Answer Back Factfile 500 - Arithmetic (UK) (Face B) (1985) (Extension) [Original] [TAPE].cdt

[STRUCTURE]Creator : ZXTape!
Total of blocks : 33
Blocks format : [P]PAUSE[/P] (1), [P]TURBO LOADING DATA[/P] (32)[/STRUCTURE]
Catalogue
CheckData
TYPE BLOCKTOTAL BLOCKDURATION BLOCK MSPAUSE AFTER BLOCK MSTOTAL DURATION MSTIME
PAUSE12164102164100 h 00 m 21 s
TURBO LOADING DATA3229406320450049856300 h 08 m 18 s
TOTAL3331570420450052020400 h 08 m 40 s

SUM OF ALL DATA1 369 227
Sum of data for Turbo Loading - Turbo Loading size 1 byte1 369 227- 01 369 227
Sum of data for Pure Data - Pure Data size 3 bytes (sum = 262)0- 00
 
Result 1 369 227- 01 369 227
BLOCKTYPE BLOCKSUMDATAUsed bits
in last byte		Last
byte		DATA
0000PAUSE 
0001TURBO LOADING DATA1 7538FF263
0002TURBO LOADING DATA120 9148FF2069
0003TURBO LOADING DATA1 8928FF263
0004TURBO LOADING DATA2 6458FF263
0005TURBO LOADING DATA2 6348FF263
0006TURBO LOADING DATA103 5688FF1811
0007TURBO LOADING DATA2 4138FF263
0008TURBO LOADING DATA114 0318FF2069
0009TURBO LOADING DATA2 4538FF263
0010TURBO LOADING DATA122 8738FF1811
0011TURBO LOADING DATA2 2628FF263
0012TURBO LOADING DATA162 2138FF2069
0013TURBO LOADING DATA2 4078FF263
0014TURBO LOADING DATA17 1868FF263
0015TURBO LOADING DATA2 1948FF263
0016TURBO LOADING DATA107 0848FF2069
0017TURBO LOADING DATA2 5598FF263
0018TURBO LOADING DATA13 8668FF263
0019TURBO LOADING DATA2 2228FF263
0020TURBO LOADING DATA115 2078FF2069
0021TURBO LOADING DATA2 2658FF263
0022TURBO LOADING DATA10 1608FF263
0023TURBO LOADING DATA2 2578FF263
0024TURBO LOADING DATA128 8488FF2069
0025TURBO LOADING DATA2 5038FF263
0026TURBO LOADING DATA9 8678FF263
0027TURBO LOADING DATA2 4628FF263
0028TURBO LOADING DATA119 8088FF1811
0029TURBO LOADING DATA2 0568FF263
0030TURBO LOADING DATA152 1688FF2069
0031TURBO LOADING DATA2 5588FF263
0032TURBO LOADING DATA31 8998FF521

CATALOGUE
BLOCKFILENAMEFILE BLOCKFIRST BLOCKLAST BLOCKFILE TYPESTARTLENGTHEXECUTIONLENGTH FILE
0001AR111YES-Binaire&6000&0800&0000&081E
0003AR112-YESBinaire&6800&001E&0000&081E
0005AR121YESYESBinaire&6000&06E1&0000&06E1
0007AR131YESYESBinaire&6000&0797&0000&0797
0009AR141YESYESBinaire&6000&06AD&0000&06AD
0011AR151YES-Binaire&6000&0800&0000&08ED
0013AR152-YESBinaire&6800&00ED&0000&08ED
0015AR161YES-Binaire&6000&0800&0000&08F3
0017AR162-YESBinaire&6800&00F3&0000&08F3
0019AR171YES-Binaire&6000&0800&0000&08B2
0021AR172-YESBinaire&6800&00B2&0000&08B2
0023AR181YES-Binaire&6000&0800&0000&08D4
0025AR182-YESBinaire&6800&00D4&0000&08D4
0027AR191YESYESBinaire&6000&0696&0000&0696
0029AR201YES-Binaire&6000&0800&0000&09C4
0031AR202-YESBinaire&6800&01C4&0000&09C4

ZXTape! Major Version : 01 Minor Version : 0D
next* BLOCK 0000 : PAUSE
Total size : 3 bytes
Pause : 21641 ms
Duration block : 00 h 00 m 21 s
previousnext* BLOCK 0001 : TURBO LOADING DATA
HEADER
Block Name : AR11
Block Number : 1
Block first : YES
File type : Binaire
File adress start : &6000
File adress length : &0800
File adress execution : &0000
File length file : &081E

Length of PILOT pulse : 2525
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1322
Length of ONE bit pulse : 2534
Length of PILOT tone : 4099
Used bits in last byte : 8 OK
Data : 263 bytes
Total size : 282 bytes

Sum DATA : 1 753

Duration : 4594 ms
Pause After this block : 19 ms
Duration block + Pause : 4613 ms
Duration block + Pause : 00 h 00 m 04 s		000000: 2C 41 52 31 31 00 00 00 00 00 00 00 00 00 00 00 ,AR11........... 000010: 00 01 00 02 00 08 00 60 FF 1E 08 00 00 00 00 00 .......`........ 000020: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000030: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000040: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000050: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000060: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000070: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000080: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000090: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000A0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000B0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000C0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000D0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000E0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000F0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000100: 00 00 2C FF FF FF FF ..,....
previousnext* BLOCK 0002 : TURBO LOADING DATA
DATA
Length of PILOT pulse : 2522
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1342
Length of ONE bit pulse : 2481
Length of PILOT tone : 4096
Used bits in last byte : 8 OK
Data : 2069 bytes
Total size : 2088 bytes

