 remainder 5.4 re 000570: 6D 61 69 6E 64 65 72 20 34 1B 33 20 72 65 6D 61 mainder 4.3 rema 000580: 69 6E 64 65 72 20 34 1B 6F 00 20 20 20 20 20 20 inder 4.o. 000590: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0005A0: 20 20 20 20 20 20 20 20 32 38 20 64 69 76 69 64 28 divid 0005B0: 65 64 20 62 79 20 35 20 3D 20 3F 20 72 3F 1B 35 ed by 5 = ? r?.5 0005C0: 20 72 65 6D 61 69 6E 64 65 72 20 33 1B 36 20 72 remainder 3.6 r 0005D0: 65 6D 61 69 6E 64 65 72 20 32 1B 33 20 72 65 6D emainder 2.3 rem 0005E0: 61 69 6E 64 65 72 20 34 1B 34 20 72 65 6D 61 69 ainder 4.4 remai 0005F0: 6E 64 65 72 20 31 1B 38 00 57 68 61 74 20 69 73 nder 1.8.What is 000600: 20 61 20 71 75 61 72 74 65 72 20 15 F7 6F 66 20 a quarter ..of 000610: 20 20 20 20 20 20 20 20 20 66 6F 72 74 79 2D 65 forty-e 000620: 69 67 68 74 3F 1B 31 32 1B 38 1B 31 34 1B 32 34 ight?.12.8.14.24 000630: 1B 70 00 20 20 20 20 20 20 20 20 20 20 20 20 20 .p. 000640: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000650: 20 38 34 20 64 69 76 69 64 65 64 20 62 79 20 31 84 divided by 1 000660: 30 20 3D 20 3F 20 72 3F 1B 38 20 72 65 6D 61 69 0 = ? r?.8 remai 000670: 6E 64 65 72 20 34 1B 39 20 72 65 6D 61 69 6E 64 nder 4.9 remaind 000680: 65 72 20 34 1B 38 20 72 65 6D 61 69 6E 64 65 72 er 4.8 remainder 000690: 20 38 1B 37 20 72 65 6D 61 69 6E 64 65 72 20 36 8.7 remainder 6 0006A0: 1B 3C 00 20 20 20 20 20 20 20 20 20 20 20 20 20 .<. 0006B0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0006C0: 20 35 34 20 64 69 76 69 64 65 64 20 62 79 20 36 54 divided by 6 0006D0: 20 3D 20 3F 1B 39 1B 38 1B 37 1B 36 1B 2B 00 57 = ?.9.8.7.6.+.W 0006E0: 68 61 74 20 69 73 20 68 61 6C 66 20 6F 66 20 73 hat is half of s 0006F0: 69 78 74 79 2D 65 69 67 68 74 3F 1B 33 34 1B 33 ixty-eight?.34.3 000700: 36 1B 33 32 1B 33 38 1B 85 00 4D 69 63 08 A7 68 6.32.38...Mic..h 000710: 61 65 6C 20 64 69 64 20 75 70 20 37 20 62 75 74 ael did up 7 but 000720: 74 6F 6E 73 20 69 6E 20 20 20 32 31 20 73 65 63 tons in 21 sec 000730: 6F 6E 64 73 2E 20 48 6F 77 20 6C 6F 6E 67 20 64 onds. How long d 000740: 69 64 20 69 74 20 20 20 74 61 6B 65 20 68 69 6D id it take him 000750: 20 74 6F 20 64 6F 20 75 70 20 65 61 63 68 20 62 to do up each b 000760: 75 74 74 6F 6E 3F 1B 33 20 73 65 63 6F 6E 64 73 utton?.3 seconds 000770: 1B 34 20 73 65 63 6F 6E 64 73 1B 32 20 73 65 63 .4 seconds.2 sec 000780: 6F 6E 64 73 1B 35 20 73 65 63 6F 6E 64 73 1B 1C onds.5 seconds.. 000790: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0007A0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0007B0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0007C0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0007D0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0007E0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0007F0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000800: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 3E ...............> 000810: D4 FF FF FF FF .....
