Micro Maths (UK) (Face B) (1985) (2. Micro Maths 2) [Original] [TAPE] [COMPILATION] [EDUCATIF].cdt
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001070: 20 20 20 20 20 20 20 20 20 20 20 20 DE DF 20 20 ..
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001400: 20 FF 11 28 03 00 00 F2 29 EF 22 79 22 20 FC 20 ..(....)."y" .
001410: FF 11 28 03 00 00 F2 29 EF 22 79 65 73 22 20 FC ..(....)."yes" .
001420: 20 03 00 00 F2 EF 22 22 20 EB 20 0B 00 00 F4 EF ....."" . .....
001430: 0F 01 8A 01 A0 20 1E 11 00 00 0D 00 23 00 8A 01 ..... ......#...
001440: 86 01 85 20 22 22 00 06 00 24 00 CA 00 06 00 25 ... ""...$.....%
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0015C0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
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0015F0: 08 00 16 22 25 20 20 22 F4 FF 19 28 FF 0C 28 FF ..."% "...(..(.
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001680: EF FF 75 28 03 00 00 E9 2C FF 0E 28 03 00 00 E9 ..u(....,..(....
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0016C0: 01 BF 01 BF 01 A0 20 1E 2D 00 00 22 00 2C 00 BF ...... .-..".,..
0016D0: 03 00 00 69 B1 3B 01 03 00 00 E9 EF 03 00 00 E9 ...i.;..........
0016E0: F4 03 00 00 69 B1 01 A0 20 1E 27 00 00 06 00 2D ....i... .'....-
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001710: 01 0D 00 00 E2 EF 19 28 01 0D 00 00 F8 EF 0E 00 .......(........
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001730: 00 00 6C E1 EF E4 0D 00 00 F2 28 17 29 01 0D 00 ..l.......(.)...
001740: 00 6C E2 EF E4 0D 00 00 F2 28 17 29 00 3E 00 36 .l.......(.).>.6
001750: 00 0D 00 00 E5 EF E4 0D 00 00 F2 28 17 29 01 03 ...........(.)..
001760: 00 00 6C E1 EF FF 79 28 FF 19 28 0D 00 00 6C E1 ..l...y(..(...l.
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001780: 28 0D 00 00 6C E2 29 2C 0F 29 00 23 00 38 00 03 (...l.),.).#.8..
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001810: 15 00 40 00 0D 00 00 F9 EF FF 0C 28 FF 45 28 0F ..@........(.E(.
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001830: 0E 20 EB 20 03 00 00 66 EC EF 03 00 00 FA F4 22 . . ...f......."
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001890: 20 EB 20 03 00 00 66 EC EF 03 00 00 FA F4 22 50 . ...f......."P
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0018D0: 00 F8 00 4A 00 44 00 A1 20 0D 00 00 F9 EF 10 20 ...J.D.. ......
0018E0: EB 20 03 00 00 66 EC EF 03 00 00 FA F4 22 50 51 . ...f......."PQ
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001980: 00 00 FA F4 22 50 51 20 3D 20 35 20 78 20 41 42 ...."PQ = 5 x AB
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0019B0: 51 52 22 F4 03 00 00 F8 00 15 00 4A 00 9F 20 1E QR"........J.. .
0019C0: C8 00 01 03 00 00 F1 EF 03 00 00 66 EC 00 F9 00 ...........f....
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0023A0: 54 52 41 44 2C 43 6F 70 79 72 69 67 68 74 20 47 TRAD,Copyright G
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002400: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20
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00D210: 18 00 40 00 03 00 00 E8 EF 22 59 5E 2D 70 20 3D ..@......"Y^-p =
00D220: 20 31 2F 59 5E 70 22 00 26 00 42 00 0D 00 00 F8 1/Y^p".&.B.....
00D230: EF 17 01 03 00 00 E1 EF 22 31 2F 59 5E 22 F4 03 ........"1/Y^"..
00D240: 00 00 E5 01 03 00 00 EC EF 03 00 00 E1 00 15 00 ................
00D250: 46 00 A1 20 0B 00 00 F7 F2 0F 20 EB 20 A0 20 1E F.. ...... . . .
00D260: 50 00 00 13 00 48 00 03 00 00 F1 EF 03 00 00 E5 P....H..........
00D270: F4 22 5E 30 22 00 3E 00 4A 00 0D 00 00 E1 EF 0F ."^0".>.J.......
00D280: 01 0D 00 00 F8 EF 0E 01 03 00 00 E8 EF 22 61 6E ............."an
00D290: 79 20 6E 75 6D 62 65 72 20 74 6F 20 74 68 65 20 y number to the
00D2A0: 70 6F 77 65 72 20 6F 66 20 30 20 3D 20 31 20 54 power of 0 = 1 T
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00D2C0: 31 22 00 15 00 50 00 A1 20 0B 00 00 F7 F1 10 20 1"...P.. ......
00D2D0: EB 20 A0 20 1E 63 00 00 0B 00 51 00 0D 00 00 F8 . . .c....Q.....
00D2E0: EF 0E 00 29 00 52 00 A1 20 0B 00 00 F7 EF 10 20 ...).R.. ......
00D2F0: EB 20 03 00 00 F1 EF 03 00 00 E6 F4 22 5E 28 22 . .........."^("
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00E1B0: 00 9E 20 0D 00 00 EB EF 0F 20 EC 20 19 27 01 A1 .. ...... . .'..
00E1C0: 20 AC 28 03 00 00 66 EC 2C 0D 00 00 65 EC F5 0D .(...f.,...e...
00E1D0: 00 00 EB 2C 0F 29 EF 22 20 22 20 EB 20 03 00 00 ...,.)." " . ...
00E1E0: 66 EC EF FF 75 28 03 00 00 66 EC 2C 0D 00 00 65 f...u(...f.,...e
00E1F0: EC F5 0D 00 00 EB 29 F4 FF 16 28 0D 00 00 EB 29 ......)...(....)
00E200: F4 FF 79 28 03 00 00 66 EC 2C 0D 00 00 6C E6 F5 ..y(...f.,...l..
00E210: 0D 00 00 65 EC F4 0D 00 00 EB 29 01 0D 00 00 6C ...e......)....l
00E220: E6 EF 0D 00 00 6C E6 F4 0D 00 00 EB 01 51 D7 A0 .....l.......Q..
00E230: 20 1E 31 00 00 06 00 30 00 B0 00 06 00 31 00 B0 .1....0.....1..
00E240: 00 06 00 32 00 C9 00 69 00 33 00 03 00 00 EC EF ...2...i.3......
00E250: 22 22 01 03 00 00 ED EF 22 22 01 03 00 00 EE EF ""......""......
00E260: 22 22 01 0D 00 00 E2 EF 19 28 01 0D 00 00 F8 EF "".......(......
00E270: 1F CD CC CC 4C 7D 01 9E 20 0D 00 00 E9 EF 0F 20 ....L}.. ......
00E280: EC 20 12 01 0D 00 00 E4 28 0D 00 00 E9 29 EF 0E . ......(....)..
00E290: 01 03 00 00 E4 28 0D 00 00 E9 29 EF 22 22 01 B0 .....(....).""..
00E2A0: 01 0D 00 00 E1 EF 0E 01 03 00 00 E1 EF 22 22 00 ............."".
00E2B0: 11 00 34 00 9E 20 0D 00 00 E9 EF 0F 20 EC 20 12 ..4.. ...... . .
00E2C0: 00 47 00 36 00 0D 00 00 E4 28 0D 00 00 E9 29 EF .G.6.....(....).
00E2D0: FF 0C 28 FF 45 28 0F 29 F6 17 F4 0F 29 01 A1 20 ..(.E(.)....)..
00E2E0: FF 45 28 0F 29 20 EE 20 1F 00 00 00 00 80 20 EB .E(.) . ...... .
00E2F0: 20 0D 00 00 E4 28 0D 00 00 E9 29 EF F5 0D 00 00 ....(....).....
00E300: E4 28 0D 00 00 E9 29 00 34 00 38 00 03 00 00 E4 .(....).4.8.....
00E310: 28 0D 00 00 E9 29 EF FF 79 28 FF 19 28 0D 00 00 (....)..y(..(...
00E320: E4 28 0D 00 00 E9 29 29 2C E4 0D 00 00 F3 28 71 .(....)),.....(q
00E330: 1C 0D 00 00 E4 28 0D 00 00 E9 29 29 29 00 37 00 .....(....))).7.
00E340: 39 00 B0 01 0D 00 00 E5 EF FF 0C 28 FF 45 28 0F 9..........(.E(.
00E350: 29 F6 16 F4 10 29 01 03 00 00 E5 EF FF 79 28 FF )....).......y(.
00E360: 19 28 0D 00 00 E5 29 2C E4 0D 00 00 F3 28 0D 00 .(....),.....(..
00E370: 00 E5 29 29 00 55 00 3A 00 0D 00 00 6C B1 EF FF ..)).U.:....l...
00E380: 0E 28 03 00 00 E4 28 0F 29 29 01 03 00 00 FA EF .(....(.))......
00E390: 22 49 66 20 55 20 3D 20 28 22 F4 03 00 00 E4 28 "If U = (".....(
00E3A0: 0F 29 F4 22 29 22 F4 FF 16 28 19 26 F5 0D 00 00 .).")"...(.&....
00E3B0: 6C B1 29 F4 22 28 22 F4 03 00 00 E4 28 10 29 F4 l.)."(".....(.).
00E3C0: 22 29 20 74 68 65 6E 20 22 00 15 00 3B 00 0B 00 ") then "...;...
00E3D0: 00 F7 EF FF 0C 28 FF 45 28 0F 29 F6 11 29 00 15 .....(.E(.)..)..
00E3E0: 00 3C 00 A1 20 0B 00 00 F7 F2 0E 20 EB 20 A0 20 .<.. ...... . .
00E3F0: 1E 48 00 00 3A 00 3D 00 0D 00 00 6C B1 EF FF 0E .H..:.=....l....
00E400: 28 03 00 00 E4 28 0F 29 29 01 0D 00 00 6C B3 EF (....(.))....l..
00E410: FF 0E 28 03 00 00 E4 28 11 29 29 01 0D 00 00 6C ..(....(.))....l
00E420: B2 EF FF 0E 28 03 00 00 E4 28 10 29 29 00 89 00 ....(....(.))...
00E430: 3E 0D 58 00 03 00 00 F1 EF 22 49 66 20 55 20 3D >.X......"If U =
00E440: 20 28 22 F4 03 00 00 E4 28 0F 29 F4 22 29 20 61 (".....(.).") a
00E450: 6E 64 20 56 20 3D 20 28 22 F4 03 00 00 E4 28 11 nd V = (".....(.
00E460: 29 F4 22 29 22 F4 FF 16 28 19 1B F5 0D 00 00 6C ).")"...(......l
00E470: B1 F5 0D 00 00 6C B3 29 F4 22 28 22 F4 03 00 00 .....l.)."("....
00E480: E4 28 10 29 F4 22 29 22 F4 FF 16 28 17 F4 0D 00 .(.).")"...(....
00E490: 00 6C B1 F5 0D 00 00 6C B2 29 F4 22 28 22 F4 03 .l.....l.)."("..