Sum DATA : 120 914

Duration : 19402 ms
Pause After this block : 2706 ms
Duration block + Pause : 22108 ms
Duration block + Pause : 00 h 00 m 22 s		000000: 16 41 52 31 31 00 00 00 00 00 00 00 19 1D 08 00 .AR11........... 000010: 41 64 64 69 74 69 6F 6E 20 2D 20 48 54 55 20 20 Addition - HTU 000020: 20 20 20 20 20 20 20 20 20 00 00 00 00 00 00 00 ....... 000030: 00 47 00 41 64 64 20 66 6F 75 72 74 65 65 6E 2C .G.Add fourteen, 000040: 20 66 6F 72 74 79 2D 66 6F 75 72 20 61 6E 64 20 forty-four and 000050: 20 66 6F 75 72 20 68 75 6E 64 72 65 64 20 61 6E four hundred an 000060: 64 20 66 6F 75 72 2E 1B 34 36 32 1B 34 34 34 1B d four..462.444. 000070: 34 39 38 1B 34 32 34 1B 33 00 46 69 6E 64 20 74 498.424.3.Find t 000080: 68 65 20 73 75 6D 20 6F 66 20 31 32 36 2C 20 38 he sum of 126, 8 000090: 34 20 61 6E 64 20 20 20 39 36 1B 33 30 36 1B 33 4 and 96.306.3 0000A0: 32 36 1B 32 39 34 1B 32 37 36 1B 43 00 57 68 61 26.294.276.C.Wha 0000B0: 74 20 69 73 20 74 68 65 20 74 6F 74 61 6C 20 77 t is the total w 0000C0: 68 65 6E 20 34 36 2C 20 32 33 31 61 6E 64 20 35 hen 46, 231and 5 0000D0: 31 36 20 61 72 65 20 61 64 64 65 64 3F 1B 37 39 16 are added?.79 0000E0: 33 1B 37 34 32 1B 37 36 33 1B 38 30 33 1B 43 00 3.742.763.803.C. 0000F0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000100: 20 B1 74 20 20 20 20 20 20 20 20 20 20 20 20 20 .t 000110: 36 37 20 2B 20 31 36 32 20 2B 20 31 34 33 20 3D 67 + 162 + 143 = 000120: 20 3F 1B 33 37 32 1B 33 35 32 1B 33 39 33 1B 33 ?.372.352.393.3 000130: 36 38 1B 4A 00 20 20 20 20 20 20 20 20 20 20 20 68.J. 000140: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000150: 20 20 20 60 36 2E 37 39 20 2B 20 60 32 2E 31 35 `6.79 + `2.15 000160: 20 3D 20 3F 1B 60 38 2E 39 34 1B 60 38 2E 36 34 = ?.`8.94.`8.64 000170: 1B 60 38 2E 37 32 1B 60 37 2E 39 38 1B 3E 00 20 .`8.72.`7.98.>. 000180: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000190: 20 20 20 20 20 20 20 20 20 20 20 20 20 34 32 36 426 0001A0: 20 2B 20 32 31 34 20 3D 20 3F 1B 36 34 30 1B 36 + 214 = ?.640.6 0001B0: 33 34 1B 36 35 30 1B 36 35 31 1B 66 00 57 68 61 34.650.651.f.Wha 0001C0: 74 20 69 73 20 74 68 65 20 6D 69 73 73 69 6E 67 t is the missing 0001D0: 20 6E 75 6D 62 65 72 3F 20 20 20 20 20 20 20 20 number? 0001E0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0001F0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 3F 20 ? 000200: 2B 20 37 53 ED 31 32 20 3D 20 39 33 36 20 20 20 + 7S.12 = 936 000210: 20 20 1B 32 32 34 1B 32 35 36 1B 32 31 32 1B 32 .224.256.212.2 000220: 34 31 1B 8E 00 41 6D 79 20 73 70 65 6E 74 20 60 41...Amy spent ` 000230: 31 2E 36 38 20 61 74 20 74 68 65 20 62 61 6B 65 1.68 at the bake 000240: 72 73 2C 60 34 2E 36 32 20 61 74 20 74 68 65 20 rs,`4.62 at the 000250: 67 72 6F 63 65 72 73 20 61 6E 64 20 32 33 70 20 grocers and 23p 000260: 20 61 74 20 74 68 65 20 6E 65 77 73 61 67 65 6E at the newsagen 000270: 74 73 2E 20 48 6F 77 20 6D 75 63 68 20 20 20 64 ts. How much d 000280: 69 64 20 73 68 65 20 73 70 65 6E 64 20 61 6C 74 id she spend alt 000290: 6F 67 65 74 68 65 72 3F 1B 60 36 2E 35 33 1B 60 ogether?.`6.53.` 0002A0: 35 2E 38 34 1B 60 36 2E 33 31 1B 60 36 2E 37 32 5.84.`6.31.`6.72 0002B0: 1B 41 00 20 20 20 20 20 20 20 20 20 20 20 20 20 .A. 0002C0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0002D0: 20 38 37 20 2B 20 39 38 20 2B 20 37 36 20 3D 20 87 + 98 + 76 = 0002E0: 3F 1B 32 36 31 1B 31 39 37 1B 32 33 31 1B 32 35 ?.261.197.231.25 0002F0: 38 1B 44 00 20 20 20 20 20 20 20 20 20 20 20 20 8.D. 000300: 20 20 20 20 20 B1 2E 20 20 20 20 20 20 20 20 20 .. 000310: 20 20 20 20 32 30 67 20 2B 20 33 30 67 20 2B 20 20g + 30g + 000320: 31 35 67 20 3D 20 3F 1B 36 35 67 1B 35 35 67 1B 15g = ?.65g.55g. 000330: 37 35 67 1B 36 30 67 1B 7A 00 57 68 61 74 20 6E 75g.60g.z.What n 000340: 75 6D 62 65 72 73 20 63 6F 6D 65 20 6E 65 78 74 umbers come next 000350: 20 69 6E 20 74 68 69 73 73 65 71 75 65 6E 63 65 in thissequence 000360: 3F 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 ? 000370: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 32 2 000380: 35 2C 20 35 30 2C 20 37 35 2C 20 3F 2C 20 3F 1B 5, 50, 75, ?, ?. 000390: 31 30 30 2C 20 31 32 35 1B 39 30 2C 20 31 31 30 100, 125.90, 110 0003A0: 1B 39 35 2C 20 31 32 30 1B 31 30 35 2C 20 31 33 .95, 120.105, 13 0003B0: 30 1B 4E 00 41 64 64 20 65 69 67 68 74 79 2D 65 0.N.Add eighty-e 0003C0: 69 67 68 74 2C 20 65 69 67 68 74 65 65 6E 20 20 ight, eighteen 0003D0: 20 20 61 6E 64 20 65 69 67 68 74 20 68 75 6E 64 and eight hund 0003E0: 72 65 64 20 61 6E 64 20 65 69 67 68 74 79 2E 1B red and eighty.. 0003F0: 39 38 36 1B 39 31 34 1B 38 38 30 1B 38 31 38 1B 986.914.880.818. 000400: 35 00 46 69 6E 64 20 FF A5 74 68 65 20 73 75 6D 5.Find ..the sum 000410: 20 6F 66 20 35 32 37 2C 20 38 31 20 61 6E 64 20 of 527, 81 and 000420: 20 20 31 37 32 2E 1B 37 38 30 1B 37 36 33 1B 37 172..780.763.7 000430: 39 35 1B 37 38 39 1B 44 00 57 68 61 74 20 69 73 95.789.D.What is 000440: 20 74 68 65 20 74 6F 74 61 6C 20 77 68 65 6E 20 the total when 000450: 39 31 32 2C 20 20 20 32 37 20 61 6E 64 20 32 20 912, 27 and 2 000460: 61 72 65 20 61 64 64 65 64 3F 1B 39 34 31 1B 39 are added?.941.9 000470: 34 35 1B 39 33 39 1B 39 33 35 1B 3C 00 31 30 35 45.939.935.<.105 000480: 20 70 6C 75 73 20 32 30 33 20 70 6C 75 73 20 33 plus 203 plus 3 000490: 30 32 20 67 69 76 65 73 20 20 20 77 68 61 74 20 02 gives what 0004A0: 74 6F 74 61 6C 3F 1B 36 31 30 1B 36 33 31 1B 36 total?.610.631.6 0004B0: 31 37 1B 36 30 35 1B 3E 00 20 20 20 20 20 20 20 17.605.>. 0004C0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0004D0: 20 20 20 20 20 20 20 36 32 34 20 2B 20 31 30 38 624 + 108 0004E0: 20 3D 20 3F 1B 37 33 32 1B 37 35 36 1B 37 39 32 = ?.732.756.792 0004F0: 1B 37 32 33 1B 66 00 57 68 61 74 20 69 73 20 74 .723.f.What is t 000500: 68 65 20 6D 69 73 73 69 6E 86 24 67 20 6E 75 6D he missin.$g num 000510: 62 65 72 3F 20 20 20 20 20 20 20 20 20 20 20 20 ber? 000520: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000530: 20 20 20 20 20 20 20 20 20 20 3F 20 2B 20 31 39 ? + 19 000540: 31 20 3D 20 38 32 31 20 20 20 20 20 1B 36 33 30 1 = 821 .630 000550: 1B 37 35 33 1B 37 31 32 1B 36 38 37 1B 44 00 20 .753.712.687.D. 000560: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000570: 20 20 20 20 20 20 20 20 20 20 20 20 20 33 34 35 345 000580: 20 2B 20 31 32 33 20 2B 20 32 33 34 20 3D 20 3F + 123 + 234 = ? 000590: 1B 37 30 32 1B 37 31 33 1B 37 31 31 1B 37 30 35 .702.713.711.705 0005A0: 1B 4A 00 20 20 20 20 20 20 20 20 20 20 20 20 20 .J. 0005B0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0005C0: 20 31 32 37 67 20 2B 20 35 34 67 20 2B 20 31 39 127g + 54g + 19 0005D0: 33 67 20 3D 20 3F 1B 33 37 34 67 1B 33 37 32 67 3g = ?.374g.372g 0005E0: 1B 33 36 34 67 1B 33 38 32 67 1B 66 00 57 68 61 .364g.382g.f.Wha 0005F0: 74 20 69 73 20 74 68 65 20 6D 69 73 73 69 6E 67 t is the missing 000600: 20 6E 75 6D 62 65 72 20 69 6E 20 83 D4 74 68 69 number in ..thi 000610: 73 20 6E 75 6D 62 65 72 20 73 65 71 75 65 6E 63 s number sequenc 000620: 65 3F 20 20 20 20 20 20 20 20 20 20 20 31 37 36 e? 176 000630: 2C 20 31 38 38 2C 20 3F 2C 20 32 31 32 2C 20 32 , 188, ?, 212, 2 000640: 32 34 1B 32 30 30 1B 32 30 34 1B 32 30 32 1B 31 24.200.204.202.1 000650: 39 38 1B 7D 00 50 68 69 6C 69 70 20 68 61 64 20 98.}.Philip had 000660: 61 20 63 6F 6C 6C 65 63 74 69 6F 6E 20 6F 66 20 a collection of 000670: 20 20 20 32 32 37 20 73 74 61 6D 70 73 20 61 6E 227 stamps an 000680: 64 20 68 69 73 20 62 72 6F 74 68 65 72 20 68 61 d his brother ha 000690: 64 33 33 32 20 73 74 61 6D 70 73 2E 20 48 6F 77 d332 stamps. How 0006A0: 20 6D 61 6E 79 20 64 69 64 20 74 68 65 79 20 68 many did they h 0006B0: 61 76 65 20 61 6C 74 6F 67 65 74 68 65 72 3F 1B ave altogether?. 0006C0: 35 35 39 1B 35 34 39 1B 35 36 39 1B 35 37 39 1B 559.549.569.579. 0006D0: 6A 00 46 69 6E 64 20 74 68 65 20 6D 69 73 73 69 j.Find the missi 0006E0: 6E 67 20 6E 75 6D 62 65 72 3A 20 20 20 20 20 20 ng number: 0006F0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000700: 20 20 20 20 20 20 20 20 20 20 20 20 20 AE D6 20 .. 000710: 20 20 20 35 31 33 20 2B 20 3F 20 2B 20 32 31 38 513 + ? + 218 000720: 20 3D 20 39 33 37 20 20 20 20 20 1B 32 30 36 1B = 937 .206. 000730: 32 34 32 1B 32 31 33 1B 32 30 30 1B 50 00 20 20 242.213.200.P. 000740: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000750: 20 20 20 20 20 20 20 20 20 20 20 20 60 32 36 2E `26. 000760: 31 33 20 2B 20 60 31 33 2E 36 32 20 3D 20 3F 1B 13 + `13.62 = ?. 000770: 60 33 39 2E 37 35 1B 60 33 37 2E 37 31 1B 60 33 `39.75.`37.71.`3 000780: 38 2E 37 33 1B 60 34 30 2E 36 35 1B 3E 00 20 20 8.73.`40.65.>. 000790: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0007A0: 20 20 20 20 20 20 20 20 20 20 20 20 31 32 31 20 121 0007B0: 2B 20 34 34 34 20 3D 20 3F 1B 35 36 35 1B 35 33 + 444 = ?.565.53 0007C0: 34 1B 35 34 35 1B 35 37 36 1B 62 00 57 68 61 74 4.545.576.b.What 0007D0: 20 69 73 20 74 68 65 20 6D 69 73 73 69 6E 67 20 is the missing 0007E0: 6E 75 6D 62 65 72 3F 20 20 20 20 20 20 20 20 20 number? 0007F0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000800: 20 20 20 20 20 20 20 20 20 20 20 20 3F 20 2B FE ? +. 000810: 83 FF FF FF FF .....
previousnext* BLOCK 0003 : TURBO LOADING DATA
HEADER
Block Name : AR11
Block Number : 2
Block last : YES
File type : Binaire
File adress start : &6800
File adress length : &001E
File adress execution : &0000
File length file : &081E

Length of PILOT pulse : 2519
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1320
Length of ONE bit pulse : 2519
Length of PILOT tone : 4096
Used bits in last byte : 8 OK
Data : 263 bytes
Total size : 282 bytes

Sum DATA : 1 892

Duration : 4588 ms
Pause After this block : 18 ms
Duration block + Pause : 4606 ms
Duration block + Pause : 00 h 00 m 04 s		000000: 2C 41 52 31 31 00 00 00 00 00 00 00 00 00 00 00 ,AR11........... 000010: 00 02 FF 02 1E 00 00 68 00 1E 08 00 00 00 00 00 .......h........ 000020: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000030: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000040: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000050: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000060: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000070: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000080: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000090: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000A0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000B0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000C0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000D0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000E0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000F0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000100: 00 4A 4E FF FF FF FF .JN....
previousnext* BLOCK 0004 : TURBO LOADING DATA
DATA
Length of PILOT pulse : 2517
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1320
Length of ONE bit pulse : 2502
Length of PILOT tone : 4098
Used bits in last byte : 8 OK
Data : 263 bytes
Total size : 282 bytes

Sum DATA : 2 645

Duration : 4626 ms
Pause After this block : 13622 ms
Duration block + Pause : 18248 ms
Duration block + Pause : 00 h 00 m 18 s		000000: 16 20 37 36 37 20 3D 20 38 31 32 20 20 20 20 20 . 767 = 812 000010: 1B 34 35 1B 31 32 35 1B 39 35 1B 36 35 1B 1C 00 .45.125.95.65... 000020: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000030: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000040: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000050: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000060: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000070: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000080: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000090: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000A0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000B0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000C0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000D0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000E0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000F0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000100: 00 5A F0 FF FF FF FF .Z.....
previousnext* BLOCK 0005 : TURBO LOADING DATA
HEADER
Block Name : AR12
Block Number : 1
Block first : YES
Block last : YES
File type : Binaire
File adress start : &6000
File adress length : &06E1
File adress execution : &0000
File length file : &06E1

Length of PILOT pulse : 2511
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1316
Length of ONE bit pulse : 2517
Length of PILOT tone : 4098
Used bits in last byte : 8 OK
Data : 263 bytes
Total size : 282 bytes

Sum DATA : 2 634

Duration : 4582 ms
Pause After this block : 17 ms
Duration block + Pause : 4599 ms
Duration block + Pause : 00 h 00 m 04 s		000000: 2C 41 52 31 32 00 00 00 00 00 00 00 00 00 00 00 ,AR12........... 000010: 00 01 FF 02 E1 06 00 60 FF E1 06 00 00 00 00 00 .......`........ 000020: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000030: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000040: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000050: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000060: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000070: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000080: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000090: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000A0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000B0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000C0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000D0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000E0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000F0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000100: 00 35 C8 FF FF FF FF .5.....
previousnext* BLOCK 0006 : TURBO LOADING DATA
DATA
Length of PILOT pulse : 2510
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1336
Length of ONE bit pulse : 2472
Length of PILOT tone : 4099
Used bits in last byte : 8 OK
Data : 1811 bytes
Total size : 1830 bytes