previousnext* BLOCK 0023 : TURBO LOADING DATA
HEADER
Block Name : AR10
Block Number : 1
Block first : YES
Block last : YES
File type : Binaire
File adress start : &6000
File adress length : &07CF
File adress execution : &0000
File length file : &07CF

Length of PILOT pulse : 2515
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1319
Length of ONE bit pulse : 2474
Length of PILOT tone : 4099
Used bits in last byte : 8 OK
Pause After this block : 23ms
Data : 263 bytes
Total size : 282 bytes

Sum DATA : 2 680		000000: 2C 41 52 31 30 00 00 00 00 00 00 00 00 00 00 00 ,AR10........... 000010: 00 01 FF 02 CF 07 00 60 FF CF 07 00 00 00 00 00 .......`........ 000020: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000030: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000040: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000050: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000060: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000070: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000080: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000090: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000A0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000B0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000C0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000D0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000E0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000F0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000100: 00 F9 56 FF FF FF FF ..V....
previousnext* BLOCK 0024 : TURBO LOADING DATA
DATA
Length of PILOT pulse : 2514
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1373
Length of ONE bit pulse : 2432
Length of PILOT tone : 4099
Used bits in last byte : 8 OK
Pause After this block : 65535ms
Data : 2069 bytes
Total size : 2088 bytes

Sum DATA : 153 617		000000: 16 41 52 31 30 00 00 00 00 00 00 00 19 CE 07 00 .AR10........... 000010: 41 6C 6C 20 53 6F 72 74 73 20 20 20 20 20 20 20 All Sorts 000020: 20 20 20 20 20 20 20 20 20 00 00 00 00 00 00 00 ....... 000030: 00 42 00 48 6F 77 20 6D 61 6E 79 20 6D 69 6E 75 .B.How many minu 000040: 74 65 73 20 61 72 65 20 74 68 65 72 65 20 69 6E tes are there in 000050: 20 61 20 71 75 61 72 74 65 72 20 6F 66 20 61 6E a quarter of an 000060: 20 68 6F 75 72 3F 1B 31 35 1B 33 30 1B 34 35 1B hour?.15.30.45. 000070: 36 30 1B 86 00 48 6F 77 20 6D 61 6E 79 20 74 65 60...How many te 000080: 6E 73 20 61 6E 64 20 75 6E 69 74 73 20 61 72 65 ns and units are 000090: 20 20 20 74 68 65 72 65 20 69 6E 20 74 68 65 20 there in the 0000A0: 6E 75 6D 62 65 72 20 34 32 2E 1B 34 20 74 65 6E number 42..4 ten 0000B0: 73 20 61 6E 64 20 32 20 75 6E 69 74 73 1B 32 20 s and 2 units.2 0000C0: 74 65 6E 73 20 61 6E 64 20 34 20 75 6E 69 74 73 tens and 4 units 0000D0: 1B 34 30 20 74 65 6E 73 20 61 6E 64 20 32 20 75 .40 tens and 2 u 0000E0: 6E 69 74 73 1B 32 30 20 74 65 6E 73 20 61 6E 64 nits.20 tens and 0000F0: 20 34 20 75 6E 69 74 73 1B 83 00 57 68 61 74 20 4 units...What 000100: 69 1B 5E 73 20 74 68 65 20 63 6F 72 72 65 63 74 i.