00E4A0: 00 00 E4 28 12 29 F4 22 29 20 74 68 65 6E 20 55 ...(.).") then U
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00E4D0: 73 2C 20 61 64 64 20 74 68 65 69 72 20 63 6F 6D s, add their com
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00E4F0: 6C 79 22 00 7E 00 42 00 03 00 00 72 B1 EF FF 79 ly".~.B....r...y
00E500: 28 FF 19 28 0D 00 00 E4 28 0F 29 F4 0D 00 00 E4 (..(....(.).....
00E510: 28 11 29 29 2C E4 0D 00 00 F3 28 0D 00 00 E4 28 (.)),.....(....(
00E520: 0F 29 F4 0D 00 00 E4 28 11 29 29 29 01 0D 00 00 .).....(.)))....
00E530: 6C F2 EF 57 6F FF 0E 28 03 00 00 72 B1 29 01 03 l..Wo..(...r.)..
00E540: 00 00 72 B2 EF FF 79 28 FF 19 28 0D 00 00 E4 28 ..r...y(..(....(
00E550: 10 29 F4 0D 00 00 E4 28 12 29 29 2C E4 0D 00 00 .).....(.)),....
00E560: F3 28 0D 00 00 E4 28 10 29 F4 0D 00 00 E4 28 12 .(....(.).....(.
00E570: 29 29 29 00 69 00 44 00 03 00 00 E1 EF 22 28 22 ))).i.D......"("
00E580: F4 03 00 00 72 B1 F4 22 29 22 F4 FF 16 28 19 26 ....r..")"...(.&
00E590: F5 0D 00 00 6C F2 29 F4 22 28 22 F4 03 00 00 72 ....l.)."("....r
00E5A0: B2 F4 22 29 22 01 03 00 00 EC EF 03 00 00 E1 01 ..")"...........
00E5B0: 03 00 00 ED EF 22 61 73 20 22 F4 03 00 00 E4 28 ....."as ".....(
00E5C0: 0F 29 F4 22 20 2B 20 22 F4 03 00 00 E4 28 11 29 .)." + ".....(.)
00E5D0: F4 22 20 3D 20 22 F4 03 00 00 72 B1 00 39 00 46 ." = "....r..9.F
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00E5F0: E4 28 10 29 F4 22 20 2B 20 22 F4 03 00 00 E4 28 .(.)." + ".....(
00E600: 12 29 F4 22 20 3D 20 22 F4 03 00 00 72 B2 01 0D .)." = "....r...
00E610: 00 00 F8 EF 17 00 15 00 48 00 A1 20 0B 00 00 F7 ........H.. ....
00E620: F2 0F 20 EB 20 A0 20 1E 56 00 00 17 00 4A 00 03 .. . . .V....J..
00E630: 00 00 F1 EF 03 B3 47 00 00 FA F4 03 00 00 E5 F4 ......G.........
00E640: 22 55 22 00 8B 00 4C 00 03 00 00 E8 EF 22 77 68 "U"...L......"wh
00E650: 65 6E 20 6D 75 6C 74 69 70 6C 79 69 6E 67 20 61 en multiplying a
00E660: 20 73 63 61 6C 61 72 20 71 75 61 6E 74 69 74 79 scalar quantity
00E670: 20 20 20 28 69 2E 65 2E 20 61 6E 20 6F 72 64 69 (i.e. an ordi
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00E690: 61 20 76 65 63 74 6F 72 20 20 20 6D 75 6C 74 69 a vector multi
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00E6C0: 20 62 79 74 68 65 20 73 63 61 6C 61 72 22 00 4A bythe scalar".J
00E6D0: 00 4E 00 03 00 00 72 B1 EF FF 79 28 FF 19 28 0D .N....r...y(..(.
00E6E0: 00 00 E5 F6 0D 00 00 E4 28 0F 29 29 2C E4 0D 00 ........(.)),...
00E6F0: 00 F3 28 0D 00 00 E5 F6 0D 00 00 E4 28 0F 29 29 ..(.........(.))
00E700: 29 01 0D 00 00 6C F2 EF FF 0E 28 03 00 00 72 B1 )....l....(...r.
00E710: 29 01 0D 00 00 F8 EF 17 00 55 00 50 00 03 00 00 )........U.P....
00E720: E1 EF 22 28 22 F4 03 00 00 72 B1 F4 22 29 22 F4 .."("....r..")".
00E730: FF 16 28 19 26 F5 0D 71 85 FF FF FF FF 11 9C 09 ..(.&..q........
00E740: B3 04 B3 04 0A 05 53 09 00 10 08 11 00 07 01 00 ......S.........
00E750: 2C 4C 43 4C 31 35 30 43 00 00 00 00 00 00 00 00 ,LCL150C........
00E760: 00 03 FF 00 9B 05 70 11 00 9B 15 00 00 00 00 00 ......p.........
00E770: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
00E780: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
00E790: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
00E7A0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
00E7B0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
00E7C0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
00E7D0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
00E7E0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
00E7F0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
00E800: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
00E810: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
00E820: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
00E830: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
00E840: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
00E850: 00 4A 47 FF FF FF FF 11 9A 09 EA 04 7C 04 2C 05 .JG.........|.,.
00E860: 37 09 00 10 08 AA 1E 11 06 00 16 00 00 6C F2 29 7............l.)
00E870: F4 22 28 22 F4 FF 79 28 FF 19 28 0D 00 00 E5 F6 ."("..y(..(.....
00E880: 0D 00 00 E4 28 10 29 29 2C E4 0D 00 00 F3 28 0D ....(.)),.....(.
00E890: 00 00 E5 F6 0D 00 00 E4 28 10 29 29 29 F4 22 29 ........(.))).")
00E8A0: 22 00 3F 00 52 00 0D 00 00 F8 EF 17 01 03 00 00 ".?.R...........
00E8B0: EC EF 03 00 00 E1 01 03 00 00 ED EF 22 61 73 20 ............"as
00E8C0: 22 F4 03 00 00 E5 F4 22 20 78 20 22 F4 03 00 00 "......" x "....
00E8D0: E4 28 0F 29 F4 22 20 3D 20 22 F4 03 00 00 72 B1 .(.)." = "....r.
00E8E0: 00 52 00 54 00 03 00 00 EE EF 22 61 6E 64 20 22 .R.T......"and "
00E8F0: F4 03 00 00 E5 F4 22 20 78 20 22 F4 03 00 00 E4 ......" x ".....
00E900: 28 10 29 F4 22 20 3D 20 22 F4 FF 79 28 FF 19 28 (.)." = "..y(..(
00E910: 0D 00 00 E5 F6 0D 00 00 E4 28 10 29 29 2C E4 0D .........(.)),..
00E920: 00 00 F3 28 0D 00 00 E5 F6 0D 00 00 E4 28 10 29 ...(.........(.)
00E930: 29 29 00 15 00 56 00 A1 20 0B 00 00 F7 F2 10 20 ))...V.. ......
00E940: EB 20 A0 20 1E 63 00 00 21 00 58 00 03 00 00 F1 . . .c..!.X.....
00E950: EF 03 00 00 FA F4 22 74 68 65 20 6D 6F 64 75 6C ......"the modul
00E960: 75 73 20 6F 66 20 55 22 00 71 00 79 82 5C 00 03 us of U".q.y.\..
00E970: 00 00 E8 EF 22 74 68 65 20 6D 6F 64 75 6C 75 73 ...."the modulus
00E980: 20 6F 66 20 61 20 76 65 63 74 6F 72 20 69 73 20 of a vector is
00E990: 74 68 65 20 73 71 75 61 72 65 72 6F 6F 74 20 6F the squareroot o
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00E9B0: 72 65 20 41 20 61 6E 64 20 42 20 61 72 65 20 74 re A and B are t
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00E9D0: 74 68 65 20 76 65 63 74 6F 72 22 00 49 00 60 00 the vector".I.`.
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00E9F0: 0F 29 F8 10 F4 0D 00 00 E4 28 10 29 F8 10 29 F6 .).......(.)..).
00EA00: 19 64 29 F7 19 64 01 03 00 00 E1 EF FF 79 28 FF .d)..d.......y(.
00EA10: 19 28 0D 00 00 E1 29 2C E4 0D 00 00 F3 28 0D 00 .(....),.....(..
00EA20: 00 E1 29 29 00 2A 01 62 00 03 00 00 EC EF 03 00 ..)).*.b........
00EA30: 00 E1 01 03 00 00 ED EF 22 61 73 20 28 22 F4 03 ........"as ("..
00EA40: 00 00 E4 28 0F 29 F4 22 29 5E 32 20 3D 20 22 F4 ...(.).")^2 = ".
00EA50: FF 79 28 FF 19 28 0D 00 00 E4 28 0F 29 F6 0D 00 .y(..(....(.)...
00EA60: 00 E4 28 0F 29 29 2C E4 0D 00 00 F3 28 FC F1 0D ..(.)),.....(...
00EA70: 00 00 E4 28 0F 29 F6 0D 00 00 E4 28 0F 29 29 29 ...(.).....(.)))
00EA80: F4 22 20 61 6E 64 20 28 22 F4 03 00 00 E4 28 10 ." and (".....(.
00EA90: 29 F4 22 29 5E 32 20 3D 20 22 F4 FF 79 28 FF 19 ).")^2 = "..y(..
00EAA0: 28 0D 00 00 E4 28 10 29 F6 0D 00 00 E4 28 10 29 (....(.).....(.)
00EAB0: 29 2C E4 0D 00 00 F3 28 0D 00 00 E4 28 10 29 F6 ),.....(....(.).
00EAC0: 0D 00 00 E4 28 10 29 29 29 01 03 00 00 EE EF 22 ....(.)))......"
00EAD0: 73 6F 20 73 71 75 61 72 65 20 72 6F 6F 74 20 28 so square root (
00EAE0: 22 F4 FF 79 28 FF 19 28 0D 00 00 E4 28 0F 29 F6 "..y(..(....(.).
00EAF0: 0D 00 00 E4 28 0F 29 29 2C E4 0D 00 00 F3 28 0D ....(.)),.....(.
00EB00: 00 00 E4 28 0F 29 F6 0D 00 00 E4 28 0F 29 29 29 ...(.).....(.)))
00EB10: F4 22 20 2B 22 F4 FF 79 28 FF 19 28 0D 00 00 E4 ." +"..y(..(....
00EB20: 28 10 29 F6 0D 00 00 E4 28 10 29 29 2C E4 0D 00 (.).....(.)),...
00EB30: 00 F3 28 0D 00 00 E4 28 10 29 F6 0D 00 00 E4 28 ..(....(.).....(
00EB40: 10 29 29 29 F4 22 29 20 3D 20 22 F4 03 00 00 E1 .))).") = ".....
00EB50: 00 06 00 63 00 C9 00 5B 00 64 00 A1 20 0B 00 00 ...c...[.d.. ...
00EB60: F7 EF 0E 20 EB 20 0D 00 00 64 31 E1 EF 0D 00 FC ... . ...d1.....
00EB70: 66 00 E4 28 11 29 01 0D 00 00 64 31 E2 EF 0D 00 f..(.)....d1....
00EB80: 00 E4 28 0F 29 F4 0D 00 00 E4 28 11 29 01 0D 00 ..(.).....(.)...
00EB90: 00 64 32 E1 EF 0D 00 00 E4 28 12 29 01 0D 00 00 .d2......(.)....
00EBA0: 64 32 E2 EF 0D 00 00 E4 28 10 29 F4 0D 00 00 E4 d2......(.).....