Sum DATA : 103 568

Duration : 17307 ms
Pause After this block : 13588 ms
Duration block + Pause : 30895 ms
Duration block + Pause : 00 h 00 m 30 s		000000: 16 41 52 31 32 00 00 00 00 00 00 00 19 E0 06 00 .AR12........... 000010: 53 75 62 74 72 61 63 74 69 6F 6E 20 2D 20 48 54 Subtraction - HT 000020: 55 20 20 20 20 20 20 20 20 00 00 00 00 00 00 00 U ....... 000030: 00 3E 00 20 20 20 20 20 20 20 20 20 20 20 20 20 .>. 000040: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000050: 20 37 33 32 20 2D 20 33 34 39 20 3D 20 3F 1B 33 732 - 349 = ?.3 000060: 38 33 1B 33 37 37 1B 34 38 37 1B 33 37 35 1B 39 83.377.487.375.9 000070: 00 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 . 000080: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 31 1 000090: 32 34 20 2D 20 39 39 20 3D 20 3F 1B 32 35 1B 31 24 - 99 = ?.25.1 0000A0: 36 1B 31 34 1B 32 33 1B 29 00 54 61 6B 65 20 35 6.14.23.).Take 5 0000B0: 37 32 20 61 77 61 79 20 66 72 6F 6D 20 37 30 31 72 away from 701 0000C0: 1B 31 32 39 1B 32 36 31 1B 31 34 39 1B 31 39 31 .129.261.149.191 0000D0: 1B 35 00 42 79 20 68 6F 77 20 6D 75 63 68 20 69 .5.By how much i 0000E0: 73 20 32 30 37 20 6C 65 73 73 20 74 68 61 6E 20 s 207 less than 0000F0: 20 35 31 32 3F 1B 33 30 35 1B 33 30 37 1B 33 30 512?.305.307.30 000100: 33 6E D8 1B 33 30 34 1B 45 00 57 68 61 74 20 63 3n..304.E.What c 000110: 68 61 6E 67 65 20 66 72 6F 6D 20 60 31 20 77 6F hange from `1 wo 000120: 75 6C 64 20 50 61 75 6C 67 65 74 20 69 66 20 68 uld Paulget if h 000130: 65 20 73 70 65 6E 74 20 37 34 70 3F 1B 32 36 70 e spent 74p?.26p 000140: 1B 32 33 70 1B 32 39 70 1B 32 35 70 1B 3D 00 48 .23p.29p.25p.=.H 000150: 6F 77 20 6D 61 6E 79 20 6D 75 73 74 20 62 65 20 ow many must be 000160: 61 64 64 65 64 20 74 6F 20 31 35 31 20 74 6F 20 added to 151 to 000170: 6D 61 6B 65 20 34 35 38 3F 1B 33 30 37 1B 32 39 make 458?.307.29 000180: 37 1B 33 31 37 1B 33 31 33 1B 29 00 53 75 62 74 7.317.313.).Subt 000190: 72 61 63 74 20 32 33 39 20 66 72 6F 6D 20 37 31 ract 239 from 71 0001A0: 32 2E 1B 34 37 33 1B 34 36 35 1B 34 37 35 1B 34 2..473.465.475.4 0001B0: 38 34 1B 4C 00 20 20 20 20 20 20 20 20 20 20 20 84.L. 0001C0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0001D0: 20 20 20 31 37 2E 31 32 6D 20 2D 20 31 32 2E 33 17.12m - 12.3 0001E0: 36 6D 20 3D 20 3F 1B 34 2E 37 36 6D 1B 35 2E 32 6m = ?.4.76m.5.2 0001F0: 36 6D 1B 34 2E 39 32 6D 1B 35 2E 31 34 6D 1B 5F 6m.4.92m.5.14m._ 000200: 00 57 68 C2 57 61 74 20 69 73 20 74 68 65 20 6D .Wh.Wat is the m 000210: 69 73 73 69 6E 67 20 6E 75 6D 62 65 72 20 69 6E issing number in 000220: 20 74 68 69 73 20 73 65 71 75 65 6E 63 65 3F 20 this sequence? 000230: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000240: 20 20 37 32 2C 20 36 34 2C 20 35 36 2C 20 3F 2C 72, 64, 56, ?, 000250: 20 34 30 1B 34 38 1B 34 36 1B 35 30 1B 34 34 1B 40.48.46.50.44. 000260: 24 00 54 61 6B 65 20 61 77 61 79 20 68 61 6C 66 $.Take away half 000270: 20 6F 66 20 39 36 2E 1B 34 38 1B 36 38 1B 34 35 of 96..48.68.45 000280: 1B 35 34 1B 2C 00 43 6F 75 6E 74 20 62 61 63 6B .54.,.Count back 000290: 20 6E 69 6E 65 20 66 72 6F 6D 20 34 34 33 2E 1B nine from 443.. 0002A0: 34 33 34 1B 34 33 35 1B 34 33 36 1B 34 33 33 1B 434.435.436.433. 0002B0: 5F 00 57 68 61 74 20 69 73 20 74 68 65 20 6D 69 _.What is the mi 0002C0: 73 73 69 6E 67 20 6E 75 6D 62 65 72 20 69 6E 20 ssing number in 0002D0: 74 68 69 73 20 6E 75 6D 62 65 72 20 73 65 6E 74 this number sent 0002E0: 65 6E 63 65 3F 20 20 20 20 20 20 20 20 20 20 20 ence? 0002F0: 20 20 20 31 37 3F 20 2D 20 32 39 20 3D 20 31 34 17? - 29 = 14 000300: 36 20 20 20 20 0A 08 20 1B 35 1B 36 1B 38 1B 33 6 .. .5.6.8.3 000310: 1B 4F 00 20 20 20 20 20 20 20 20 20 20 20 20 20 .O. 000320: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000330: 20 38 31 32 20 2D 20 36 37 39 20 3D 20 3F 20 20 812 - 679 = ? 000340: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 1B . 000350: 31 33 33 1B 32 33 31 1B 31 36 33 1B 32 30 33 1B 133.231.163.203. 000360: 67 00 57 68 61 74 20 69 73 20 74 68 65 20 6D 69 g.What is the mi 000370: 73 73 69 6E 67 20 6E 75 6D 62 65 72 3F 20 20 20 ssing number? 000380: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000390: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0003A0: 20 20 39 31 30 20 2D 20 3F 20 3D 20 34 37 33 20 910 - ? = 473 0003B0: 20 20 20 20 20 20 1B 34 33 37 1B 35 31 33 1B 35 .437.513.5 0003C0: 33 33 1B 34 35 37 1B 47 00 20 20 20 20 20 20 20 33.457.G. 0003D0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0003E0: 20 20 20 20 20 20 20 54 61 6B 65 20 31 30 31 20 Take 101 0003F0: 61 77 61 79 20 66 72 6F 6D 20 32 30 36 1B 31 30 away from 206.10 000400: 35 1B 31 31 35 1B 31 9D 75 30 31 1B 31 30 38 1B 5.115.1.u01.108. 000410: 31 00 57 68 61 74 20 6E 75 6D 62 65 72 20 69 73 1.What number is 000420: 20 36 32 36 20 6C 65 73 73 20 74 68 61 6E 20 20 626 less than 000430: 36 36 32 3F 1B 33 36 1B 33 34 1B 34 36 1B 34 32 662?.36.34.46.42 000440: 1B 44 00 57 68 61 74 20 63 68 61 6E 67 65 20 66 .D.What change f 000450: 72 6F 6D 20 60 31 20 77 6F 75 6C 64 20 49 20 20 rom `1 would I 000460: 20 67 65 74 20 69 66 20 49 20 73 70 65 6E 74 20 get if I spent 000470: 34 36 70 3F 1B 35 34 70 1B 34 34 70 1B 35 36 70 46p?.54p.44p.56p 000480: 1B 35 32 70 1B 28 00 53 75 62 74 72 61 63 74 20 .52p.(.Subtract 000490: 34 31 30 20 66 72 6F 6D 20 35 32 31 1B 31 31 31 410 from 521.111 0004A0: 1B 31 31 39 1B 31 30 36 1B 31 30 39 1B 46 00 20 .119.106.109.F. 0004B0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0004C0: 20 20 20 20 20 20 20 20 20 20 20 20 20 32 36 2E 26. 0004D0: 38 6D 20 2D 20 32 33 2E 39 6D 20 3D 20 3F 1B 32 8m - 23.9m = ?.2 0004E0: 2E 39 6D 1B 33 2E 31 6D 1B 33 2E 39 6D 1B 32 2E .9m.3.1m.3.9m.2. 0004F0: 31 6D 1B 67 00 57 68 61 74 20 69 73 20 74 68 65 1m.g.What is the 000500: 20 6D 69 73 73 69 6E 67 20 27 4C 6E 75 6D 62 65 missing 'Lnumbe 000510: 72 20 69 6E 20 74 68 69 73 20 73 65 71 75 65 6E r in this sequen 000520: 63 65 3F 20 20 20 20 20 20 20 20 20 20 20 20 20 ce? 000530: 20 20 20 20 20 20 31 39 37 2C 20 31 38 39 2C 20 197, 189, 000540: 31 38 31 2C 20 3F 2C 20 31 36 35 1B 31 37 33 1B 181, ?, 165.173. 000550: 31 37 31 1B 31 37 30 1B 31 37 32 1B 66 00 57 68 171.170.172.f.Wh 000560: 61 74 20 69 73 20 74 68 65 20 6D 69 73 73 69 6E at is the missin 000570: 67 20 6E 75 6D 62 65 72 3F 20 20 20 20 20 20 20 g number? 000580: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000590: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 3F 20 ? 0005A0: 2D 20 33 38 20 3D 20 37 32 31 20 20 20 20 20 20 - 38 = 721 0005B0: 20 1B 37 35 39 1B 37 35 34 1B 37 35 36 1B 37 35 .759.754.756.75 0005C0: 38 1B 25 00 54 61 6B 65 20 61 77 61 79 20 68 61 8.%.Take away ha 0005D0: 6C 66 20 6F 66 20 31 32 32 2E 1B 36 31 1B 36 32 lf of 122..61.62 0005E0: 1B 36 33 1B 36 30 1B 5E 00 46 69 6E 64 20 74 68 .63.60.^.Find th 0005F0: 65 20 6D 69 73 73 69 6E 67 20 6E 75 6D 62 65 72 e missing number 000600: 20 69 6E 20 20 20 20 74 68 69 73 6E F4 20 6E 75 in thisn. nu 000610: 6D 62 65 72 20 73 65 6E 74 65 6E 63 65 3A 20 20 mber sentence: 000620: 20 20 20 20 20 20 20 20 20 20 20 34 37 35 20 2D 475 - 000630: 20 32 36 3F 20 3D 20 32 31 31 20 20 20 20 1B 34 26? = 211 .4 000640: 1B 33 1B 35 1B 32 1B 3F 00 20 20 20 20 20 20 20 .3.5.2.?. 000650: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000660: 20 20 20 20 20 20 20 37 39 38 20 2D 20 36 36 36 798 - 666 000670: 20 3D 20 3F 1B 31 33 32 1B 31 32 33 1B 31 33 38 = ?.132.123.138 000680: 1B 31 34 36 34 1B 67 00 57 68 61 74 20 69 73 20 .1464.g.What is 000690: 74 68 65 20 6D 69 73 73 69 6E 67 20 6E 75 6D 62 the missing numb 0006A0: 65 72 3F 20 20 20 20 20 20 20 20 20 20 20 20 20 er? 0006B0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0006C0: 20 20 20 20 20 20 20 20 20 35 32 31 20 2D 20 3F 521 - ? 0006D0: 20 3D 20 31 33 34 20 20 20 20 20 20 1B 33 38 37 = 134 .387 0006E0: 1B 36 35 35 1B 36 35 33 1B 33 38 36 1B 1C 00 00 .655.653.386.... 0006F0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000700: 00 00 00 00 00 00 00 00 00 00 00 00 00 DD 0D FF ................ 000710: FF FF FF ...
previousnext* BLOCK 0007 : TURBO LOADING DATA
HEADER
Block Name : AR13
Block Number : 1
Block first : YES
Block last : YES
File type : Binaire
File adress start : &6000
File adress length : &0797
File adress execution : &0000
File length file : &0797