^s the correct 000110: 20 73 79 6D 62 6F 6C 20 20 20 20 28 3C 2C 20 3E symbol (<, > 000120: 20 6F 72 20 3D 29 20 6E 65 65 64 65 64 20 74 6F or =) needed to 000130: 20 63 6F 6D 70 6C 65 74 65 74 68 69 73 20 6E 75 completethis nu 000140: 6D 62 65 72 20 73 65 6E 74 65 6E 63 65 3A 20 20 mber sentence: 000150: 20 20 20 20 20 20 20 38 20 2B 20 32 20 2B 20 34 8 + 2 + 4 000160: 20 2B 20 31 20 3F 20 34 20 2B 20 37 20 2B 20 33 + 1 ? 4 + 7 + 3 000170: 20 2B 20 32 20 1B 3C 1B 3E 1B 3D 1B 20 1B 47 00 + 2 .<.>.=. .G. 000180: 48 6F 77 20 6D 75 63 68 20 69 73 20 74 68 65 20 How much is the 000190: 38 20 77 6F 72 74 68 20 69 6E 20 74 68 65 6E 75 8 worth in thenu 0001A0: 6D 62 65 72 20 38 37 3F 1B 38 20 74 65 6E 73 1B mber 87?.8 tens. 0001B0: 38 20 75 6E 69 74 73 1B 38 20 68 75 6E 64 72 65 8 units.8 hundre 0001C0: 64 73 1B 20 1B 4E 00 49 66 20 79 6F 75 20 73 61 ds. .N.If you sa 0001D0: 79 20 74 68 65 20 74 69 6D 65 20 69 73 20 32 30 y the time is 20 0001E0: 20 74 6F 20 32 68 6F 77 20 73 68 6F 75 6C 64 20 to 2how should 0001F0: 69 74 20 62 65 20 77 72 69 74 74 65 6E 3F 1B 31 it be written?.1 000200: 2E 34 30 C9 D2 1B 31 2E 35 30 1B 32 2E 34 30 1B .40...1.50.2.40. 000210: 32 2E 32 30 1B 40 00 48 6F 77 20 69 73 20 74 68 2.20.@.How is th 000220: 65 20 6E 75 6D 62 65 72 20 73 65 76 65 6E 74 79 e number seventy 000230: 20 66 6F 75 72 77 72 69 74 74 65 6E 20 69 6E 20 fourwritten in 000240: 66 69 67 75 72 65 73 3F 1B 37 34 1B 37 30 34 1B figures?.74.704. 000250: 34 37 1B 20 1B 2F 00 48 6F 77 20 6D 61 6E 79 20 47. ./.How many 000260: 66 61 63 65 73 20 64 6F 65 73 20 61 20 63 75 62 faces does a cub 000270: 65 20 20 20 20 68 61 76 65 3F 1B 36 1B 34 1B 31 e have?.6.4.1 000280: 32 1B 38 1B 20 00 57 68 61 74 20 69 73 20 68 61 2.8. .What is ha 000290: 6C 66 20 6F 66 20 31 34 3F 1B 37 1B 38 1B 32 38 lf of 14?.7.8.28 0002A0: 1B 32 34 1B 55 00 48 6F 77 20 6D 61 6E 79 20 6D .24.U.How many m 0002B0: 69 6E 75 74 65 73 20 61 72 65 20 74 68 65 72 65 inutes are there 0002C0: 20 20 20 20 62 65 74 77 65 65 6E 20 33 2E 30 35 between 3.05 0002D0: 20 70 2E 6D 2E 20 61 6E 64 20 20 20 20 20 20 20 p.m. and 0002E0: 20 20 33 2E 34 30 20 70 2E 6D 2E 3F 1B 33 35 1B 3.40 p.m.?.35. 0002F0: 33 30 1B 34 30 1B 32 35 1B 70 00 48 6F 77 20 6D 30.40.25.p.How m 000300: 61 6E 79 20 74 69 FB 65 6E 73 20 61 6E 64 20 75 any ti.ens and u 000310: 6E 69 74 73 20 69 73 20 74 68 65 6E 75 6D 62 65 nits is thenumbe 000320: 72 20 39 31 20 77 6F 72 74 68 3F 1B 39 20 74 65 r 91 worth?.9 te 000330: 6E 73 20 61 6E 64 20 31 20 75 6E 69 74 1B 31 20 ns and 1 unit.1 000340: 74 65 6E 20 61 6E 64 20 39 20 75 6E 69 74 73 1B ten and 9 units. 