00EBB0: 28 12 29 00 49 00 66 00 A1 20 0B 00 00 F7 EF 0F (.).I.f.. ......
00EBC0: 20 EB 20 0D 00 00 64 31 E1 EF 0D 00 00 E5 F6 0D . ...d1........
00EBD0: 00 00 E4 28 0F 29 01 0D 00 00 64 32 E1 EF 0D 00 ...(.)....d2....
00EBE0: 00 E5 F6 0D 00 00 E4 28 10 29 01 0D 00 00 64 31 .......(.)....d1
00EBF0: E2 EF 0E 01 0D 00 00 64 32 E2 EF 0E 00 33 00 67 .......d2....3.g
00EC00: 00 A1 20 0B 00 00 F7 EF 10 20 EB 20 0D 00 00 64 .. ...... . ...d
00EC10: 31 E1 EF 0E 01 0D 00 00 64 32 E1 EF 0E 01 0D 00 1.......d2......
00EC20: 00 64 31 E2 EF 0E 01 0D 00 00 64 32 E2 EF 0E 00 .d1.......d2....
00EC30: EF 00 6A 00 0D 00 00 62 B1 EF FF 76 28 0D 00 00 ..j....b...v(...
00EC40: E4 28 0F 29 2C 0D 00 00 64 31 E1 2C 0D 00 00 64 .(.),...d1.,...d
00EC50: 31 E2 2C 0E 29 01 0D 00 00 73 B1 EF FF 77 28 0D 1.,.)....s...w(.
00EC60: 00 00 E4 28 0F 29 2C 0D 00 00 64 31 E1 2C 0D 00 ...(.),...d1.,..
00EC70: 00 C2 78 64 31 E2 2C 0E 29 01 0D 00 00 62 B2 EF ..xd1.,.)....b..
00EC80: FF 76 28 0D 00 00 E4 28 10 29 2C 0D 00 00 64 32 .v(....(.),...d2
00EC90: E1 2C 0D 00 00 64 32 E2 2C 0E 29 01 0D 00 00 73 .,...d2.,.)....s
00ECA0: B2 EF FF 77 28 0D 00 00 E4 28 10 29 2C 0D 00 00 ...w(....(.),...
00ECB0: 64 32 E1 2C 0D 00 00 64 32 E2 2C 0E 29 01 0D 00 d2.,...d2.,.)...
00ECC0: 00 73 63 B1 EF FF 0C 28 1A 60 02 F7 28 0D 00 00 .sc....(.`..(...
00ECD0: 62 B1 F5 0D 00 00 73 B1 29 29 01 0D 00 00 73 63 b.....s.))....sc
00ECE0: B2 EF FF 0C 28 19 C8 F7 28 0D 00 00 62 B2 F5 0D ....(...(...b...
00ECF0: 00 00 73 B2 29 29 01 B8 20 FF 00 28 0D 00 00 73 ..s.)).. ..(...s
00ED00: B1 F6 0D 00 00 73 63 B1 29 F4 19 10 2C FF 00 28 .....sc.)...,..(
00ED10: 0D 00 00 73 B2 F6 0D 00 00 73 63 B2 29 F4 19 10 ...s.....sc.)...
00ED20: 00 48 00 6C 00 AE 20 0E 2C 0D 00 00 73 B2 F6 0D .H.l.. .,...s...
00ED30: 00 00 73 63 B2 01 94 20 0E 2C 0D 00 00 62 B2 F6 ..sc... .,...b..
00ED40: 0D 00 00 73 63 B2 01 AE 20 0D 00 00 73 B1 F6 0D ...sc... ...s...
00ED50: 00 00 73 63 B1 2C 0E 01 94 20 0D 00 00 62 B1 F6 ..sc.,... ...b..
00ED60: 0D 00 00 73 63 B1 2C 0E 00 06 00 6D 00 D0 00 30 ...sc.,....m...0
00ED70: 00 6E 00 4A 4E AE 20 0E 2C 0E 01 94 20 0D 00 00 .n.JN. .,... ...
00ED80: E4 28 0F 29 F6 0D 00 00 73 63 B1 2C 0D 00 00 E4 .(.)....sc.,....
00ED90: 28 10 29 F6 0D 00 00 73 63 B2 01 BF 22 55 22 3B (.)....sc..."U";
00EDA0: 00 39 00 78 00 AE 20 0E 2C 0E 01 94 20 0D 00 00 .9.x.. .,... ...
00EDB0: 64 31 E1 F6 0D 00 00 73 63 B1 2C 0D 00 00 64 32 d1.....sc.,...d2
00EDC0: E1 F6 0D 00 00 73 63 B2 01 A1 20 0B 00 00 F7 EF .....sc... .....
00EDD0: 0E 20 EB 20 BF 22 56 22 3B 00 28 00 82 00 AE 20 . . ."V";.(....
00EDE0: 0E 2C 0E 01 94 20 0D 00 00 64 31 E2 F6 0D 00 00 .,... ...d1.....
00EDF0: 73 63 B1 2C 0D 00 00 64 32 E2 F6 0D 00 00 73 63 sc.,...d2.....sc
00EE00: B2 00 06 00 84 00 D1 00 06 00 8C 00 C9 00 00 00 ................
00EE10: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
00EE20: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
00EE30: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
00EE40: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
00EE50: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
00EE60: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
00EE70: 00 00 00 00 00 35 A8 FF FF FF FF 11 87 09 B3 04 .....5..........
00EE80: B3 04 FF 04 52 09 00 10 08 12 00 07 01 00 2C 4C ....R.........,L
00EE90: 43 4C 31 36 30 42 00 00 00 00 00 00 00 00 00 01 CL160B..........
00EEA0: 00 00 00 08 70 01 FF 8E 16 00 00 00 00 00 00 00 ....p...........
00EEB0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
00EEC0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
00EED0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
00EEE0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
00EEF0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
00EF00: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
00EF10: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
00EF20: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
00EF30: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
00EF40: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
00EF50: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
00EF60: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
00EF70: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
00EF80: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 5E ...............^
00EF90: BD FF FF FF FF 11 85 09 B3 04 B3 04 2E 05 31 09 ..............1.
00EFA0: 00 10 08 89 0A 15 08 00 16 1B 00 01 00 A1 20 0D .............. .
00EFB0: 00 00 74 E5 EF 0E 20 EB 20 A0 20 1E 03 00 20 01 ..t... . . ... .
00EFC0: 97 20 CE 00 06 00 02 00 C9 00 4A 00 03 00 C5 20 . ........J....
00EFD0: 4C 43 4C 31 36 30 42 20 20 41 4D 53 54 52 41 44 LCL160B AMSTRAD
00EFE0: 2C 43 6F 70 79 72 69 67 68 74 20 47 2E 4C 75 64 ,Copyright G.Lud
00EFF0: 69 6E 73 6B 69 20 31 39 38 31 2C 61 64 61 70 74 inski 1981,adapt
00F000: 65 64 20 66 6F 72 20 41 6D 73 74 72 61 64 20 31 ed for Amstrad 1
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00F020: 05 00 B2 20 9C 20 A0 20 1E 23 00 01 03 00 00 F3 ... . . .#......
00F030: EF 22 20 20 20 20 20 20 20 20 20 20 20 20 20 20 ."
00F040: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20
00F050: 20 20 20 20 20 20 20 20 20 20 22 00 23 00 06 00 ".#...
00F060: 8D 20 E4 0D 00 00 F2 28 0D 00 00 E9 29 EF FF 0C . .....(....)...
00F070: 28 0D 00 00 E9 F6 FF 45 28 0F 29 F4 0F 29 00 28 (......E(.)..).(
00F080: 00 07 00 8D 20 E4 0D 00 00 F3 28 0D 00 00 E9 29 .... .....(....)
00F090: EF FF 0E 28 FF 19 28 0D 00 00 E9 29 29 F4 28 0D ...(..(....)).(.
00F0A0: 00 00 E9 F0 0E 29 00 34 00 DB FD 08 00 82 20 0E .....).4...... .
00F0B0: 01 A2 20 0E 2C 0E 01 A2 20 0F 2C 19 0B 01 A2 20 .. .,... .,....
00F0C0: 10 2C 14 01 A2 20 11 2C 19 18 01 BA 20 0E 01 BB .,... .,.... ...
00F0D0: 20 0F 01 8A 01 BB 20 10 01 BA 20 11 00 80 00 09 ..... ... .....
00F0E0: 00 03 00 00 62 F8 EF FF 03 28 19 87 29 F4 FF 7B ....b....(..)..{
00F0F0: 28 19 26 2C FF 03 28 19 83 29 29 F4 FF 03 28 19 (.&,..(..))...(.
00F100: 8B 29 F4 FF 03 28 19 85 29 F4 FF 16 28 19 26 29 .)...(..)...(.&)
00F110: F4 FF 03 28 19 8A 29 F4 FF 03 28 19 85 29 F4 FF ...(..)...(..)..
00F120: 16 28 19 26 29 F4 FF 03 28 19 8A 29 F4 FF 03 28 .(.&)...(..)...(
00F130: 19 8D 29 F4 FF 7B 28 19 26 2C FF 03 28 19 8C 29 ..)..{(.&,..(..)
00F140: 29 F4 FF 03 28 19 8E 29 F4 FF 03 28 19 0B 29 F4 )...(..)...(..).
00F150: FF 03 28 19 0B 29 F4 FF 03 28 17 29 00 4A 00 0A ..(..)...(.).J..
00F160: 00 A9 20 11 2C 0F 01 BF 20 03 00 00 F3 F4 22 20 .. .,... ....."
00F170: 20 20 4D 61 74 72 69 63 65 73 20 28 4D 69 63 72 Matrices (Micr
00F180: 6F 20 4D 61 74 68 73 29 20 20 22 F4 FF 03 28 19 o Maths) "...(.
00F190: A4 29 F4 22 20 4C 43 4C 20 31 39 38 31 20 20 20 .)." LCL 1981
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00F1F0: A3 20 22 48 65 6C 6C 6F 2C 20 77 68 61 74 20 69 £ "Hello, what i
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00F350: 28 29 F4 03 00 00 F3 3B 01 BA 20 0E 01 BB 20 0F ().....;.. ... .
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00F4E0: 00 4E 41 CD 29 EF 22 4E 4F 20 53 4F 55 4E 44 22 .NA.)."NO SOUND"
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010010: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20
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0102A0: E1 28 12 29 F6 0D 00 00 E2 28 12 29 29 01 03 00 .(.).....(.))...
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0102C0: 2C E4 0D 00 00 F3 28 FF 1D 28 03 00 00 E3 28 12 ,.....(..(....(.
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0102E0: 22 F4 03 00 00 E3 28 0F 29 F4 22 20 22 F4 03 00 ".....(.)." "...
0102F0: 00 E3 28 10 29 F4 22 29 22 F4 FF 16 28 19 25 F5 ..(.).")"...(.%.
010300: 0D 00 00 6C B1 F5 0D 00 00 6C B2 29 F4 22 28 22 ...l.....l.)."("
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0103C0: 00 E2 28 11 29 F4 22 29 3D 22 F4 03 00 00 E3 28 ..(.).")=".....(
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010400: 28 10 29 F4 22 29 2B 28 22 F4 03 00 00 E1 28 10 (.).")+(".....(.
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010420: 3D 22 F4 03 00 00 E3 28 10 29 F4 22 20 65 74 A7 =".....(.)." et.