Length of PILOT pulse : 2508
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1316
Length of ONE bit pulse : 2509
Length of PILOT tone : 4098
Used bits in last byte : 8 OK
Data : 263 bytes
Total size : 282 bytes

Sum DATA : 2 413

Duration : 4579 ms
Pause After this block : 17 ms
Duration block + Pause : 4596 ms
Duration block + Pause : 00 h 00 m 04 s		000000: 2C 41 52 31 33 00 00 00 00 00 00 00 00 00 00 00 ,AR13........... 000010: 00 01 FF 02 97 07 00 60 FF 97 07 00 00 00 00 00 .......`........ 000020: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000030: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000040: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000050: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000060: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000070: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000080: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000090: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000A0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000B0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000C0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000D0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000E0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000F0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000100: 00 30 81 FF FF FF FF .0.....
previousnext* BLOCK 0008 : TURBO LOADING DATA
DATA
Length of PILOT pulse : 2509
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1333
Length of ONE bit pulse : 2472
Length of PILOT tone : 4099
Used bits in last byte : 8 OK
Data : 2069 bytes
Total size : 2088 bytes

Sum DATA : 114 031

Duration : 18994 ms
Pause After this block : 13400 ms
Duration block + Pause : 32394 ms
Duration block + Pause : 00 h 00 m 32 s		000000: 16 41 52 31 33 00 00 00 00 00 00 00 19 96 07 00 .AR13........... 000010: 4D 75 6C 74 69 70 6C 69 63 61 74 69 6F 6E 20 2D Multiplication - 000020: 20 48 54 55 20 20 20 20 20 00 00 00 00 00 00 00 HTU ....... 000030: 00 3C 00 20 20 20 20 20 20 20 20 20 20 20 20 20 .<. 000040: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000050: 20 31 32 32 20 78 20 38 20 3D 20 3F 1B 39 37 36 122 x 8 = ?.976 000060: 1B 38 39 36 1B 39 34 35 1B 39 37 30 1B 5E 00 57 .896.945.970.^.W 000070: 68 61 74 20 77 6F 75 6C 64 20 62 65 20 74 68 65 hat would be the 000080: 20 63 6F 73 74 20 6F 66 20 34 6B 67 20 6F 66 20 cost of 4kg of 000090: 61 70 70 6C 65 73 20 69 66 20 61 70 70 6C 65 73 apples if apples 0000A0: 20 63 6F 73 74 20 38 32 70 20 20 70 65 72 20 6B cost 82p per k 0000B0: 67 3F 1B 60 33 2E 32 38 1B 60 33 2E 32 32 1B 60 g?.`3.28.`3.22.` 0000C0: 33 2E 33 32 1B 60 33 2E 31 32 1B 5C 00 46 69 6E 3.32.`3.12.\.Fin 0000D0: 64 20 74 68 65 20 6D 69 73 73 69 6E 67 20 6E 75 d the missing nu 0000E0: 6D 62 65 72 3A 20 20 20 20 20 20 20 20 20 20 20 mber: 0000F0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000100: 20 0D 85 20 20 20 20 20 20 20 20 20 20 20 20 20 .. 000110: 38 20 78 20 3F 20 3D 20 36 34 20 20 20 20 20 20 8 x ? = 64 000120: 1B 38 1B 36 1B 39 1B 37 1B 3B 00 20 20 20 20 20 .8.6.9.7.;. 000130: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000140: 20 20 20 20 20 20 20 20 20 38 30 20 78 20 37 20 80 x 7 000150: 3D 20 3F 1B 35 36 30 1B 34 39 30 1B 35 34 30 1B = ?.560.490.540. 000160: 35 38 30 1B 3B 00 20 20 20 20 20 20 20 20 20 20 580.;. 000170: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000180: 20 20 20 20 33 31 20 78 20 37 20 3D 20 3F 1B 32 31 x 7 = ?.2 000190: 31 37 1B 32 32 31 1B 32 31 34 1B 32 30 37 1B 33 17.221.214.207.3 0001A0: 00 48 6F 77 20 6D 61 6E 79 20 64 61 79 73 20 61 .How many days a 0001B0: 72 65 20 74 68 65 72 65 20 69 6E 20 37 20 20 77 re there in 7 w 0001C0: 65 65 6B 73 3F 1B 34 39 1B 35 36 1B 34 32 1B 33 eeks?.49.56.42.3 0001D0: 35 1B 60 00 57 68 61 74 20 69 73 20 74 68 65 20 5.`.What is the 0001E0: 6D 69 73 73 69 6E 67 20 6E 75 6D 62 65 72 20 69 missing number i 0001F0: 6E 20 74 68 69 73 20 6E 75 6D 62 65 72 20 73 65 n this number se 000200: 6E 74 65 E7 81 6E 63 65 3F 20 20 20 20 20 20 20 nte..nce? 000210: 20 20 20 20 20 20 31 33 3F 20 78 20 33 20 3D 20 13? x 3 = 000220: 33 39 36 20 20 20 20 20 20 20 20 1B 32 1B 34 1B 396 .2.4. 000230: 36 1B 31 1B 61 00 57 68 61 74 20 69 73 20 74 68 6.1.a.What is th 000240: 65 20 6D 69 73 73 69 6E 67 20 6E 75 6D 62 65 72 e missing number 000250: 3F 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 ? 000260: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000270: 20 20 20 20 20 20 20 32 37 20 78 20 3F 20 3D 20 27 x ? = 000280: 35 39 34 20 20 20 20 20 1B 32 32 1B 31 34 1B 31 594 .22.14.1 000290: 38 1B 32 36 1B 54 00 48 6F 77 20 6D 75 63 68 20 8.26.T.How much 0002A0: 77 6F 75 6C 64 20 36 20 6D 65 74 72 65 73 20 6F would 6 metres o 0002B0: 66 20 20 20 20 72 69 62 62 6F 6E 20 63 6F 73 74 f ribbon cost 0002C0: 20 61 74 20 31 38 70 20 70 65 72 20 6D 65 74 72 at 18p per metr 0002D0: 65 3F 1B 60 31 2E 30 38 1B 39 38 70 1B 60 31 2E e?.`1.08.98p.`1. 0002E0: 31 36 1B 60 31 2E 31 38 1B 3C 00 20 20 20 20 20 16.`1.18.<. 0002F0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000300: 20 20 20 20 20 3B EE 20 20 20 20 32 32 34 20 78 ;. 224 x 000310: 20 34 20 3D 20 3F 1B 38 39 36 1B 38 37 36 1B 38 4 = ?.896.876.8 000320: 36 38 1B 38 38 38 1B 3C 00 20 20 20 20 20 20 20 68.888.<. 000330: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000340: 20 20 20 20 20 20 20 33 32 31 20 78 20 33 20 3D 321 x 3 = 000350: 20 3F 1B 39 36 33 1B 39 37 36 1B 39 35 33 1B 39 ?.963.976.953.9 000360: 38 39 1B 52 00 48 6F 77 20 6D 75 63 68 20 77 6F 89.R.How much wo 000370: 75 6C 64 20 38 6B 67 20 6F 66 20 73 75 67 61 72 uld 8kg of sugar 000380: 20 20 20 63 6F 73 74 20 61 74 20 34 38 70 20 70 cost at 48p p 000390: 65 72 20 6B 69 6C 6F 67 72 61 6D 3F 1B 60 33 2E er kilogram?.`3. 0003A0: 38 34 1B 60 33 2E 36 36 1B 60 33 2E 39 36 1B 60 84.`3.66.`3.96.` 0003B0: 33 2E 37 34 1B 61 00 46 69 6E 64 20 74 68 65 20 3.74.a.Find the 0003C0: 6D 69 73 73 69 6E 67 20 6E 75 6D 62 65 72 3A 20 missing number: 0003D0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0003E0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0003F0: 20 20 20 20 20 20 20 20 20 39 20 78 20 3F 20 3D 9 x ? = 000400: 20 31 38 30 20 20 20 89 A2 20 20 1B 32 30 1B 33 180 .. .20.3 000410: 30 1B 32 37 1B 31 35 1B 3C 00 20 20 20 20 20 20 0.27.15.<. 000420: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000430: 20 20 20 20 20 20 20 20 31 30 31 20 78 20 39 20 101 x 9 000440: 3D 20 3F 1B 39 30 39 1B 39 39 30 1B 39 39 39 1B = ?.909.990.999. 000450: 39 30 30 1B 3B 00 20 20 20 20 20 20 20 20 20 20 900.;. 000460: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000470: 20 20 20 20 39 37 20 78 20 38 20 3D 20 3F 1B 37 97 x 8 = ?.7 000480: 37 36 1B 38 30 34 1B 37 39 34 1B 37 38 34 1B 60 76.804.794.784.` 000490: 00 57 68 61 74 20 69 73 20 74 68 65 20 6D 69 73 .What is the mis 0004A0: 73 69 6E 67 20 6E 75 6D 62 65 72 3F 20 20 20 20 sing number? 0004B0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0004C0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0004D0: 20 20 3F 20 78 20 33 35 20 3D 20 32 34 35 20 20 ? x 35 = 245 0004E0: 20 20 20 20 1B 37 1B 35 1B 31 35 1B 31 31 1B 5F .7.5.15.11._ 0004F0: 00 57 68 61 74 20 69 73 20 74 68 65 20 6D 69 73 .What is the mis 000500: 73 69 6E 67 20 6E 75 6D 62 91 E2 65 72 20 69 6E sing numb..er in 000510: 20 74 68 69 73 20 6E 75 6D 62 65 72 20 73 65 6E this number sen 000520: 74 65 6E 63 65 3F 20 20 20 20 20 20 20 20 20 20 tence? 000530: 20 20 20 20 31 3F 32 20 78 20 35 20 3D 20 39 31 1?2 x 5 = 91 000540: 30 20 20 20 20 20 20 1B 38 1B 39 1B 37 1B 36 1B 0 .8.9.7.6. 000550: 37 00 48 6F 77 20 6D 61 6E 79 20 68 6F 75 72 73 7.How many hours 000560: 20 61 72 65 20 74 68 65 72 65 20 69 6E 20 20 20 are there in 000570: 38 20 64 61 79 73 3F 1B 31 39 32 1B 39 36 1B 31 8 days?.192.96.1 000580: 32 34 1B 31 37 36 1B 37 00 48 6F 77 20 6D 61 6E 24.176.7.How man 000590: 79 20 6D 6F 6E 74 68 73 20 61 72 65 20 74 68 65 y months are the 0005A0: 72 65 20 69 6E 20 20 39 20 79 65 61 72 73 3F 1B re in 9 years?. 0005B0: 31 30 38 1B 39 36 1B 31 32 30 1B 38 34 1B 3B 00 108.96.120.84.;. 0005C0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0005D0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 37 39 79 0005E0: 20 78 20 38 20 3D 20 3F 1B 36 33 32 1B 36 34 38 x 8 = ?.632.648 0005F0: 1B 36 31 38 1B 36 32 37 1B 67 00 46 69 6E 64 20 .618.627.g.Find 000600: 74 68 65 20 6D 69 73 73 69 6E 67 1A 43 20 6E 75 the missing.C nu 000610: 6D 62 65 72 3A 20 20 20 20 20 20 20 20 20 20 20 mber: 000620: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000630: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 3F 20 ? 000640: 78 20 36 20 3D 20 39 30 36 20 20 20 20 20 20 20 x 6 = 906 000650: 20 1B 31 35 31 1B 31 32 31 1B 31 38 31 1B 31 39 .151.121.181.19 000660: 31 1B 5F 00 57 68 61 74 20 69 73 20 74 68 65 20 1._.What is the 000670: 6D 69 73 73 69 6E 67 20 6E 75 6D 62 65 72 3F 20 missing number? 000680: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000690: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0006A0: 20 20 20 20 33 31 30 20 78 20 3F 20 3D 20 39 33 310 x ? = 93 0006B0: 30 20 20 20 20 20 20 20 1B 33 1B 32 1B 34 1B 35 0 .3.2.4.5 0006C0: 1B 4C 00 48 6F 77 20 6D 75 63 68 20 77 6F 75 6C .L.How much woul 0006D0: 64 20 34 20 6C 69 74 72 65 73 20 6F 66 20 20 20 d 4 litres of 0006E0: 20 6D 69 6C 6B 20 63 6F 73 74 20 61 74 20 33 38 milk cost at 38 0006F0: 70 20 70 65 72 20 6C 69 74 72 65 3F 1B 31 35 32 p per litre?.152 000700: 1B 31 33 38 1B 31 34 36 1B 31 35 38 1B 98 43 5C .138.146.158..C\ 000710: 00 57 68 61 74 20 69 73 20 74 68 65 20 6D 69 73 .What is the mis 000720: 73 69 6E 67 20 6E 75 6D 62 65 72 20 69 6E 20 74 sing number in t 000730: 68 69 73 20 6E 75 6D 62 65 72 20 73 65 6E 74 65 his number sente 000740: 6E 63 65 3F 20 20 20 20 20 20 20 20 20 20 20 20 nce? 000750: 20 20 32 3F 37 20 78 20 33 20 3D 20 36 38 31 20 2?7 x 3 = 681 000760: 20 20 1B 32 1B 33 1B 34 1B 36 1B 3A 00 20 20 20 .2.3.4.6.:. 000770: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000780: 20 20 20 20 20 20 20 20 20 20 20 38 28 38 38 29 8(88) 000790: 20 3D 20 3F 1B 37 30 34 1B 36 36 36 1B 37 32 34 = ?.704.666.724 0007A0: 1B 36 38 30 1B 1C 00 00 00 00 00 00 00 00 00 00 .680............ 0007B0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0007C0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0007D0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0007E0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0007F0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000800: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 64 ...............d 000810: 08 FF FF FF FF .....
previousnext* BLOCK 0009 : TURBO LOADING DATA
HEADER
Block Name : AR14
Block Number : 1
Block first : YES
Block last : YES
File type : Binaire
File adress start : &6000
File adress length : &06AD
File adress execution : &0000
File length file : &06AD