000350: 39 30 20 74 65 6E 73 20 61 6E 64 20 31 20 75 6E 90 tens and 1 un 000360: 69 74 1B 39 31 20 74 65 6E 73 1B 52 00 49 66 20 it.91 tens.R.If 000370: 79 6F 75 20 73 61 79 20 74 68 65 20 74 69 6D 65 you say the time 000380: 20 69 73 20 35 20 74 6F 20 31 31 68 6F 77 20 73 is 5 to 11how s 000390: 68 6F 75 6C 64 20 69 74 20 62 65 20 77 72 69 74 hould it be writ 0003A0: 74 65 6E 3F 1B 31 30 2E 35 35 1B 31 31 2E 30 35 ten?.10.55.11.05 0003B0: 1B 31 31 2E 35 35 1B 31 30 2E 34 35 1B 82 00 57 .11.55.10.45...W 0003C0: 68 61 74 20 69 73 20 74 68 65 20 63 6F 72 72 65 hat is the corre 0003D0: 63 74 20 73 79 6D 62 6F 6C 20 20 20 20 28 3C 2C ct symbol (<, 0003E0: 20 3E 20 6F 72 20 3D 29 20 6E 65 65 64 65 64 20 > or =) needed 0003F0: 74 6F 20 63 6F 6D 70 6C 65 74 65 74 68 69 73 20 to completethis 000400: 6E 75 6D 62 65 72 20 0D A7 73 65 6E 74 65 6E 63 number ..sentenc 000410: 65 3F 20 20 20 20 20 20 20 20 20 32 31 20 2B 20 e? 21 + 000420: 34 32 20 2B 20 31 36 20 3F 20 33 31 20 2B 20 31 42 + 16 ? 31 + 1 000430: 35 20 2B 20 33 33 20 20 1B 3D 1B 3C 1B 3E 1B 20 5 + 33 .=.<.>. 000440: 1B 37 00 48 6F 77 20 6D 61 6E 79 20 65 64 67 65 .7.How many edge 000450: 73 20 64 6F 65 73 20 61 20 73 71 75 61 72 65 20 s does a square 000460: 20 70 79 72 61 6D 69 64 20 68 61 76 65 3F 1B 38 pyramid have?.8 000470: 1B 35 1B 34 1B 31 32 1B 80 00 41 20 74 72 61 69 .5.4.12...A trai 000480: 6E 20 6C 65 61 76 65 73 20 4C 6F 6E 64 6F 6E 20 n leaves London 000490: 61 74 20 36 2E 35 30 20 61 6E 64 20 74 61 6B 65 at 6.50 and take 0004A0: 73 20 32 35 20 6D 69 6E 75 74 65 73 20 74 6F 20 s 25 minutes to 0004B0: 72 65 61 63 68 20 74 68 65 20 6E 65 78 74 20 73 reach the next s 0004C0: 74 61 74 69 6F 6E 2E 20 41 74 20 77 68 61 74 20 tation. At what 0004D0: 74 69 6D 65 77 69 6C 6C 20 69 74 20 61 72 72 69 timewill it arri 0004E0: 76 65 3F 1B 37 2E 31 35 1B 37 2E 32 35 1B 37 2E ve?.7.15.7.25.7. 0004F0: 31 30 1B 36 2E 31 30 1B 40 00 48 6F 77 20 6D 61 10.6.10.@.How ma 000500: 6E 79 20 67 72 61 6D 73 20 AE 52 61 72 65 20 74 ny grams .Rare t 000510: 68 65 72 65 20 69 6E 20 20 20 33 20 6B 69 6C 6F here in 3 kilo 000520: 67 72 61 6D 73 3F 1B 33 2C 30 30 30 1B 33 30 30 grams?.3,000.300 000530: 1B 33 30 1B 31 2C 35 30 30 1B 6C 00 53 65 70 74 .30.1,500.l.Sept 000540: 65 6D 62 65 72 2C 20 4A 75 6E 65 20 61 6E 64 20 ember, June and 000550: 4E 6F 76 65 6D 62 65 72 20 20 65 61 63 68 20 68 November each h 000560: 61 76 65 20 33 30 20 64 61 79 73 2E 20 57 68 69 ave 30 days. Whi 000570: 63 68 20 6F 74 68 65 72 6D 6F 6E 74 68 20 6F 6E ch othermonth on 000580: 6C 79 20 68 61 73 20 33 30 20 64 61 79 73 3F 1B ly has 30 days?. 000590: 41 70 72 69 6C 1B 4D 61 79 1B 41 75 67 75 73 74 April.May.August 0005A0: 1B 4A 75 6C 79 1B 37 00 48 6F 77 20 6D 61 6E 79 .July.7.How many 