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010440: 10 20 EB 20 A0 20 1E 63 00 00 A8 00 59 00 0D 00 . . . .c....Y...
010450: 00 E1 28 10 29 EF 0F 01 0D 00 00 E1 28 11 29 EF ..(.).......(.).
010460: 0D 00 00 E1 28 0F 29 F6 0D 00 00 E1 28 12 29 F4 ....(.).....(.).
010470: 28 F5 0F 29 F8 E4 0D 00 00 F2 28 10 29 01 03 00 (..)......(.)...
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010490: 28 10 29 29 2C E4 0D 00 00 F3 28 0D 00 00 E1 28 (.)),.....(....(
0104A0: 10 29 29 29 01 03 00 00 E1 28 11 29 EF FF 79 28 .))).....(.)..y(
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010590: 20 20 20 20 20 20 20 20 20 20 20 20 20 9A 9A 9A ...
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0105D0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20
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010600: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20
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010620: 20 20 20 20 20 20 20 20 20 20 20 28 61 64 2D 62 (ad-b
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010670: 0D 00 00 72 B1 01 0D 00 00 E3 28 10 29 EF F5 0D ...r......(.)...
010680: 00 00 E1 28 10 29 F7 0D 00 00 72 B1 01 0D 00 00 ...(.)....r.....
010690: E3 28 11 29 EF F5 0D 00 00 E1 28 11 29 F7 0D 00 .(.)......(.)...
0106A0: 00 72 B1 01 0D 00 00 E3 28 12 29 EF 0D 00 00 E1 .r......(.).....
0106B0: 28 0F 29 F7 0D 00 00 72 B1 01 9E 20 0D 00 00 E9 (.)....r... ....
0106C0: EF 0F 20 EC 20 12 01 03 00 00 E3 28 0D 00 00 E9 .. . ......(....
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0106E0: E9 29 29 F6 FF 0C 28 FF 00 28 0D 00 00 E3 28 0D .))...(..(....(.
0106F0: 00 00 E9 29 29 29 29 01 03 00 00 E3 28 0D 00 00 ...)))).....(...
010700: E9 29 EF FF 79 28 03 00 00 E3 28 0D 00 00 E9 29 .)..y(....(....)
010710: 2C E4 0D 00 00 F3 28 FF 1D 28 03 00 00 E3 28 0D ,.....(..(....(.
010720: 00 00 E9 29 29 29 29 01 B0 00 2C 00 5F 00 0D 00 ...))))...,._...
010730: 00 EC 28 0F 29 82 12 EF FF 0E 28 03 00 00 E3 28 ..(.).....(....(
010740: 0F 29 29 01 0D 00 00 EC 28 10 29 EF FF 0E 28 03 .)).....(.)...(.
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010790: 10 29 29 F4 22 28 22 F4 03 00 00 E3 28 11 29 F4 .))."(".....(.).
0107A0: 22 20 22 F4 03 00 00 E3 28 12 29 F4 22 29 22 00 " ".....(.).")".
0107B0: 83 00 61 00 03 00 00 EC EF 03 00 00 E1 01 03 00 ..a.............
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0107F0: 12 29 F4 22 29 20 2D 20 28 22 F4 03 00 00 E1 28 .).") - (".....(
010800: 10 29 F4 22 20 78 20 22 F4 03 00 00 E1 28 11 29 .)." x ".....(.)
010810: F4 22 29 20 3D 20 22 F4 FF 79 28 FF 19 28 0D 00 .") = "..y(..(..
010820: 00 72 B1 29 2C E4 0D 00 00 F3 28 0D 00 00 72 B1 .r.),.....(...r.
010830: 29 29 00 8A 00 62 00 0F 09 03 00 00 EE EF 22 73 ))...b........"s
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010860: F4 22 20 20 20 20 20 20 20 20 20 20 20 20 20 20 ."
010870: 20 73 6F 20 64 20 2F 20 64 65 74 65 72 6D 69 6E so d / determin
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010890: 22 20 2F 20 22 F4 FF 79 28 FF 19 28 0D 00 00 72 " / "..y(..(...r
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0108B0: F4 22 20 3D 20 22 F4 03 00 00 E3 28 0F 29 00 06 ." = ".....(.)..
0108C0: 00 63 00 C9 00 00 00 00 00 00 00 00 00 00 00 00 .c..............
0108D0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
0108E0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
0108F0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
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010970: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
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010A80: 03 00 20 01 97 20 CE 00 06 00 02 00 C9 00 0E 00 .. .. ..........
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010B10: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20
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010B90: A2 20 10 2C 14 01 A2 20 11 2C 19 18 01 BA 20 0E . .,... .,.... .
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010BF0: F4 FF 7B 28 19 26 2C FF 03 28 19 8C 29 29 F4 FF ..{(.&,..(..))..
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010D90: 00 27 00 11 00 0B 00 00 D4 EF 0F 01 03 00 00 C9 .'..............
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0110A0: 11 28 03 00 00 F2 29 20 F2 20 22 6E 6F 22 20 FA .(....) . "no" .
0110B0: 20 03 00 00 F2 F2 22 22 20 EB 20 A0 20 1E 1E 00 ....."" . . ...
0110C0: 00 3F 00 22 00 A1 20 FF 11 28 03 00 00 F2 29 EF .?.".. ..(....).
0110D0: 22 79 22 20 FC 20 FF 11 28 03 00 00 F2 29 EF 22 "y" . ..(....)."
0110E0: 79 65 73 22 20 FC 20 03 00 00 F2 EF 22 22 20 EB yes" . ....."" .
0110F0: 20 0B 00 00 F4 EF 0F 01 8A 01 A0 20 1E 11 00 00 .......... ....
011100: 0D 00 23 00 8A 01 86 01 85 20 22 22 00 06 00 24 ..#...... ""...$
011110: 00 CA 00 06 00 25 00 C5 00 0C 00 26 00 03 00 00 .....%.....&....
011120: E9 EF 22 22 00 0D 00 27 00 03 00 00 69 B1 EF FF ..""...'....i...
011130: 43 00 93 00 28 00 0D 00 00 78 F0 EF FF 78 28 23 C...(....x...x(#
011140: 0E 29 01 0D 00 00 79 F0 EF FF 7F 28 23 0E 29 01 .)....y....(#.).
011150: A9 20 0F 2C 0F 01 BB 20 11 01 BF 20 FF 75 28 22 . .,... ... .u("
011160: 54 65 73 74 22 F4 FF 19 28 0B 00 00 74 E5 29 F4 Test"...(...t.).
011170: 22 20 20 20 53 63 6F 72 65 93 CC 22 F4 FF 19 28 " Score.."...(
011180: 0B 00 00 6D EB 29 F4 22 25 20 20 22 F4 FF 19 28 ...m.)."% "...(
011190: FF 0C 28 FF 46 F7 1A 2C 01 29 F5 0B 00 00 74 E4 ..(.F..,.)....t.
0111A0: 29 F4 22 20 73 65 63 73 2E 20 22 F4 03 00 00 D3 )." secs. ".....
0111B0: 2C 19 28 29 01 BB 20 0F 01 A9 20 0D 00 00 78 F0 ,.().. ... ...x.
0111C0: 2C 0D 00 00 79 F0 00 17 00 29 00 A1 20 03 00 00 ,...y....).. ...
0111D0: 69 B1 EF 22 22 20 EB 20 A0 20 1E 27 00 00 51 00 i.."" . . .'..Q.
0111E0: 2A 00 A1 20 03 00 00 69 B1 EF FF 03 28 19 7F 29 *.. ...i....(..)
0111F0: 20 FA 20 FF 78 28 23 0E 29 20 EE 20 10 20 EB 20 . .x(#.) . . .
011200: BF 20 FF 03 28 16 29 3B FF 03 28 19 10 29 3B 01 . ..(.);..(..);.
011210: 03 00 00 E9 EF FF 75 28 03 00 00 E9 2C FF 0E 28 ......u(....,..(
011220: 03 00 00 E9 29 F5 0F 29 01 A0 20 1E 27 00 00 30 ....)..).. .'..0
011230: 00 2B 00 A1 20 03 00 00 69 B1 EF FF 03 28 19 0D .+.. ...i....(..
011240: 29 20 FC 20 FF 0E 28 03 00 00 E9 29 20 EE 19 25 ) . ..(....) ..%
011250: 20 EB 20 BF 01 BF 01 BF 01 A0 20 1E 2D 00 00 22 . ....... .-.."
011260: 00 2C 00 BF 03 00 00 69 B1 3B 01 03 00 00 E9 EF .,.....i.;......
011270: 03 00 00 E9 F4 03 00 00 69 B1 01 4D E5 FF FF FF ........i..M....
011280: FF 11 9F 09 21 05 7C 04 0E 05 61 09 00 10 08 11 ....!.|...a.....
011290: 00 07 01 00 2C 4C 43 4C 31 32 30 41 00 00 00 00 ....,LCL120A....
0112A0: 00 00 00 00 00 02 FF 00 99 04 70 09 00 99 0C 00 ..........p.....
0112B0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
0112C0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
0112D0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
0112E0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
0112F0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
011300: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
011310: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
011320: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
011330: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
011340: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
011350: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
011360: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
011370: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
011380: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
011390: 00 00 00 00 00 94 CE FF FF FF FF 11 98 09 EA 04 ................
0113A0: 7C 04 32 05 42 09 00 10 08 59 1A 0F 05 00 16 A0 |.2.B....Y......
0113B0: 20 1E 27 00 00 06 00 2D 00 C9 00 42 00 AA 00 03 .'....-...B....
0113C0: 00 00 EC EF 22 22 01 03 00 00 ED EF 22 22 01 03 ....""......""..
0113D0: 00 00 EE EF 22 22 01 9E 20 0D 00 00 EA EF 20 0F ...."".. ..... .
0113E0: 20 EC 20 12 01 03 00 00 E1 28 0D 00 00 EA 29 EF . ......(....).
0113F0: 22 22 01 B0 01 0D 00 00 E2 EF 19 28 00 2A 00 B4 "".........(.*..
011400: 00 0D 00 00 E5 EF FF 0C 28 FF 45 28 0F 29 F6 16 ........(.E(.)..
011410: F4 10 29 01 0D 00 00 E6 EF FF 0C 28 FF 45 28 0F ..)........(.E(.
011420: 29 F6 15 F4 11 29 00 12 00 B9 00 0D 00 00 E7 EF )....)..........
011430: E4 0D 00 00 F2 28 13 29 00 43 00 BE 00 03 00 00 .....(.).C......
011440: FA EF 22 44 69 66 66 65 72 65 6E 74 69 61 74 65 .."Differentiate
011450: 20 77 69 74 68 20 72 65 73 70 65 63 74 20 74 6F with respect to
011460: 20 58 3A 22 F4 FF 16 28 0D 00 00 E2 F5 19 20 29 X:"...(...... )
011470: 01 0B 00 00 F7 EF F5 0B 00 00 F7 00 79 00 C0 00 ............y...
011480: 03 00 00 E5 EF FF 19 28 0D 00 00 E5 29 01 03 00 .......(....)...
011490: 00 E5 EF FF 79 28 03 00 00 E5 2C FF 0E 28 03 00 ....y(....,..(..
0114A0: 00 E5 29 F5 0F 29 01 03 00 00 E6 EF FF 19 28 9F ..)..)........(.
0114B0: 4F 0D 00 00 E6 29 01 03 00 00 E6 EF FF 79 28 03 O....).......y(.