Length of PILOT pulse : 2512
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1316
Length of ONE bit pulse : 2509
Length of PILOT tone : 4099
Used bits in last byte : 8 OK
Data : 263 bytes
Total size : 282 bytes

Sum DATA : 2 453

Duration : 4583 ms
Pause After this block : 18 ms
Duration block + Pause : 4601 ms
Duration block + Pause : 00 h 00 m 04 s		000000: 2C 41 52 31 34 00 00 00 00 00 00 00 00 00 00 00 ,AR14........... 000010: 00 01 FF 02 AD 06 00 60 FF AD 06 00 00 00 00 00 .......`........ 000020: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000030: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000040: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000050: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000060: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000070: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000080: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000090: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000A0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000B0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000C0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000D0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000E0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000F0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000100: 00 A4 0A FF FF FF FF .......
previousnext* BLOCK 0010 : TURBO LOADING DATA
DATA
Length of PILOT pulse : 2512
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1339
Length of ONE bit pulse : 2475
Length of PILOT tone : 4096
Used bits in last byte : 8 OK
Data : 1811 bytes
Total size : 1830 bytes

Sum DATA : 122 873

Duration : 17674 ms
Pause After this block : 13395 ms
Duration block + Pause : 31069 ms
Duration block + Pause : 00 h 00 m 31 s		000000: 16 41 52 31 34 00 00 00 00 00 00 00 19 AC 06 00 .AR14........... 000010: 44 69 76 69 73 69 6F 6E 20 2D 20 48 54 55 20 20 Division - HTU 000020: 20 20 20 20 20 20 20 20 20 00 00 00 00 00 00 00 ....... 000030: 00 5A 00 20 20 20 20 20 20 20 20 20 20 20 20 20 .Z. 000040: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000050: 20 44 69 76 69 64 65 20 38 33 20 62 79 20 39 20 Divide 83 by 9 000060: 74 6F 20 74 77 6F 20 64 65 63 69 6D 61 6C 20 70 to two decimal p 000070: 6C 61 63 65 73 2E 1B 39 2E 32 32 1B 39 2E 35 33 laces..9.22.9.53 000080: 1B 38 2E 37 32 1B 39 2E 33 31 1B 2F 00 48 6F 77 .8.72.9.31./.How 000090: 20 6D 61 6E 79 20 73 65 74 73 20 6F 66 20 39 20 many sets of 9 0000A0: 61 72 65 20 74 68 65 72 65 20 20 69 6E 20 35 34 are there in 54 0000B0: 3F 1B 36 1B 37 1B 38 1B 35 1B 3C 00 48 6F 77 20 ?.6.7.8.5.<.How 0000C0: 6D 61 6E 79 20 31 30 63 6D 20 6C 65 6E 67 74 68 many 10cm length 0000D0: 73 20 61 72 65 20 20 20 20 20 74 68 65 72 65 20 s are there 0000E0: 69 6E 20 31 20 6D 65 74 72 65 3F 1B 31 30 1B 38 in 1 metre?.10.8 0000F0: 1B 36 1B 31 32 1B 69 00 41 20 6A 75 67 20 68 6F .6.12.i.A jug ho 000100: 6C AB 9C 64 73 20 68 61 6C 66 20 61 20 6C 69 74 l..ds half a lit 000110: 72 65 20 6F 66 20 20 20 6F 72 61 6E 67 65 20 64 re of orange d 000120: 72 69 6E 6B 2E 20 48 6F 77 20 6D 61 6E 79 20 31 rink. How many 1 000130: 30 30 6D 6C 20 20 62 65 61 6B 65 72 73 20 63 6F 00ml beakers co 000140: 75 6C 64 20 62 65 20 66 69 6C 6C 65 64 20 66 72 uld be filled fr 000150: 6F 6D 20 20 69 74 3F 1B 35 1B 34 1B 36 1B 31 30 om it?.5.4.6.10 000160: 1B 32 00 53 68 61 72 65 20 37 32 70 20 65 71 75 .2.Share 72p equ 000170: 61 6C 6C 79 20 62 65 74 77 65 65 6E 20 39 20 20 ally between 9 000180: 20 63 68 69 6C 64 72 65 6E 2E 1B 38 1B 39 1B 37 children..8.9.7 000190: 1B 36 1B 63 00 41 20 6E 75 6D 62 65 72 20 68 61 .6.c.A number ha 0001A0: 73 20 62 65 65 6E 20 64 69 76 69 64 65 64 20 75 s been divided u 0001B0: 70 20 20 69 6E 74 6F 20 65 69 67 68 74 20 73 65 p into eight se 0001C0: 74 73 20 6F 66 20 65 69 67 68 74 2E 20 57 68 61 ts of eight. Wha 0001D0: 74 77 61 73 20 74 68 65 20 6F 72 69 67 69 6E 61 twas the origina 0001E0: 6C 20 6E 75 6D 62 65 72 3F 1B 36 34 1B 35 36 1B l number?.64.56. 0001F0: 37 32 1B 34 38 1B 35 00 57 68 61 74 20 69 73 20 72.48.5.What is 000200: 61 20 74 B2 A4 65 6E 74 68 20 6F 66 20 6F 6E 65 a t..enth of one 000210: 20 20 20 20 20 20 20 20 68 75 6E 64 72 65 64 3F hundred? 000220: 1B 31 30 1B 32 30 1B 32 35 1B 35 30 1B 32 00 48 .10.20.25.50.2.H 000230: 6F 77 20 6D 61 6E 79 20 77 65 65 6B 73 20 61 72 ow many weeks ar 000240: 65 20 74 68 65 72 65 20 69 6E 20 20 20 36 33 20 e there in 63 000250: 64 61 79 73 3F 1B 39 1B 38 1B 37 1B 31 30 1B 1A days?.9.8.7.10.. 000260: 00 44 69 76 69 64 65 20 37 32 20 62 79 20 38 1B .Divide 72 by 8. 000270: 39 1B 38 1B 31 30 1B 37 1B 5D 00 49 66 20 39 20 9.8.10.7.].If 9 000280: 6D 65 74 72 65 73 20 6F 66 20 66 61 62 72 69 63 metres of fabric 000290: 20 63 6F 73 74 20 20 20 20 60 31 38 2E 35 34 20 cost `18.54 0002A0: 66 69 6E 64 20 74 68 65 20 63 6F 73 74 20 6F 66 find the cost of 0002B0: 20 31 20 20 20 20 20 6D 65 74 72 65 2E 1B 60 32 1 metre..`2 0002C0: 2E 30 36 1B 60 32 2E 31 36 1B 60 32 2E 32 31 1B .06.`2.16.`2.21. 0002D0: 60 32 2E 30 32 1B 3F 00 48 6F 77 20 6D 61 6E 79 `2.02.?.How many 0002E0: 20 63 65 6E 74 69 6D 65 74 72 65 73 20 61 72 65 centimetres are 0002F0: 20 74 68 65 72 65 69 6E 20 68 61 6C 66 20 61 20 therein half a 000300: 6D 65 74 72 65 42 1F 3F 1B 35 30 1B 32 35 1B 31 metreB.?.50.25.1 000310: 30 30 1B 32 35 30 1B 1D 00 44 69 76 69 64 65 20 00.250...Divide 000320: 39 34 20 62 79 20 32 1B 34 37 1B 35 36 1B 34 35 94 by 2.47.56.45 000330: 1B 34 33 1B 80 00 41 20 62 61 67 20 6F 66 20 73 .43...A bag of s 000340: 77 65 65 74 73 20 63 6F 6E 74 61 69 6E 69 6E 67 weets containing 000350: 20 35 36 20 73 77 65 65 74 73 20 77 61 73 20 73 56 sweets was s 000360: 68 61 72 65 64 20 65 71 75 61 6C 6C 79 20 20 20 hared equally 000370: 20 20 62 65 74 77 65 65 6E 20 37 20 63 68 69 6C between 7 chil 000380: 64 72 65 6E 2E 20 48 6F 77 20 6D 61 6E 79 20 20 dren. How many 000390: 73 77 65 65 74 73 20 64 69 64 20 65 61 63 68 20 sweets did each 0003A0: 63 68 69 6C 64 20 68 61 76 65 3F 1B 38 1B 37 1B child have?.8.7. 0003B0: 36 1B 39 1B 34 00 57 68 61 74 20 69 73 20 74 68 6.9.4.What is th 0003C0: 72 65 65 20 71 75 61 72 74 65 72 73 20 6F 66 20 ree quarters of 0003D0: 20 20 20 20 65 69 67 68 74 79 3F 1B 36 30 1B 34 eighty?.60.4 0003E0: 30 1B 32 30 1B 37 30 1B 5B 00 20 20 20 20 20 20 0.20.70.[. 0003F0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000400: 20 20 20 20 20 20 20 30 1A 20 44 69 76 69 64 65 0. Divide 000410: 20 35 39 20 62 79 20 36 20 74 6F 20 74 77 6F 20 59 by 6 to two 000420: 64 65 63 69 6D 61 6C 20 70 6C 61 63 65 73 2E 1B decimal places.. 000430: 39 2E 38 33 1B 39 2E 36 37 1B 38 2E 35 33 1B 31 9.83.9.67.8.53.1 000440: 30 2E 31 32 1B 3B 00 44 69 76 69 64 65 20 38 37 0.12.;.Divide 87 000450: 20 62 79 20 39 20 74 6F 20 74 77 6F 20 64 65 63 by 9 to two dec 000460: 69 6D 61 6C 20 70 6C 61 63 65 73 1B 39 2E 36 37 imal places.9.67 000470: 1B 39 2E 33 34 1B 39 2E 37 38 1B 39 2E 38 33 1B .9.34.9.78.9.83. 000480: 5E 00 20 20 20 20 20 20 20 20 20 20 20 20 20 20 ^. 000490: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0004A0: 44 69 76 69 64 65 20 39 33 20 62 79 20 35 20 74 Divide 93 by 5 t 0004B0: 6F 20 74 77 6F 20 64 65 63 69 6D 61 6C 20 70 6C o two decimal pl 0004C0: 61 63 65 73 2E 1B 31 38 2E 36 30 1B 31 37 2E 35 aces..18.60.17.5 0004D0: 33 1B 31 38 2E 33 31 1B 31 39 2E 32 37 1B 27 00 3.18.31.19.27.'. 0004E0: 57 68 61 74 20 69 73 20 61 20 71 75 61 72 74 65 What is a quarte 0004F0: 72 20 6F 66 20 38 34 3F 1B 32 31 1B 32 34 1B 34 r of 84?.21.24.4 000500: 32 1B 32 38 1B 53 00 41 20 24 7B 62 6F 61 74 20 2.28.S.A ${boat 000510: 74 6F 6F 6B 20 39 36 20 68 6F 75 72 73 20 74 6F took 96 hours to 000520: 20 63 72 6F 73 73 20 74 68 65 20 41 74 6C 61 6E cross the Atlan 000530: 74 69 63 2E 20 48 6F 77 20 6D 61 6E 79 20 64 61 tic. How many da 000540: 79 73 20 20 20 64 69 64 20 69 74 20 74 61 6B 65 ys did it take 000550: 3F 1B 34 1B 36 1B 38 1B 33 1B 3C 00 44 69 76 69 ?.4.6.8.3.<.Divi 000560: 64 65 20 34 33 20 62 79 20 38 20 74 6F 20 74 77 de 43 by 8 to tw 000570: 6F 20 64 65 63 69 6D 61 6C 20 70 6C 61 63 65 73 o decimal places 000580: 2E 1B 35 2E 33 38 1B 34 2E 37 33 1B 36 2E 32 31 ..5.38.4.73.6.21 000590: 1B 35 2E 38 39 1B 5A 00 20 20 20 20 20 20 20 20 .5.89.Z. 0005A0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0005B0: 20 20 20 20 20 20 44 69 76 69 64 65 20 33 37 20 Divide 37 0005C0: 62 79 20 34 20 74 6F 20 74 77 6F 20 64 65 63 69 by 4 to two deci 0005D0: 6D 61 6C 20 70 6C 61 63 65 73 2E 1B 39 2E 32 35 mal places..9.25 0005E0: 1B 39 2E 34 35 1B 39 2E 33 36 1B 39 2E 31 32 1B .9.45.9.36.9.12. 0005F0: 29 00 57 68 61 74 20 69 73 20 61 20 74 68 69 72 ).What is a thir 000600: 64 20 6F 66 20 6E 69 6E 65 74 79 B5 AD 3F 1B 33 d of ninety..?.3 000610: 30 1B 32 30 1B 34 35 1B 36 30 1B 27 00 34 38 20 0.20.45.60.'.48 000620: 6D 6F 6E 74 68 73 20 69 73 20 68 6F 77 20 6D 61 months is how ma 000630: 6E 79 20 79 65 61 72 73 3F 1B 34 1B 35 1B 36 1B ny years?.4.5.6. 000640: 33 1B 3C 00 44 69 76 69 64 65 20 37 31 20 62 79 3.<.Divide 71 by 000650: 20 39 20 74 6F 20 74 77 6F 20 64 65 63 69 6D 61 9 to two decima 000660: 6C 20 70 6C 61 63 65 73 2E 1B 37 2E 38 39 1B 36 l places..7.89.6 000670: 2E 33 32 1B 38 2E 32 35 1B 37 2E 32 33 1B 3B 00 .32.8.25.7.23.;. 000680: 48 6F 77 20 6D 61 6E 79 20 35 30 63 6D 20 6C 65 How many 50cm le 000690: 6E 67 74 68 73 20 61 72 65 20 20 20 20 20 74 68 ngths are th 0006A0: 65 72 65 20 69 6E 20 31 20 6D 65 74 72 65 3F 1B ere in 1 metre?. 0006B0: 32 1B 35 1B 31 30 1B 31 1B 1C 00 00 00 00 00 00 2.5.10.1........ 0006C0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0006D0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0006E0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0006F0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000700: 00 00 00 00 00 00 00 00 00 00 00 00 00 36 D7 FF .............6.. 000710: FF FF FF ...
previousnext* BLOCK 0011 : TURBO LOADING DATA
HEADER
Block Name : AR15
Block Number : 1
Block first : YES
File type : Binaire
File adress start : &6000
File adress length : &0800
File adress execution : &0000
File length file : &08ED