0005B0: 20 63 6F 72 6E 65 72 73 20 64 6F 65 73 20 61 20 corners does a 0005C0: 20 20 20 20 20 20 63 75 62 6F 69 64 20 68 61 76 cuboid hav 0005D0: 65 3F 1B 38 1B 36 1B 31 32 1B 31 30 1B 37 00 48 e?.8.6.12.10.7.H 0005E0: 6F 77 20 6D 61 6E 79 20 66 61 63 65 73 20 64 6F ow many faces do 0005F0: 65 73 20 61 20 73 71 75 61 72 65 20 20 70 79 72 es a square pyr 000600: 61 6D 69 64 20 68 61 76 65 3F 1B 54 98 35 1B 38 amid have?.T.5.8 000610: 1B 31 32 1B 34 1B 56 00 48 6F 77 20 6D 61 6E 79 .12.4.V.How many 000620: 20 6D 69 6E 75 74 65 73 20 61 72 65 20 74 68 65 minutes are the 000630: 72 65 20 20 20 20 62 65 74 77 65 65 6E 20 32 2E re between 2. 000640: 31 35 20 61 2E 6D 2E 20 61 6E 64 20 20 20 20 20 15 a.m. and 000650: 20 20 20 20 33 2E 35 35 20 61 2E 6D 2E 3F 1B 31 3.55 a.m.?.1 000660: 30 30 1B 34 30 1B 32 30 1B 38 35 1B 4B 00 48 6F 00.40.20.85.K.Ho 000670: 77 20 6D 75 63 68 20 69 73 20 74 68 65 20 37 20 w much is the 7 000680: 77 6F 72 74 68 20 69 6E 20 74 68 65 6E 75 6D 62 worth in thenumb 000690: 65 72 20 36 37 3F 1B 37 20 75 6E 69 74 73 1B 37 er 67?.7 units.7 0006A0: 20 74 65 6E 73 1B 37 30 20 75 6E 69 74 73 1B 37 tens.70 units.7 0006B0: 30 20 74 65 6E 73 1B 24 00 57 68 61 74 20 69 73 0 tens.$.What is 0006C0: 20 61 20 71 75 61 72 74 65 72 20 6F 66 20 31 32 a quarter of 12 0006D0: 3F 1B 33 1B 36 1B 39 1B 31 36 1B 37 00 48 6F 77 ?.3.6.9.16.7.How 0006E0: 20 6D 61 6E 79 20 63 6F 72 6E 65 72 73 20 64 6F many corners do 0006F0: 65 73 20 61 20 20 20 20 20 20 20 63 79 6C 69 6E es a cylin 000700: 64 65 72 20 68 61 76 65 3F 1B 30 1B 32 51 8A 1B der have?.0.2Q.. 000710: 35 1B 33 1B 3D 00 48 6F 77 20 6D 61 6E 79 20 63 5.3.=.How many c 000720: 65 6E 74 69 6D 65 74 72 65 73 20 61 72 65 20 74 entimetres are t 000730: 68 65 72 65 69 6E 20 32 20 6D 65 74 72 65 73 3F herein 2 metres? 000740: 1B 32 30 30 1B 32 30 1B 32 30 30 30 1B 35 30 30 .200.20.2000.500 000750: 1B 37 00 48 6F 77 20 6D 61 6E 79 20 70 65 6E 63 .7.How many penc 000760: 65 20 61 72 65 20 74 68 65 72 65 20 69 6E 20 20 e are there in 000770: 20 68 61 6C 66 20 61 20 60 31 3F 1B 35 30 1B 32 half a `1?.50.2 000780: 35 1B 34 30 1B 37 30 1B 55 00 48 6F 77 20 6D 61 5.40.70.U.How ma 000790: 6E 79 20 6D 69 6E 75 74 65 73 20 61 72 65 20 74 ny minutes are t 0007A0: 68 65 72 65 20 20 20 20 62 65 74 77 65 65 6E 20 here between 0007B0: 35 2E 34 30 20 70 2E 6D 2E 20 61 6E 64 20 20 20 5.40 p.m. and 0007C0: 20 20 20 20 20 20 36 2E 32 35 20 70 2E 6D 2E 3F 6.25 p.m.? 0007D0: 1B 34 35 1B 33 35 1B 35 30 1B 37 35 1B 1C 00 00 .45.35.50.75.... 0007E0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0007F0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000800: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 7E ...............~ 000810: 32 FF FF FF FF 2....
previoustop
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