0114C0: 00 00 E6 2C FF 0E 28 03 00 00 E6 29 F5 0F 29 01 ...,..(....)..).
0114D0: 03 00 00 E7 EF FF 19 28 0D 00 00 E7 29 01 03 00 .......(....)...
0114E0: 00 E7 EF FF 79 28 03 00 00 E7 2C FF 0E 28 03 00 ....y(....,..(..
0114F0: 00 E7 29 F5 0F 29 00 59 00 C3 00 03 00 00 F9 EF ..)..).Y........
011500: 22 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 "
011510: 20 20 6E 20 20 20 20 20 20 20 6E 2D 31 20 20 20 n n-1
011520: 20 20 20 20 20 20 74 68 65 20 64 65 72 69 76 61 the deriva
011530: 74 69 76 65 20 6F 66 20 61 58 20 20 69 73 20 6E tive of aX is n
011540: 61 58 20 20 20 20 20 20 20 20 20 20 20 20 22 00 aX ".
011550: 15 00 D2 00 A1 20 0B 00 00 F7 EF 0F 20 EB 20 A0 ..... ...... . .
011560: 20 1E 2C 01 00 1D 00 DC 00 03 00 00 F1 EF 03 00 .,.............
011570: 00 FA F4 03 00 00 E5 F4 22 58 5E 22 F4 03 00 00 ........"X^"....
011580: E6 00 2B 00 E6 00 03 00 00 E8 EF 03 00 00 F9 F4 ..+.............
011590: 22 61 6E 64 20 5E 20 69 73 20 27 74 6F 20 74 68 "and ^ is 'to th
0115A0: 65 20 70 6F 77 65 72 20 6F 66 27 22 00 9E 00 F0 e power of'"....
0115B0: 00 EC 69 03 00 00 72 B1 EF FF 19 28 0D 00 00 E5 ..i...r....(....
0115C0: F6 0D 00 00 E6 29 01 03 00 00 72 B1 EF FF 79 28 .....)....r...y(
0115D0: 03 00 00 72 B1 2C FF 0E 28 03 00 00 72 B1 29 F5 ...r.,..(...r.).
0115E0: 0F 29 01 03 00 00 72 B2 EF FF 19 28 0D 00 00 E6 .)....r....(....
0115F0: F5 0F 29 01 03 00 00 72 B2 EF FF 79 28 03 00 00 ..)....r...y(...
011600: 72 B2 2C FF 0E 28 03 00 00 72 B2 29 F5 0F 29 01 r.,..(...r.)..).
011610: 03 00 00 E1 28 0F 29 EF 03 00 00 72 B1 F4 22 58 ....(.)....r.."X
011620: 5E 22 F4 03 00 00 72 B2 01 03 00 00 E1 28 10 29 ^"....r......(.)
011630: EF 22 58 5E 22 F4 03 00 00 72 B2 F4 22 2E 22 F4 ."X^"....r..".".
011640: 03 00 00 72 B1 01 0D 00 00 EE EF 10 00 59 00 04 ...r.........Y..
011650: 01 03 00 00 EC EF 03 00 00 E1 28 0F 29 01 03 00 ..........(.)...
011660: 00 ED EF 22 61 73 20 22 F4 03 00 00 E5 F4 22 20 ..."as "......"
011670: 78 20 22 F4 03 00 00 E6 F4 22 20 3D 20 22 F4 03 x "......" = "..
011680: 00 00 72 B1 01 03 00 00 EE EF 22 61 6E 64 20 22 ..r......."and "
011690: F4 03 00 00 E6 F4 22 20 2D 20 31 20 3D 20 22 F4 ......" - 1 = ".
0116A0: 03 00 00 72 B2 00 16 00 2C 01 A1 20 0B 00 00 F7 ...r....,.. ....
0116B0: EF F5 0F 9A 40 20 EB 20 A0 20 1E 90 01 00 2C 00 ....@ . . ....,.
0116C0: 36 01 03 00 00 F1 EF 03 00 00 FA F4 22 58 5E 32 6..........."X^2
0116D0: 20 2B 20 22 F4 03 00 00 E5 F4 22 58 20 2B 20 22 + "......"X + "
0116E0: F4 03 00 00 E7 F4 22 20 22 00 2E 00 3B 01 03 00 ......" "...;...
0116F0: 00 F7 EF 22 64 65 72 69 76 61 74 69 76 65 20 6F ..."derivative o
011700: 66 20 61 20 63 6F 6E 73 74 61 6E 74 20 69 73 20 f a constant is
011710: 7A 65 72 6F 20 20 22 00 41 00 40 01 03 00 00 E8 zero ".A.@.....
011720: EF 03 00 00 F9 F4 22 74 68 65 20 64 65 72 69 76 ......"the deriv
011730: 61 74 69 76 65 20 6F 66 20 6E 58 20 69 73 20 6E ative of nX is n
011740: 20 61 6E 64 20 74 68 65 22 F4 FF 16 28 15 29 F4 and the"...(.).
011750: 03 00 00 F7 F4 22 20 22 00 57 00 4A 01 03 00 00 ....." ".W.J....
011760: E1 28 0F 29 EF 22 32 58 2B 22 F4 03 00 00 E5 01 .(.)."2X+"......
011770: 03 00 00 E1 28 10 29 EF 22 58 32 2B 22 F4 03 00 ....(.)."X2+"...
011780: 00 E5 01 03 00 00 E1 28 11 29 EF 03 00 00 E5 F4 .......(.)......
011790: 22 2B 32 58 22 01 03 00 00 E1 28 12 29 EF 03 00 "+2X".....(.)...
0117A0: 00 E5 F4 22 2B 58 32 22 01 0D 00 00 EE EF 12 00 ..."+X2"........
0117B0: 34 00 54 01 03 BB CF 00 00 EC EF 03 00 00 E1 28 4.T............(
0117C0: 0F 29 F4 22 20 61 73 20 74 68 65 20 64 65 72 69 .)." as the deri
0117D0: 76 61 74 69 76 65 20 6F 66 20 58 5E 32 20 69 73 vative of X^2 is
0117E0: 20 32 58 20 22 00 30 00 5E 01 03 00 00 ED EF 22 2X ".0.^......"
0117F0: 74 68 65 20 64 65 72 69 76 61 74 69 76 65 20 6F the derivative o
011800: 66 20 22 F4 03 00 00 E5 F4 22 58 20 69 73 20 22 f "......"X is "
011810: F4 03 00 00 E5 00 32 00 68 01 03 00 00 EE EF 22 ......2.h......"
011820: 61 6E 64 20 74 68 65 20 64 65 72 69 76 61 74 69 and the derivati
011830: 76 65 20 6F 66 20 22 F4 03 00 00 E7 F4 22 20 69 ve of "......" i
011840: 73 20 7A 65 72 6F 22 00 06 00 90 01 C9 00 00 00 s zero".........
011850: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
011860: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
011870: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
011880: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
011890: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
0118A0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................
0118B0: 00 00 00 00 00 00 00 25 2C FF FF FF FF .......%,....
RESULT OF SEARCH :
PRO=19 CHEA=0 COD=0 MUSI=0 COP=14 GRA=20 WRIT=3 198=41 199=0 STARTER=0 KBI=0 CAAV=0 L.TOURNIER=0
PRO=19 CHEA=0 COD=0 MUSI=0 COP=14 GRA=20 WRIT=3 198=41 199=0 STARTER=0 KBI=0 CAAV=0 L.TOURNIER=0
Cc f,MENUp7)q Micro Maths menu2A copyright (c) G.Ludinski 1981,adapted for t
he Amstrad 1985 ( ) ( 2() , F , Zt"Micro Maths 2" d tFInl"LCLLCLLCLLCL"p ,
, , , , , , ,$x lr , , , () , t , , ()()t g C"" ! (
) ( ), $ C"" F t , , , ,n (()" Micro nyMaths 2 menu
"(() 1"Similar trianglesA"1"Geo
metry of the circle and its chordsB"1"Advanced StatisticsC"1""Applicatzions of P
ythagoras TheoremD"1,"TrigonometryE"16"Factorisation of Algebraic equationsF"1"G
raphsG"1J"Simultaneous equationsH"1T"Indices in ArithmetgicI"1"Indices in Algebr
aJ"1h"VectorsK"1j"MatricesL"1l"Differential calculusM"rC "" rJ() "a" "b" "c"
"d" "e" "f" "g" "h" "i" "j" "k" "l" "m" r t "a" "LCL130B" "b"
"LCL160A" "c" "LCL150A" "d" "LCL130C" "e" "LCL110D" "f" "LCL110A" "g"
"LCL140D" "h" "LCL160D" "i" "LCL130A" "j" "LCL150D" "k" "LX!,MENUp!9
4%CL150C" "l" "LCL160B" "m" "LCL120A" ,, ,,2 ,,2 ,R,2 ,,d ,,d ,,2 ,R,2 ,,2
,, ,,d ,,dL,LCL130Bp, t J LCL130B AMSTRAD,Copyright G.Ludinski 1981,adapt
ed for Amstrad 1985 $ ()4" "# ( )( E(
))( ( )(( ))(Q )4 , , , , k b()(&,())()()(&)()()(&,())()()()()J , " Similar
Triangle(Micro Maths)"()"LCL 1981 " 2 ,, ,, KEY DEF 3,0,223q£ "Hello, what
is your name"NA "Here are some problems " (NA) "NO SOUND" NA O ,, ,"CALC"(
)"" ,( )"CONT"( ) ,( )"" t,c,m,wstmt(F,)"" 2tt" P
A
QR BC "Z u(,((()()()() b %* "CALC" ,, & "CALC"
,, ((() ) "") + F (u(,)) S "Yes,congratulations" (NA)"NO SO
UND" ,, ,,2 ,,2 ,R,2 ,,d ,,d ,,2 ,R,2 ,,2 ,, ,,d ,,d "No,"",try again" 9 "
Sorry,the answer is " (£ "Do you want more (y/n)"m((d)t) ()"m" %Z! () "y"
()/ "yes" () "n" () "no" "" " ()"y" ()"yes" "" # ""$%&"" 'iC( xx(#) y
(#) , u("Test"(t)" Score"(m),LCL130Bp6!F4) "% "((F,)t)" secs. ",() x, y) i
"" 'Q* i() x(#) ()()u(,()) '0+ i( ) () % -",ii '-x +2"""""" ( 3 "4 l (
) l ()6 ()ly(( l),)ly(( l),)#8y(( ),)K9"In triangles PQR and ABC,"".Are these t
riangles similar " V (E())B f"QR 4 x BC, angle ABC angle PQR, and angle
ACB angle PRQ"OC f"PQ 5 x AB, QR 5 x BC and angles ACB PRQ"JD f"PQ 3
x "AB, QR 3 x BC and PR 3 x AC"KF f"angles ABC PQR, ACB PRQ and BAC QPR"
OH f"PQ 5 x AB, QR 5 x BC and angles ABC PQR"J fL"triangles are similar if
1 Corresponding sides are proportional 2 Corresponding angles are e
qual 3 Two corresponding sides are proportional with the angl
e between them equal "M()"as corresponding sides
are proportional"()"as corresponding angles are equal"()"as two corresponding si
des are proportional,with the angle between themequal"2N "y"r"yes)"