Length of PILOT pulse : 2511
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1315
Length of ONE bit pulse : 2522
Length of PILOT tone : 4096
Used bits in last byte : 8 OK
Data : 263 bytes
Total size : 282 bytes

Sum DATA : 2 262

Duration : 4574 ms
Pause After this block : 18 ms
Duration block + Pause : 4592 ms
Duration block + Pause : 00 h 00 m 04 s		000000: 2C 41 52 31 35 00 00 00 00 00 00 00 00 00 00 00 ,AR15........... 000010: 00 01 00 02 00 08 00 60 FF ED 08 00 00 00 00 00 .......`........ 000020: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000030: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000040: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000050: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000060: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000070: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000080: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000090: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000A0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000B0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000C0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000D0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000E0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000F0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000100: 00 7C DA FF FF FF FF .|.....
previousnext* BLOCK 0012 : TURBO LOADING DATA
DATA
Length of PILOT pulse : 2509
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1332
Length of ONE bit pulse : 2485
Length of PILOT tone : 4096
Used bits in last byte : 8 OK
Data : 2069 bytes
Total size : 2088 bytes

Sum DATA : 162 213

Duration : 20216 ms
Pause After this block : 2696 ms
Duration block + Pause : 22912 ms
Duration block + Pause : 00 h 00 m 22 s		000000: 16 41 52 31 35 00 00 00 00 00 00 00 19 EC 08 00 .AR15........... 000010: 50 6F 74 20 4C 75 63 6B 20 20 20 20 20 20 20 20 Pot Luck 000020: 20 20 20 20 20 20 20 20 20 00 00 00 00 00 00 00 ....... 000030: 00 4E 00 57 72 69 74 65 20 74 68 65 20 6E 75 6D .N.Write the num 000040: 62 65 72 20 65 69 67 68 74 20 68 75 6E 64 72 65 ber eight hundre 000050: 64 61 6E 64 20 6E 69 6E 65 74 79 20 74 68 72 65 dand ninety thre 000060: 65 20 69 6E 20 66 69 67 75 72 65 73 2E 1B 38 39 e in figures..89 000070: 33 1B 39 38 33 1B 33 39 38 1B 38 39 30 33 1B 49 3.983.398.8903.I 000080: 00 49 6E 20 74 68 65 20 6E 75 6D 62 65 72 20 33 .In the number 3 000090: 34 32 20 68 6F 77 20 6D 75 63 68 20 69 73 20 74 42 how much is t 0000A0: 68 65 20 34 20 77 6F 72 74 68 3F 1B 34 20 74 65 he 4 worth?.4 te 0000B0: 6E 73 1B 34 20 68 75 6E 64 72 65 64 73 1B 34 20 ns.4 hundreds.4 0000C0: 75 6E 69 74 73 1B 20 1B 48 00 48 6F 77 20 6D 61 units. .H.How ma 0000D0: 6E 79 20 31 30 70 20 63 6F 69 6E 73 20 68 61 76 ny 10p coins hav 0000E0: 65 20 74 68 65 20 20 20 73 61 6D 65 20 76 61 6C e the same val 0000F0: 75 65 20 61 73 20 6F 6E 65 20 60 31 20 63 6F 69 ue as one `1 coi 000100: 6E E0 66 3F 1B 31 30 1B 31 30 30 1B 35 30 1B 32 n.f?.10.100.50.2 000110: 35 1B 6F 00 48 6F 77 20 69 73 20 74 68 69 73 20 5.o.How is this 000120: 61 6D 6F 75 6E 74 20 77 72 69 74 74 65 6E 20 69 amount written i 000130: 6E 20 6E 75 6D 62 65 72 73 3A 20 73 65 76 65 6E n numbers: seven 000140: 20 70 6F 75 6E 64 20 63 6F 69 6E 73 20 61 6E 64 pound coins and 000150: 74 77 65 6E 74 79 20 74 77 6F 20 70 65 6E 63 65 twenty two pence 000160: 3F 1B 60 37 2E 32 32 1B 37 60 2E 32 32 70 1B 60 ?.`7.22.7`.22p.` 000170: 37 30 2E 32 32 1B 60 37 20 61 6E 64 20 32 32 70 70.22.`7 and 22p 000180: 1B 41 00 48 6F 77 20 6D 61 6E 79 20 6D 69 6C 6C .A.How many mill 000190: 69 6C 69 74 72 65 73 20 61 72 65 20 74 68 65 72 ilitres are ther 0001A0: 65 69 6E 20 31 20 6C 69 74 72 65 3F 1B 31 2C 30 ein 1 litre?.1,0 0001B0: 30 30 1B 35 30 30 1B 31 30 30 1B 31 30 2C 30 30 00.500.100.10,00 0001C0: 30 1B 3F 00 57 68 61 74 20 6E 75 6D 62 65 72 20 0.?.What number 0001D0: 63 6F 6D 65 73 20 62 65 66 6F 72 65 20 20 20 20 comes before 0001E0: 20 20 35 2C 30 30 30 3F 1B 34 2C 39 39 39 1B 34 5,000?.4,999.4 0001F0: 2C 30 30 30 1B 35 2C 39 39 39 1B 34 2C 39 30 30 ,000.5,999.4,900 000200: 1B 48 00 54 9E 48 6F 77 20 6D 75 63 68 20 69 73 .H.T.How much is 000210: 20 74 68 65 20 37 20 77 6F 72 74 68 20 69 6E 20 the 7 worth in 000220: 74 68 65 6E 75 6D 62 65 72 20 37 32 34 3F 1B 37 thenumber 724?.7 000230: 20 68 75 6E 64 72 65 64 73 1B 37 20 74 65 6E 73 hundreds.7 tens 000240: 1B 37 20 75 6E 69 74 73 1B 20 1B 9D 00 52 6F 62 .7 units. ...Rob 000250: 69 6E 20 73 74 61 72 74 65 64 20 70 6C 61 79 69 in started playi 000260: 6E 67 20 74 68 65 20 20 20 20 20 70 69 61 6E 6F ng the piano 000270: 20 61 74 20 34 2E 32 33 20 70 2E 6D 2E 20 61 6E at 4.23 p.m. an 000280: 64 20 20 20 20 20 20 20 20 66 69 6E 69 73 68 65 d finishe 000290: 64 20 61 74 20 35 2E 30 34 20 70 2E 6D 2E 20 46 d at 5.04 p.m. F 0002A0: 6F 72 20 68 6F 77 20 6C 6F 6E 67 20 77 61 73 20 or how long was 0002B0: 68 65 20 70 6C 61 79 69 6E 67 3F 1B 34 31 20 6D he playing?.41 m 0002C0: 69 6E 75 74 65 73 1B 33 33 20 6D 69 6E 75 74 65 inutes.33 minute 0002D0: 73 1B 34 37 20 6D 69 6E 75 74 65 73 1B 33 39 20 s.47 minutes.39 0002E0: 6D 69 6E 75 74 65 73 1B 60 00 53 61 72 61 68 20 minutes.`.Sarah 0002F0: 77 61 73 20 62 6F 72 6E 20 6F 6E 20 31 32 74 68 was born on 12th 000300: 20 4D 61 79 2C 64 E6 20 20 20 31 39 37 39 2E 20 May,d. 1979. 000310: 48 6F 77 20 6F 6C 64 20 77 69 6C 6C 20 73 68 65 How old will she 000320: 20 62 65 20 6F 6E 20 20 68 65 72 20 62 69 72 74 be on her birt 000330: 68 64 61 79 20 69 6E 20 31 39 39 33 3F 1B 31 34 hday in 1993?.14 000340: 1B 31 37 1B 31 32 1B 31 35 1B 47 00 48 6F 77 20 .17.12.15.G.How 000350: 6D 61 6E 79 20 35 70 20 63 6F 69 6E 73 20 68 61 many 5p coins ha 000360: 76 65 20 74 68 65 20 20 20 20 73 61 6D 65 20 76 ve the same v 000370: 61 6C 75 65 20 61 73 20 6F 6E 65 20 60 31 20 63 alue as one `1 c 000380: 6F 69 6E 3F 1B 32 30 1B 33 30 1B 31 30 1B 35 30 oin?.20.30.10.50 000390: 1B A9 00 50 68 69 6C 69 70 20 61 72 72 69 76 65 ...Philip arrive 0003A0: 64 20 61 74 20 73 63 68 6F 6F 6C 20 61 74 20 20 d at school at 0003B0: 20 38 2E 34 37 61 2E 6D 2E 20 61 6E 64 20 6C 65 8.47a.m. and le 0003C0: 66 74 20 61 74 20 33 2E 33 36 70 2E 6D 2E 20 46 ft at 3.36p.m. F 0003D0: 6F 72 20 68 6F 77 20 6C 6F 6E 67 20 77 61 73 20 or how long was 0003E0: 68 65 20 61 74 20 73 63 68 6F 6F 6C 3F 1B 36 20 he at school?.6 0003F0: 68 6F 75 72 73 20 34 39 20 6D 69 6E 75 74 65 73 hours 49 minutes 000400: 1B 36 20 68 6F 75 72 B5 01 73 20 33 32 20 6D 69 .6 hour..s 32 mi 000410: 6E 75 74 65 73 1B 35 20 68 6F 75 72 73 20 35 37 nutes.5 hours 57 000420: 20 6D 69 6E 75 74 65 73 1B 35 20 68 6F 75 72 73 minutes.5 hours 000430: 20 34 33 20 6D 69 6E 75 74 65 73 1B 44 00 48 6F 43 minutes.D.Ho 000440: 77 20 6D 61 6E 79 20 31 30 70 20 63 6F 69 6E 73 w many 10p coins 000450: 20 68 61 76 65 20 74 68 65 20 20 20 73 61 6D 65 have the same 000460: 20 76 61 6C 75 65 20 61 73 20 61 20 60 35 20 6E value as a `5 n 000470: 6F 74 65 3F 1B 35 30 1B 35 1B 31 30 1B 32 35 1B ote?.50.5.10.25. 