PO"n"r"no)"BP " (i.e. "r ( )R "as the sum of the internal angles of a tr
iangle 180 degrees,so corresponding angles are equal (rule 2)"QT "as the equ
al angle must be between the proportional sides"V cX f"If triangles ABC and
PQR are similar,AB "l" cm.,BC "l" cm.,PQ "( l)" cm. and angles ABC PQR and B
AC QPR. Find QR" fY"find the ratio between the two corresponding sides wh
o!FD,LCL130Bp&5se values are given. Then multiply the remaining side whose va
lue is given by this number"Z l( )y(,())" cm.""as PQ/AB "" so QR/BC is also "
"as BC"l" so QR "l" x "" "c+ l(f) l ( l() e # (f, e,)" " a (f, e,
)" " fu(f, e)y(f, l e) l l ' (f, e ,)" " fu(f, e )( )y(f, l e ) l l T,LC
L160Ap12 t J LCL160A AMSTRAD,Copyright G.Ludinski 1981,adapted for Amstra
d 1985 # 4" "# ( )( E())( ( )(( ))( )
4 , , , , kb()(&,())()()(&)()()(&,())()()()()J , " Circles (Micro Maths)
"()" LCL 1981 " 7 # ,, ,, ,, ,,q £ "Hello, what is your name"NA "Here a
re some problems " (NA) "NO SOUND" NA O ,, ,"CALC"( )"" ,( )"CONT"( ) ,( )"
" t,c,m,wtgmt(F,)'"" 3ttt () (P) d u(" ",((()+)()() b $* "CALC" ,, &
"CALC" ,, % () "" (() ) S "Yes,congratulations" (NA)"NO SO
UND" ,, ,,2 ,*(,2 ,R,2 ,,d ,,d ,,2 ,R,2 ,,2 ,, ,,d ,,d "No,"",try again" 9
"Sorry,the answer is " (£ "Do you want more (y/n)"m((d)t) ()"m" $Z () "y"
() "yes" () "n" () "no" "" ! ()"y" ()"yes" "" " ""#$"" o%iC& xx(#) y
(#) , u("Test"(t)" Score"(m)"% "((F,)t)" secs. ",() x, y' i"" %Q( i() x
(#) ()()u(,())K,LCL160Ap*2. %0) i( ) () % +"*ii %++, l(f) l 2K-
( l() e (f, e,)" " 1a. (f, e,)" " fu(/f, e)y(f, l e) l l 1/ ' (f, e ,)"
" fu(f, e )( )y(f, l e ) l l 10123"""""" ( "") '4 l(E()) l ()6 a(E()F )ly(( l
), ( l))ly(( l), ( l))ay(( a), ( a))8"ABCD is a cyclic quadrilateral,O is the ce
ntre of the circle and OP is 9 perpendicular to BD, meeting BD at P. OQi
s perpendicular to AD, meeting AD at Q."(E()) F'"If BP"l" cm. then BD"cB"a li
ne drawn from the centre of a circle perpendicular to a chord bisects )that c
hord"gD ly(( ), ( ))" cm.""as BD is a chord bisected by OP"%E"and 2 x "l" "F
LNH"If BD"l" cm.,OQ"l" cm. and AD"l" cm. then OP"OJ 4 ll" cm.""as BD and AD a
re equal chords so OPOQ"NK"equal chords are the same distance from the centre
of the circle"L T8N"If angle BAD"a" degrees.The angle BOD"mP"the angle subten
ded by the arc of a circle at the centre is twice the angle at the circumferenc
e"R ay(( ), ( ))" degrees as 2 x "a" ""and BOD is the angle at the centre""and
BAD the angle at the circumference"T c9V"If angle BAD"a" degrees then angle
BCD"LX"opposite angles of a cyclic quadrilateral 180 degrees"Z ay(( )
, ( ))" degrees as 180 - "a" "sM,LCL160ApR/7h"and ABCD is acyclic quadrilateral
""and BAD and BCD are opposite angles"c-d o(((#))) , o&n ( r ,px ,(
r ) ,( r ) p() p() p() p()( r p() p()) p() p() p() p() p() p()
, p() p( ), p( ) p( ), p( ) ( ) p( ), p( ) p(), p()K ,"o" , , ,"Q" , ,
"P"2 p(), p() , p(), p()H,LCL150Ap8 t J LCL150A AMSTRAD,Copyright G.Lu
dinski 1981,adapted for Amstrad 1985' # (), ()4"
"# ( )( E())( ( )(!8( ))( )4 , , , , kb()(&,())()()(&)()()(&,(
))()()()()J , " Statistics 2 (Micro Maths) "()" LCL 1981 " n 7 ,, ,, ,, ,
,q £ "Hello, what is your name"NA "Here are some problems " (NA) "NO SOUND" N
A O ,, ,"CALC"( )"" ,( )"CONT"( ) ,( )""7l t,c,m,wtmt(F,)'"" 3ttR u(" ",((
()+)()() b $* "CALC" ,, & "CALC" ,, 1 "" (() ) S "Yes,congratu
lations" (NA)"NO SOUND" ,, ,,2 ,,2 ,R,2 ,,d ,,d ,,2 ,R,2 ,,2 ,, ,,d ,,d "
No,"",try again" 9 "Sorry,the answer is " (£ "Do you want more (y/n)"m((d)t) (
)"m" $Z () "y" () "yes" () "n" () "no" "" ! ()"y" ()"yes" "" " ""
#$"" %iC& xx(#) y(#) , u("Test"(t)" Score"(m)"% "((F,)t)" secs. ",() x, y'
i"" %Q( i() x(#) ()()u(,()) %0) i( ) () % +"*F,LCL150Ap9n3 ii %++, l(
f) l 2K- ( l() e (f, e,)" " 1a. (f, e,)" " fu(f, e)y(f, l e) l l 1
/ ' (f, e ,)" " fu(f, e )( )y(f, l e ) l l 1012q3"""""" ( "" m dm(E().)4
65( )(E()) ( )m 556 ( )m m( )m 9 ( ) 6 d d( ) ( ) d d( ) d dl8A d(
d) d d ( d)lB"" dy(( ( )), ( ( )))","u(,( d))Ct"th"m( d) m t"st"D m t"n
d"E m t"rd"F P9H"The mode of the following numbers "J"The mode is the
number that occurs most frequently"L my(( ), ( ))"as there are more of the num
ber "" in thelist than any other number"P Z9R"The median of the following num
bers "qT"The median is the middle number when the numbers are arranged in as
cending order (as they are here)"V (( d))y(( ), ( ))"as there are "y(( d), (
d))" numbers"sX"and the middle number is the "y((( d)), (( d)))t" number,which i
s "Z c n(Ev()) (E() ) n (E() ) n (h n) y(( ), ( ))y(( ), ( ))y(( ), ( ))f"If
"" men,"" women and "" children are I,LCL150ApE0watching football. The angle a
t the centre of the sector representing men,in a pie chart" ,fa"angle men
x 360 degrees total
where men number of men total number of people"
b ( n)y(( ), ( ))" degrees""as "" + "" + "" "( )"and ("" / "y((h n), (h n))"
) x 360 "c!F,LCL130Cp66 t J LCL130C AMSTRAD,Copyright G.Ludinski 1981,ad
apted for Amstrad 1985 K ()4)" "#3 (
)( E())( ( )(( 5))( )4G , , , , kQb()(&,())()()(&)()()(&,())()()()()J , "
Pythagoras (Micro Maths) "()" LCL 1981 "e s7o ,, ,, ,, ,,qy£ "Hello, wha
t is your name"NA "Here are some problems " (NA) "NO SOUND" NA O ,, ,"CALC"
( )"" ,( )"CONT"( ) ,( )"" t,"c,m,wtmt(F,)"" tt "
ac
b " " A
B"()"C
H "b u(4" ",((()+)()() b
U* "CALC" ,, & "CALC" ,, ((() ) "") + (u(,)) 5 S "Yes,c
ongratulations" (NA)"NO SOUND" ,, ,,2 ,,2 ,R,2 ,,d ,,d ,,2 ,R,2 ,,2 ,, ,,d ,,
d A"No,"",try again" 9 "Sorry,the answer is " (£ "Do you want more (y/n)"m
((d)t)# ()"m" UZ- () "y" () "yes" () "n" ()D!d,LCL130CpkmB "no" "" 7 ()
"y" ()"yes" "" A ""KU"" iiCs xx(#) y(#) , u("Test"(t)" Score"(m)"% "((F
,)t)" secs.L ",() x, y i"" iQ i() x(#) ()()u(,()) i0 i( ) () % "ii i
0"""""" ( LR (E()) (E())y(( ),)y(( ),) (d( ))d( )y(,()) f"If the shorter
sides (a and b) of at right-angled triangle are "" cm. and "" cm. then the hypot
enuse (c)" Yf" 2 2 2 c a + b
where chypotenuse,a and b other sides"R " cm.""as hypotenuse 2 ""2
+ ""2"M"so c square root ("( )" +"( )") " Otf"If an isosceles triangle A
BC has AB and AC "" cm. and BC "( )" cm. then the height AH" Yf'"the height AH
bisects BC creating tworight-angled triangles AHB and AHC. 2 2 2
AH AB - BH "51 ( )y(,())" cm.""as BH "( )" / 2 "E"
AH square root (""2 - ""2) "O+Y l(f) l c ( l()m e #w (f, e,)" " a
(f, eS,)" " fu(f, e)y(f, l e) l l ' (f, e ,)" " fu(f, e )( )y(f, l e ) l l
!c,LCL110Dp cu t $J LCL110D AMSTRAD,Copyright G.Ludinski 1981,adapted
for Amstrad 1985 4" "# ( )( E())( ( )
(( ))( M)4 , , , , k b()(&,())()()(&)()()(&,())()()()()J , " Trigonometry (M
icro Maths) "()" LCL 1981 " ,, ,,q£ "Hello, what is your name"NA "Here a
re some problems " (NA) "NO SOUND" NA O ,, ,"CALC"( )"" ,( )"CONT"( ) ,( )"
" t,c,m,wtmt,£(F,)" C
A B "'"" ttL u(,((()()()(
) b %* "CALC" ,, & "CALC" ,, 1 (() ) "" S "Yes,congratulations
" (NA)"NO SOUND" ,, ,,2 ,,2 ,R,2 ,,d ,,d ,,2 ,R,2 ,,2 ,, ,,d ,,d "No,"",t
ry again" 9 "Sorry,the answer is " oV &£ "Do you want more (y/n)"m((d)t) ()"m"
%Z! () "y" () "yes" () "n" () "no" "" " ()"y" ()"yes" "" # ""$%&"
" 'iC( xx(#) y(#) , u("Test"(t)" Score"(m)"% "((F,)t)" secs. ",() x, y) i"
" 'Q* i() x(#) KWFP,LCL110Dp z4F()()u(,()) '0+ i( ) () % -",ii '-""""
(E()( ) (E()Z ) (E()F )(E()) D""" cm "" and "" degrees " ( )y(,())( )y(,())Y"( )
y(,())"AB ""BC ","AC "( )"angle C "( )56z"Triangle ABC has a right-angle at B.