000480: 6A 00 48 6F 77 20 69 73 20 74 68 69 73 20 61 6D j.How is this am 000490: 6F 75 6E 74 20 77 72 69 74 74 65 6E 20 69 6E 20 ount written in 0004A0: 66 69 67 75 72 65 73 3A 20 65 69 67 68 74 65 65 figures: eightee 0004B0: 6E 20 70 6F 75 6E 64 73 20 61 6E 64 20 20 74 68 n pounds and th 0004C0: 72 65 65 20 70 65 6E 63 65 3F 1B 60 31 38 2E 30 ree pence?.`18.0 0004D0: 33 1B 60 31 38 2E 33 1B 60 31 38 2E 33 30 1B 60 3.`18.3.`18.30.` 0004E0: 31 38 20 61 6E 64 20 33 70 1B 49 00 49 6E 20 74 18 and 3p.I.In t 0004F0: 68 65 20 6E 75 6D 62 65 72 20 34 38 32 20 68 6F he number 482 ho 000500: 77 20 6D 75 63 68 20 69 73 0D 72 20 74 68 65 20 w much is.r the 000510: 32 20 77 6F 72 74 68 3F 1B 32 20 75 6E 69 74 73 2 worth?.2 units 000520: 1B 32 20 74 65 6E 73 1B 32 20 68 75 6E 64 72 65 .2 tens.2 hundre 000530: 64 73 1B 20 1B 60 00 53 69 6D 6F 6E 20 77 61 73 ds. .`.Simon was 000540: 20 62 6F 72 6E 20 6F 6E 20 36 74 68 20 4A 75 6E born on 6th Jun 000550: 65 2C 20 20 20 31 39 36 37 2E 20 48 6F 77 20 6F e, 1967. How o 000560: 6C 64 20 77 69 6C 6C 20 62 65 20 62 65 20 6F 6E ld will be be on 000570: 20 20 20 68 69 73 20 62 69 72 74 68 64 61 79 20 his birthday 000580: 69 6E 20 32 30 30 33 3F 1B 33 36 1B 33 31 1B 33 in 2003?.36.31.3 000590: 33 1B 33 37 1B 48 00 48 6F 77 20 6D 61 6E 79 20 3.37.H.How many 0005A0: 6D 69 6C 6C 69 6C 69 74 72 65 73 20 61 72 65 20 millilitres are 0005B0: 74 68 65 72 65 69 6E 20 61 20 71 75 61 72 74 65 therein a quarte 0005C0: 72 20 6F 66 20 61 20 6C 69 74 72 65 3F 1B 32 35 r of a litre?.25 0005D0: 30 1B 35 30 30 1B 32 35 1B 31 32 35 1B 60 00 57 0.500.25.125.`.W 0005E0: 68 61 74 20 69 73 20 74 68 65 20 6D 69 73 73 69 hat is the missi 0005F0: 6E 67 20 6E 75 6D 62 65 72 20 69 6E 20 74 68 69 ng number in thi 000600: 73 20 73 65 71 75 65 6E 63 65 3A F9 FC 20 20 20 s sequence:.. 000610: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000620: 31 37 2C 20 33 39 2C 20 36 31 2C 20 3F 2C 20 31 17, 39, 61, ?, 1 000630: 30 35 1B 38 33 1B 37 39 1B 38 37 1B 38 35 1B 43 05.83.79.87.85.C 000640: 00 57 68 69 63 68 20 63 6F 69 6E 20 68 61 73 20 .Which coin has 000650: 74 68 65 20 73 61 6D 65 20 76 61 6C 75 65 20 61 the same value a 000660: 73 20 74 77 65 6E 74 79 20 31 70 20 63 6F 69 6E s twenty 1p coin 000670: 73 3F 1B 32 30 70 1B 31 30 70 1B 35 30 70 1B 60 s?.20p.10p.50p.` 000680: 31 1B 5D 00 48 6F 77 20 6D 61 6E 79 20 68 6F 75 1.].How many hou 000690: 72 73 20 61 72 65 20 74 68 65 72 65 20 20 20 20 rs are there 0006A0: 20 20 62 65 74 77 65 65 6E 20 31 31 20 61 2E 6D between 11 a.m 0006B0: 2E 20 6F 6E 20 4D 6F 6E 64 61 79 20 61 6E 64 20 . on Monday and 0006C0: 33 20 70 2E 6D 2E 20 6F 6E 20 54 75 65 73 64 61 3 p.m. on Tuesda 0006D0: 79 3F 1B 32 38 1B 31 34 1B 33 32 1B 32 32 1B 4A y?.28.14.32.22.J 0006E0: 00 57 68 61 74 20 61 6D 6F 75 6E 74 20 69 73 20 .What amount is 0006F0: 6F 6E 65 20 70 65 6E 6E 79 20 6C 65 73 73 20 74 one penny less t 000700: 68 61 6E 20 66 6F 75 72 20 70 6F 75 6E DF DF 64 han four poun..d 000710: 73 3F 1B 60 33 2E 39 39 1B 60 33 2E 30 30 1B 60 s?.`3.99.`3.00.` 000720: 34 2E 30 31 1B 60 34 2E 39 39 1B 41 00 48 6F 77 4.01.`4.99.A.How 000730: 20 6D 61 6E 79 20 63 65 6E 74 69 6D 65 74 72 65 many centimetre 000740: 73 20 61 72 65 20 74 68 65 72 65 69 6E 20 38 20 s are therein 8 000750: 6D 65 74 72 65 73 3F 1B 38 30 30 1B 38 2C 30 30 metres?.800.8,00 000760: 30 1B 34 2C 30 30 30 1B 35 30 30 1B 48 00 48 6F 0.4,000.500.H.Ho 000770: 77 20 6D 75 63 68 20 69 73 20 74 68 65 20 39 20 w much is the 9 000780: 77 6F 72 74 68 20 69 6E 20 74 68 65 6E 75 6D 62 worth in thenumb 000790: 65 72 20 38 39 34 3F 1B 39 20 74 65 6E 73 1B 39 er 894?.9 tens.9 0007A0: 20 75 6E 69 74 73 1B 39 20 68 75 6E 64 72 65 64 units.9 hundred 0007B0: 73 1B 20 1B 9A 00 45 6D 69 6C 79 27 73 20 77 61 s. ...Emily's wa 0007C0: 74 63 68 20 73 68 6F 77 73 20 74 68 65 20 74 69 tch shows the ti 0007D0: 6D 65 20 20 69 73 20 38 2E 34 32 20 61 2E 6D 2E me is 8.42 a.m. 0007E0: 20 62 75 74 20 69 74 20 69 73 20 32 33 20 20 20 but it is 23 0007F0: 20 20 6D 69 6E 75 74 65 73 20 73 6C 6F 77 2E 20 minutes slow. 000800: 57 68 61 74 20 69 73 20 74 68 65 20 20 20 20 E5 What is the . 000810: 38 FF FF FF FF 8....
previousnext* BLOCK 0013 : TURBO LOADING DATA
HEADER
Block Name : AR15
Block Number : 2
Block last : YES
File type : Binaire
File adress start : &6800
File adress length : &00ED
File adress execution : &0000
File length file : &08ED

Length of PILOT pulse : 2511
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1316
Length of ONE bit pulse : 2521
Length of PILOT tone : 4096
Used bits in last byte : 8 OK
Data : 263 bytes
Total size : 282 bytes

Sum DATA : 2 407

Duration : 4578 ms
Pause After this block : 18 ms
Duration block + Pause : 4596 ms
Duration block + Pause : 00 h 00 m 04 s		000000: 2C 41 52 31 35 00 00 00 00 00 00 00 00 00 00 00 ,AR15........... 000010: 00 02 FF 02 ED 00 00 68 00 ED 08 00 00 00 00 00 .......h........ 000020: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000030: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000040: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000050: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000060: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000070: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000080: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000090: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000A0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000B0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000C0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000D0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000E0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000F0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000100: 00 86 73 FF FF FF FF ..s....
previousnext* BLOCK 0014 : TURBO LOADING DATA
DATA
Length of PILOT pulse : 2510
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1330
Length of ONE bit pulse : 2488
Length of PILOT tone : 4096
Used bits in last byte : 8 OK
Data : 263 bytes
Total size : 282 bytes