" z"Find AC where "J "sin(C) opposite (AB) / hypotenuse (AC)"ST ( d
( ))d( )y(,())Q "as "" / sin ( "" ) "h r z"Find BC where "z"cos(C) adja
cent (BC) / hypotenuse (AC) " (d ( ))d( )y(,())H"as "" x cos( "" ) "( ) 4z"F
ind angle C where "U"tan (C) opposite (AB) / adjacent (BC) " (d(( )))d( )y(,
())"as tan(C) "" / ""so angle C atn(""/"") "c,LCL110Aph5£ t J LCL11
0A AMSTRAD,Copyright G.Ludinski 1981,adapted for Amstrad 1985 ()4"
"# ( )( E())( ( )(( N))( )4 , , , , kb()(&,())
()()(&)()()(&,())()()()()J , " Factorisation (Micro Maths) "()" LCL 1981 " q£ "
Hello, what is your name"NA "Here are some problems " (NA) "NO SOUND" NA O
,, ,"CALC"( )"" ,( )"CONT"( ) ,( )""3 t m t(F,) '( "" t tO2 u(" ",((()+)()
() 3 b X*4 "CALC" ,, &6 "CALC" ,, 22 ()( ) PF Z H ZSP "Yes,con
gratulations" (NA)"NO SOUND" R ,, ,,2 ,,2 ,R,2 ,,d ,,d ,,2 ,R,2 ,,2 ,, ,,d ,
,d nZ "No,"",try again" 29d "Sorry,the answer is " (£ "Do you want more (
y/n)" m((d ) t) ()"m" XZ () "y" () "yes" () "n" () "no" "" ()"y" ()"y
es" "" ( "" ' () ()+ (E()) + (E()) 0 9 (( ) ( )) """""
" ( )"" " of the constant" "Factorise"u(,)4 &£Y,LCL110Ahph!5A" DxE co
nstant"R 6J" 2 X -"( )L"it is
equal to (X+e)(X-e) where e is the squ+are root"" "(( ))y(, (( )))r"(X+"")"r
"(X-"")"C"r"(""+X)"r"(-""+X)"()rr#()rr3$()rr()rr ,()" as square root of "( )"
"6 I" 2 X ""X"J"find,by trial and error
,two numbers which when multiplied together give the constant,and which when ad
ded give the coefficient of X.Write them in the form (X+d)(X+e) where d and e a
re these numbers"ETr"(X"")"r"(X"")"r"("( )"+X)"Er"("( )"+X)"()rr()rr3h()rr(
)rr r()" as "( )" x "( )" "3"and "( )" + "( )" " ( ) "+"y(,())Xl"" viC xx(
#) y(#) , u("Test"( t)" Score"( m)"% "((F,) t)" secs. ",() x, y i"" vQ i
() x(#) ()()u(,()) v0 i( ) () % "ii vf,LCL140Dp7B t J LCL140D AMS
TRAD,Copyright G.Ludinski 1981,adapted for Amstrad 1985w ,,,,,, ,, ,,,,,, ,, ,,
, ,,,,," " ,,, ,,,,, ,,, ,,,,, ,,,,,0,-
' ( )( E())( ( )(( ))( )4 , , , , 'kb()(&,())()()(&)()()(&,())()()()()J
, " Graphs (Micro Maths) "()" LCL 1981 " 7 ,, ,, ,, ,,q £ "Hello, w
hat is your name"NA "Here are some problems " (NA) "NO SOUND" NA O ,, ,"CAL
C"( )"" ,( )"CONT"( ) ,( )"" t,c,m,wtmt(F,)+"" 7tt "
" " "g " 1
"H()" "()" " ()()0 ()() 6 ()
() ()()()(,,&)()()(,*,&)() u(" ",((()+)()() b (* "CALC" ,, & "CALC"
,Vw, / ( ) (() ) "" S "Yes,congratulations" (NA)"NO SOUN
D" ! ,, ,,2 ,,2 ,R,!,LCL140Dp!6B 2 ,,d ,,d ,,2 ,R,2 ,,2 ,, ,,d ,,d ! "No,"",
try again" 9 "Sorry,the answer is " (!£ "Do you want more (y/n)"q"m((d)t)# ()
"m" (Z$ () "y" () "yes" () "n" () "no" "" !% ()"y" ()"yes" "" & ""
'("" )iC*N xx(#) y(#) , u("Test"(t)" Score"(m)"% "((F,)t)" secs. ",() x, y
+ i"" )Q, i() x(#) ()()u(,()) )0- &i( ) () % /".ii )/+0 l(f) l 6
K1 ( l() e (f, e,)" " 5a2 (f, e,)" " fu(f, e)y(if, l e) l l 53 ' (f,
e ,)" " fu(f, e )( )y(f, l e ) l l 5456L7"""""" (""""(E()) B8 ()( ())( ()) ()
() ()q9 ( ( )( )) 8 O O8 O OL"of a straight line""
Y"y(( ), ( ))"X" B"The gradient "" "" " v" The gradient of a straig
ht line is the cSoefficient of X when the equation is written in the form YmX+
c"kA y(( ), ( ))"as "y(( ), ( ))" is the coefficient of X"B FHC"The graph ""
"" crosses the Y aJnV,LCL140Dp5 xis at Y"8D"this is found by finding Y
when X 0" QE y(( ), ( ))"as when X 0, Y 0"F PfGf"The graph of the pa
rabola YX2""X"" crosses the X axis at X" 0fH" the values of X when Y is zero are
found by factorising the equation into the form (X+a)(X+b)0. Therefore either
(X+a) must equal zero or (X+b) must equal 0. If (X+a)0 then X-a. I
f (X+b)0 then X-b"I bJ nnly(( ), ( ))sy(( ), ( )) KFJsy(( ), ( ))ly(( ), ( )
).Ks" "ll" "sDL"asr factorising gives (X"")(X"") 0"M"so graph crosses X axis at
X"s" and X"l N PO( ) "+"y(,())P/G,LCL160Dp26 t J LCL160D AMSTRAD,Copyr
ight G.Ludinski 1981,adapted for Amstrad 1985 #"
"# ( )( E())( ( )(( ))( )4X , , , , kb()(&,())()()(&)()()(&,()
)()()()()J , " Sim. Equations(Micro Maths) "()" LCL 1981 " 7 / ,, ,, ,, ,,
q £ "Hello, what is your name"NA "Here are some problems " (NA) "NO SOUND" NA
O ,, ,"CALC"( )"" ,( )"CONT"( ) ,( )""3 t m t(F,) ' "" 3 t tR u(" ",((()
+)()() b $* "CALC" ,, & "CALC" ,, % AL () "" (() ) S "
Yes,congratulations" (NA)"NO SOUND" ,, ,,2 ,,2 ,R,2 ,,d ,,d ,,2 ,R,2 ,,2 ,,
,,d ,,d "No,"",try again" S "Sorry,the answer is " ( )(£ "Do you w
ant more (y/n)" m((d ) t) ()"m" $Z () "y" () "yes" () "n" () "no" "" !
()"y" ()"yes" "" " ""#$"" %iC& xx(#) y(#) , u("Test"( t)" Score"( m)"%
"((F,) t)" secs. ",() x, y' i"" %Q( i() x(#) ()()u(,()) %0) isS,LCL16
0Dp6B ( ) () % +"*ii %++, l(f) l 2K- ( l() e (f, e,)" " 1a. (f,
e,)" " fu(f, e)y(f, l e) l l 1/ ' (f, e ,)" " fu(f, e )( )y(f, l e ) l l 1
0123"""""" ( "" k4 xx(E() ) (E())xy(( x), ( x))y(( ), ( ))*6 ( )(E())-8 (E()
) ( ) ( )s( )y(( ( )), ( ( ))) ( ) ( V ) ( )"+"( )N c( () x)( () ) c( ()
x)( () ) n () n () n c Z f f m n m n m n n () n () n c Z f f ( n m n m
n m) ( n m n m n m) 6Fcy(( c), ( c))cy(( c), ( c))-A f () f () jB Gh(
f )( f ) ( f )( f ) f f f f BDFFfy(( f), ( f))fy(( f), ( f))HG l(()) l(c)
l(()) l(c)HJ()"X"()"Y"c( l l)"equation 1 "()"X"()"Y"c( l l)"equation 2 so X and
Y"I"to find Y, multiply equations by the numbers that make the coefficients of
the X terms equal. Then subtract eqn. 2 from eqn. 1 to get X"J"" f "multiply
eqn. 1 by "f", "9K"" f "multiply eqn. 2 by "fSLx" "f"as to find Y," ,f$Mk( ()
0 ,LCL160Dpo0Ff)ky(k, ((k)))c( c f)cy(c, ((c))) l(k) l(c)k( () f)ky(k, ((k)))c(
c f)cy(c, ((c))) l(k) $l(c)Nk(( () f))ky(k, ((k))) l(k)k(( () f))ky(k, ((k))) l(
k)s"+" ( () f) s"-"/Os"+" ( () f) s"-"Pk"X"sk"Y"c( l l l)"equation 1 "k"X"sk
"Y"c( l l l)"equation 2"*R()"subtract eqn. 2 from eqn. 1"T()"("y(( () f), ( () f
4))"-"y(( () f), ( () f))")Y"y(( c f), ( c f))"-"y(( c f), ( c f))9V()"so Y"".Su
bstituting for Y in eqn. 1"tX()()"X"u((),)"("y((( ())),g (( ())))"x"")"c" so X"x
Y cZ f ( n )( n ) ( n )( n ) ( n )( n ) n n n n n n f f c b,LCL130A
p£!7 t $J LCL130A AMSTRAD,Copyright G.Ludinski 1981,adapted for Amstrad
1985 4" "# ( )( E())( ( )(( ))( t)4
, , , , k b()(&,())()()(&)()()(&,())()()()()J , " Indices 1 (Micro Maths) "
()"LCL 1981 " + # ,, ,, ,,q£ "Hello, what is your name"NA "Here are some
problems " (NA) "NO SOUND" NA O ,, ,"CALC"( )"" ,( )"CONT"( ) ,( )"" t,c,m
,wt)"mt(F,)'"" 2ttL u(,((()()()() b %* "CALC" ,, & "CALC" ,, 1 (1()
) "" S "Yes,congratulations" (NA)"NO SOUND" ,, ,,2 ,,2 ,R,2 ,,d ,,d
,,2 ,R,2 ,,2 ,, ,,d ,,d "No,"",try again" 9 "Sorry,the answer is " (£ "Do
you want more (y/n)"m((d)t) ()"m" %Z! () "y" () "yes" () "n" () "no" ""
" ()"y" ()"yes" "" # ""$%&"" 'iC( xx(#) y(#) , u("Test"(t)" Score"(km)
"% "((F,)t)" secs. ",() x, y) i"" 'Q* i() x(#) ()()u(,()) '0+ i( ) ()
% -",ii '#d,LCL130ApN!5P -02"""""" ( L,4 (E()Z ) (E())55 (E())( )y(,)Q6( )y(,
)( )y(,)(E()) F("a"" x a"" a"8"to multiply those type of terms,add indices
"B ( )y(,())9D"a""as "" + "" "F P,H"(a"") / (a"") a"XJ"to divide those ty
pe of terms, subtract bottom index from top index "L ( )y(,())9N"a""as
"" - "" "P c&R"(a"")"" a"T"multiply indices"V ( )y(,())9X"a""as "" x ""
"c6!Z,LCL150Dp !B t J LCL150D AMSTRAD,Copyright G.Ludinski 1981,adapted f
or Amstrad 1985 #" "# ( )( E())( (
)(( ))( )4 , , , , kb()(&,())()()(&)()()(&,())()()()()J , " Indices 2 (Mi
cro Maths) "()" LCL 1981 " 7 ,, ,, ,, ,,q £ "Hello, what is your name"NA
"Here are some problems " (NA) "NO SOUND" NA O ,, ,"CALC"( )"" ,( )"CONT"(
) ,( )"" t,c,m,wtgmt(F,)'"" 3ttR u(" ",((()+)()() b $* "CALC" ,, & "C
ALC" ,, % () "" (() ) S "Yes,congratulations" (NA)"NO SOUN
D" ,, ,,2 ,,2 ,R,2 ,,d ,,d ,,2 ,R,2 ,,2 ,, ,,d ,,d "No,"",try again" 9 "So
rry,the answer is " (£ "Do you want more (y/n)"m((df)t) ()"m" $Z () "y" ()
"yes" () "n" () "no" "" ! ()"y" ()"yes" "" " ""#$"" %iC& xx(#) y(#)
, u("Test"(t)" Score"(m)"% "((F,)t)" secs. ",() x, y' i"" %Q( i() x(#)
()()u(,()) %0) i( ) ()!u,LCL150Dp6D) % +"*ii %++, l(f) l 2K- ( l
() e (f, e,)" " 1a. (f, e,)" " fu(f, e)y(f, l e) l l 1/ ' (f, e ,)" " f
u(f, e )( )y(f, l e ) l l 10123"""""" ("""" 84 (E()) 6y(( ), ( ))y(( ), (
))38y(( ), ( ))(E())R (E()) ( ( )) ( ) "y(( ), ( v)) FF"Write the a
nswer in the form of a fraction. Y-""Y-p 1/Yp"&B "1/Y"F PH"0"J "any n
umber to the power of 0 1 T0 " L"1"P cQ )R "(""/2)")T "(""/3)"gV"to ca
lculate Y(p/q) first take the qth root of Y,then raise this result to the power
of p"dW ( )y(( ), ( ))"and """" "WX "as the denominator 2 so the square
root of "" "RZ "as the denominator 3 so the cube root of "" "ci!,LCL150CpP
t J LCL150C AMSTRAD,Copyright G.Ludinski 1981,adapted for Amstrad 1985
#" "# ( )( E())( ( )(( ))( )4s , ,
, , b"
"()()() J ,y " Vectors (Micro Maths) "()" LCL 1981 " 7 ,, ,, ,,
,,q £ "Hello, what is your name"NA "Here are some problems " (NA) "NO SOUND"
NA O ,,z ,"CALC"( )"" ,( )"CONT"( ) ,( )"" t,c,m,wtmt(F,)h"" 3tt ,"CALC"(
)( )"" ,"CALC"( )""R Tu(" ",((()+)()() y b $ ,,0i ()() $i(((i)) ,,0
u(,)"CALC" ,, , u(,)"CALC" ,, % () "" (() ) S "Yes,con
gratulations" (NA)"NO SOUND" ,, ,,2 ,,2 ,R,2 ,i£,d ,,d ,,2 ,R,2 ,,2 ,, ,,d ,,
d "No,"",try again" "Sorry,the answer is " "Press Return"£ r"Sorry,the an
swer is " d(£ "Do you want more (y/n)"m((d)t) ()"m" $Z () "y" () "yes" (
) "n" () "no" "" ! ()"y" ()X,LCL150Cp6 "yes" "" " ""#$()"" %iC& xx(#)
y(#) , u("Test"(t)" Score"(m)"% "((F,)t)" secs. ",() x, y' i"" %Q( i()
x(#) ()()u(,()) %0) i( ) () % +"*ii %++, l(f) l 2K- ( l() e 7 (
f, e,)" " 1a. (f, e,)" " fu(f, e)y(f, l e) l l 1/ ' (f, e ,)" " fu(f, e )
( )y(f, l e ) l l Q 1012i3"""""" ( L ( )( )"" ""4 G6 ( )(E()) E() ( )
( )48( )y(( ( )), (q ( )))79 (E())y(( ), ( ))U l(())"If U ("()")"(& l)"("()")
then "(E()) H l(()) l(()) l(()) X"If U ("()") and V ("()")"( l l)"("()")"(
l l)"("()") then U+V ""to add vectors, add their components separately"Bry((
() ()), ( () ())) lWo(r)ry(( () ()), ( () ()))iD"("r")"(& l)"("r")""as "()" + "
()" "r9F"and "()" + "()" "r H VJG"U"L"when multiplying a scalar quantity
(i.e. an ordinary number) by a vector multiply each component of the vector by
the scalar"JNry(( ()), ( ())) l(r) UP"("r")"(& q S,LCL150CpJG,7l)"("y(( ()),
( ()))")"R "as "" x "()" "rRT"and "" x "()" "y(( ()), ( ()))V c!X"the mo
dulus of U"qy"the modulus of a vector is the squareroot of(A2 + B2) where A and
B are thecomponents of the vector"I (( () ())d)dy(( ), ( ))*b"as ("()")2 "y(( (
) ()), ( () ()))" and ("()")2 "y(( () ()), ( () ()))"so square root ("y(( () ()
), ( () ()))" +"y(( () ()), ( () ()))") "cd d1 f() d1 () () d2 () d2 () ()If
d1 () d2 () d1 d23g d1 d2 d1 d2j bv( (), d1, d1,) sw( (), d1, xd1,) bv(
(), d2, d2,) sw( (), d2, d2,) sc(( b s)) sc(( b s)) ( s sc),( s sc)Hl , s sc ,
b sc s sc, b sc,m0nJN , () sc, () sc"U"9x , d1 sc, d2 sc "V"( , d1 sc, d2
sc5R,LCL160Bp.1 t J LCL160B AMSTRAD,Copyright G.Ludinski 1981,adapted fo
r Amstrad 1985 #" "# ( )( E())( ( )
(( ))( )4 , , , , b()(&,())()()(&)()()(&)()()(&,())()()()()J , " Matrices
(Micro Maths) "()" LCL 1981 " 7 ,, ,, ,, ,,q £ "Hello, what is your na
me"NA "Here are some problems " (NA) "NO SOUND" NA V ,, ,"CALC"( )( )"" ,(
)"CONT"( ) ,( 0)""3 t m t(F,) ' "" 3 t tR u(" ",((()+)()() b() $ ()()()
,,0i $i(((i)) ,,0 u(,)"CALC" ,, , u(,)"CALC" ,, % () "" (() )
S "Y es,congratulations" (NA)"NO SOUND" ,, ,,2 ,,2 ,R,2 ,,d ,,d ,,2
,R,2 ,,2 ,, ,,d ,,d "No,"",try a"gain" 9 "Sorry,the answer is " (£ "Do
you want more (y/n)" m((d ) t) ()"m" $Z () "y" () "yes" () "n" () "no" "
" Z ! ()"y" ()"yes" "" " ""#$"" %iC& xx(#) y(#) , u("Test"( t)" Score"
( m)"% "((F,) t)" secs. ",() x, Z,LCL160Bp,. y' i"" %Q( i() x(#) ()()u
(,()) %0) i( ) () % +"*ii %++, l(f) l 2K- ( l() e (f, e,)" " 1a.
(f, e,)" " fu(f, e)y(f, l e) l l 1/ ' (f, e ,)" " fu(f, e )( )y(f, l )e )
l l 1012K3"""""" ( "" (E())4 ( )(E()) ( )(E())( )y(( ( )), ( ( )))( )y(W(
( )), ( ( )))6 r( () ())( () ()) (( r) () r) 48"Matrix P ("()" "()") Q (
"()" "()") ("()" "()")£ ("()" "()")"h"i.e. if matrix
PxQS then the element S(row r,col.c) is created from P(row r) and Q(col.c)"
H" so P + Q "Y"to add (or subtract) matrices,add (or subtract) their appr
Oopriate elements"sB ( )y(( ( ) ( )), ( ( ) ( ))) ( )(( ))XD"("()" "()")"(% (
) ())"("()" "()")"uF"as "()" + "()" "()"and "()" + "()" "()" etc."H XJ" P
x Q "L"P x Q (ae+bg af+bh) (ce+dg cf+dh) where P
(a b)and Q (e f) (c d1) (g h)
"N()( () () () ())()y((), ((())))()( () () () ())()y((), ((()))) l(()) l(()
)XV,LCL160Bp20*3P()( () () () ())()y((), ((())))()( () () () ())()y((), ((())))T
R"("()" "()")"(% l l)"("()" "()")"TkX" as P(row 1)"()" "()" & Q(col.1)"()" "()"s
o row 1,col.1("()"x"()")+("()"x"()")"()V"and row 1,col.2("()"x"()")+("()"x"()")"
()" etc."X cY () () () ()() ()()y(( ()), ( ()))()y(( ()), ( ())) r () () ()
()hZ"Matrix P ("()" "()")"(#)"("s()" "()") so the inverse of P ""inverse of P
1 (d -b) x (-c a) ad-bc
where matrix P (a b)
(c d) (ad-bc) -is called the determinant of P " () () r () () r
() () r () () r ( )(( ( ))(( ( ))))( )y(( ), ((( )))), ()(()) ()(())X"("()" "
()")"(% () ())"("()" "()")"a"as, the determinant ("()" x "()") - ("()" x "()")
"y(( r), ( r))b"so, for example, as d "()" so d / determinant "
()" / "y(( r), ( r))" "()cj,LCL120Ap9 t $J LCL120A AMSTRAD,Copyright G
.Ludinski 1981,adapted for Amstrad 1985 ()4"
"# ( )( E())( ( )(( ))( )4 , , , , k b()(&,())()()(&)()()(&,())()()()
()J , " Differentiation(Micro Maths) "()"LCL 1981 " C ,, ,,q£ "Hello, what
is your name"NA "Here are some problems " (NA) "NO SOUND" NA O ,, ,"CALC"(
)"" ,( )"CONT"( ) ,( )"" t,c,m,wtmt(F,)'"" ttO u(" ",((()+)()() b %* "CALC
" ,, & "CALC" ,, 2 S ()( ) S "Yes,congratulations" (NA)"NO SOUND
" ,, ,,2 ,,2 ,R,2 ,,d ,,d ,,2 ,R,2 ,,2 ,, ,,d ,,d "No,"",try again" 9 "Sor
ry,the answer is " (£ "Do you want more (y/n)"m((d)t) ()"m" %Z! () "y" ()
"yes" () "n" () "no" "" " ()"y" ()"yes" "" # ""$%&"" 'iC( xx(#) y(#)
, u("Test"(t)" Score"(m)"% "((F,)t)" secs. ",() x, y) i"" 'Q* i() x(#)
()()u(,()) '0+ i( ) () % -",iiM!a,LCL120Ap2BY '-B"""""" ( )"" (* (E()
) (E()) ()C"Differentiate with respect to X"( )y( )y(,())(O )y(,())( )y(,())Y"
n n-1 the derivative of aX is naX "
,"X"+"and is 'to the power of'"ir( )ry(r,(r))r( )ry(r,(r))()r"X"r()"X"r"."r
Y()"as "" x "" "r"and "" - 1 "r, ,6"X2 + ""X + "" "."derivative of a consta
nt is zero "A"the derivative of nX is n and the"()" "WJ()"2X+"()"X2+"()"+2X"()"
+X2" 4T()" as the derivative of X2 is 2X "0"the derivative of ""X is "2h"and the
derivative of "" is zero"%,Tous droits réservés. Reproduction sans autorisation interdite. © Kukulcan