Sum DATA : 17 186

Duration : 5073 ms
Pause After this block : 13446 ms
Duration block + Pause : 18519 ms
Duration block + Pause : 00 h 00 m 18 s		000000: 16 20 63 6F 72 72 65 63 74 20 74 69 6D 65 3F 20 . correct time? 000010: 20 20 20 20 20 20 20 1B 39 2E 30 35 20 61 2E 6D .9.05 a.m 000020: 2E 1B 38 2E 31 39 20 61 2E 6D 2E 1B 38 2E 35 37 ..8.19 a.m..8.57 000030: 20 61 2E 6D 2E 1B 39 2E 30 37 20 70 2E 6D 2E 1B a.m..9.07 p.m.. 000040: 49 00 48 6F 77 20 6D 61 6E 79 20 32 70 20 63 6F I.How many 2p co 000050: 69 6E 73 20 68 61 76 65 20 74 68 65 20 20 20 20 ins have the 000060: 73 61 6D 65 20 76 61 6C 75 65 20 61 73 20 6F 6E same value as on 000070: 65 20 35 30 70 20 63 6F 69 6E 3F 1B 32 35 1B 31 e 50p coin?.25.1 000080: 30 30 1B 35 30 1B 31 30 1B 64 00 57 68 61 74 20 00.50.10.d.What 000090: 69 73 20 74 68 65 20 6D 69 73 73 69 6E 67 20 6E is the missing n 0000A0: 75 6D 62 65 72 20 69 6E 20 74 68 69 73 20 73 65 umber in this se 0000B0: 71 75 65 6E 63 65 3A 20 20 20 20 20 20 20 20 20 quence: 0000C0: 20 20 20 20 20 20 20 31 33 34 2C 20 31 34 39 2C 134, 149, 0000D0: 20 31 36 34 2C 20 3F 2C 20 31 39 34 1B 31 37 39 164, ?, 194.179 0000E0: 1B 31 37 35 1B 31 38 35 1B 31 38 31 1B 1C 00 00 .175.185.181.... 0000F0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000100: 00 D1 2A FF FF FF FF ..*....
previousnext* BLOCK 0015 : TURBO LOADING DATA
HEADER
Block Name : AR16
Block Number : 1
Block first : YES
File type : Binaire
File adress start : &6000
File adress length : &0800
File adress execution : &0000
File length file : &08F3

Length of PILOT pulse : 2509
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1314
Length of ONE bit pulse : 2520
Length of PILOT tone : 4098
Used bits in last byte : 8 OK
Data : 263 bytes
Total size : 282 bytes

Sum DATA : 2 194

Duration : 4570 ms
Pause After this block : 35 ms
Duration block + Pause : 4605 ms
Duration block + Pause : 00 h 00 m 04 s		000000: 2C 41 52 31 36 00 00 00 00 00 00 00 00 00 00 00 ,AR16........... 000010: 00 01 00 02 00 08 00 60 FF F3 08 00 00 00 00 00 .......`........ 000020: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000030: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000040: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000050: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000060: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000070: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000080: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000090: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000A0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000B0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000C0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000D0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000E0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000F0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000100: 00 E5 26 FF FF FF FF ..&....
previousnext* BLOCK 0016 : TURBO LOADING DATA
DATA
Length of PILOT pulse : 2509
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1319
Length of ONE bit pulse : 2503
Length of PILOT tone : 4074
Used bits in last byte : 8 OK
Data : 2069 bytes
Total size : 2088 bytes

Sum DATA : 107 084

Duration : 19070 ms
Pause After this block : 2696 ms
Duration block + Pause : 21766 ms
Duration block + Pause : 00 h 00 m 21 s		000000: 16 41 52 31 36 00 00 00 00 00 00 00 19 F2 08 00 .AR16........... 000010: 41 64 64 69 74 69 6F 6E 20 2D 20 54 68 48 54 55 Addition - ThHTU 000020: 20 20 20 20 20 20 20 20 20 00 00 00 00 00 00 00 ....... 000030: 00 49 00 20 20 20 20 20 20 20 20 20 20 20 20 20 .I. 000040: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000050: 20 31 36 31 32 20 2B 20 33 32 37 20 2B 20 31 30 1612 + 327 + 10 000060: 39 20 3D 20 3F 1B 32 30 34 38 1B 32 33 36 35 1B 9 = ?.2048.2365. 000070: 31 39 30 37 1B 32 31 34 35 1B 4E 00 20 20 20 20 1907.2145.N. 000080: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000090: 20 20 20 20 20 20 20 20 20 20 34 36 30 32 20 2B 4602 + 0000A0: 20 32 33 34 36 20 2B 20 33 31 30 32 20 3D 20 3F 2346 + 3102 = ? 0000B0: 1B 31 30 30 35 30 1B 39 38 39 35 1B 31 31 32 34 .10050.9895.1124 0000C0: 33 1B 31 30 39 37 38 1B 77 00 41 64 64 20 6F 6E 3.10978.w.Add on 0000D0: 65 20 74 68 6F 75 73 61 6E 64 20 66 6F 75 72 20 e thousand four 0000E0: 68 75 6E 64 72 65 64 20 61 6E 64 20 66 69 66 74 hundred and fift 0000F0: 79 20 74 77 6F 20 74 6F 20 74 68 72 65 65 20 20 y two to three 000100: 20 17 4C 20 20 20 20 20 74 68 6F 75 73 61 6E 64 .L thousand 000110: 20 74 68 72 65 65 20 68 75 6E 64 72 65 64 20 61 three hundred a 000120: 6E 64 20 20 20 20 74 68 72 65 65 2E 1B 34 37 35 nd three..475 000130: 35 1B 34 37 38 32 1B 34 36 35 39 1B 34 38 31 32 5.4782.4659.4812 000140: 1B 66 00 46 69 6E 64 20 74 68 65 20 74 6F 74 61 .f.Find the tota 000150: 6C 20 6F 66 20 74 77 6F 20 74 68 6F 75 73 61 6E l of two thousan 000160: 64 61 6E 64 20 74 77 6F 2C 20 74 77 65 6E 74 79 dand two, twenty 000170: 20 74 77 6F 2C 20 74 77 6F 20 20 20 20 20 20 68 two, two h 000180: 75 6E 64 72 65 64 20 61 6E 64 20 74 77 65 6C 76 undred and twelv 000190: 65 2E 1B 32 32 33 36 1B 32 32 35 34 1B 32 32 32 e..2236.2254.222 0001A0: 32 1B 32 32 31 34 1B 5E 00 20 20 20 20 20 20 20 2.2214.^. 0001B0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0001C0: 20 20 20 20 20 20 20 35 32 36 67 20 2B 20 39 32 526g + 92 0001D0: 38 67 20 2B 20 31 32 33 67 20 2B 20 38 67 20 3D 8g + 123g + 8g = 0001E0: 20 3F 6B 67 1B 31 2E 35 38 35 6B 67 1B 31 2E 33 ?kg.1.585kg.1.3 0001F0: 35 36 6B 67 1B 31 35 2E 38 35 6B 67 1B 31 33 2E 56kg.15.85kg.13. 000200: 35 36 6B 76 59 67 1B 5A 00 20 20 20 20 20 20 20 56kvYg.Z. 000210: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000220: 20 20 20 20 20 20 20 20 20 36 30 2E 36 32 33 20 60.623 000230: 2B 20 33 2E 31 30 37 20 2B 20 35 2E 39 32 20 3D + 3.107 + 5.92 = 000240: 20 3F 20 20 20 20 20 20 1B 36 39 2E 36 35 1B 37 ? .69.65.7 000250: 30 2E 33 34 1B 36 37 2E 37 38 1B 36 38 2E 39 35 0.34.67.78.68.95 000260: 1B 51 00 20 20 20 20 20 20 20 20 20 20 20 20 20 .Q. 000270: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000280: 20 31 30 30 30 33 20 2B 20 31 31 39 38 32 20 2B 10003 + 11982 + 000290: 20 31 36 39 34 20 3D 20 3F 1B 32 33 36 37 39 1B 1694 = ?.23679. 0002A0: 32 32 37 38 39 1B 32 34 35 33 34 1B 32 31 32 31 22789.24534.2121 0002B0: 32 1B 55 00 20 20 20 20 20 20 20 20 20 20 20 20 2.U. 0002C0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0002D0: 20 20 39 32 31 30 20 2B 20 33 31 38 30 20 2B 20 9210 + 3180 + 0002E0: 31 32 34 30 20 2B 20 38 30 31 20 3D 20 3F 1B 31 1240 + 801 = ?.1 0002F0: 34 34 33 31 1B 31 34 36 37 35 1B 31 34 33 32 35 4431.14675.14325 000300: 1B 31 34 37 36 38 C1 38 1B 4F 00 20 20 20 20 20 .14768.8.O. 000310: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000320: 20 20 20 20 20 20 20 20 20 35 37 31 32 20 2B 20 5712 + 000330: 32 31 36 33 20 2B 20 31 36 31 20 2B 20 39 38 20 2163 + 161 + 98 000340: 3D 20 3F 1B 38 31 33 34 1B 37 39 39 38 1B 38 39 = ?.8134.7998.89 000350: 36 34 1B 39 30 30 31 1B 4C 00 20 20 20 20 20 20 64.9001.L. 000360: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000370: 20 20 20 20 20 20 20 20 33 36 33 20 2B 20 36 33 363 + 63 000380: 20 2B 20 36 33 36 33 20 2B 20 33 20 3D 20 3F 1B + 6363 + 3 = ?. 000390: 36 37 39 32 1B 36 39 37 32 1B 37 30 31 32 1B 36 6792.6972.7012.6 0003A0: 36 35 32 1B 53 00 20 20 20 20 20 20 20 20 20 20 652.S. 0003B0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0003C0: 20 20 20 20 39 2E 31 30 32 20 2B 20 30 2E 32 32 9.102 + 0.22 0003D0: 32 20 2B 20 31 2E 31 20 3D 20 3F 1B 31 30 2E 34 2 + 1.1 = ?.10.4 0003E0: 32 34 1B 39 2E 33 33 35 1B 31 30 2E 33 32 31 1B 24.9.335.10.321. 0003F0: 31 30 2E 31 35 33 1B 58 00 20 20 20 20 20 20 20 10.153.X. 000400: 20 20 20 20 20 20 20 3C 08 20 20 20 20 20 20 20 <. 000410: 20 20 20 20 20 20 20 20 20 30 2E 30 30 31 36 20 0.0016 000420: 2B 20 30 2E 30 38 32 37 20 2B 20 30 2E 39 31 36 + 0.0827 + 0.916 000430: 20 3D 20 3F 1B 31 2E 30 30 30 33 1B 30 2E 30 39 = ?.1.0003.0.09 000440: 37 36 1B 30 2E 30 30 39 37 1B 30 2E 39 37 38 33 76.0.0097.0.9783 000450: 1B 50 00 20 20 20 20 20 20 20 20 20 20 20 20 20 .P. 000460: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000470: 20 36 20 2B 20 30 2E 36 20 2B 20 30 2E 30 36 20 6 + 0.6 + 0.06 000480: 2B 20 36 2E 30 36 20 3D 20 3F 1B 31 32 2E 37 32 + 6.06 = ?.12.72 000490: 1B 37 2E 33 32 1B 36 2E 32 34 1B 31 30 2E 35 36 .7.32.6.24.10.56 0004A0: 1B 49 00 20 20 20 20 20 20 20 20 20 20 20 20 20 .I. 0004B0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0004C0: 20 31 38 37 36 20 2B 20 38 31 32 20 2B 20 32 36 1876 + 812 + 26 0004D0: 37 20 3D 20 3F 1B 32 39 35 35 1B 32 39 33 31 1B 7 = ?.2955.2931. 0004E0: 32 39 37 36 1B 32 39 36 34 1B 6E 00 57 68 61 74 2976.2964.n.What 0004F0: 20 69 73 20 74 68 65 20 6D 69 73 73 69 6E 67 20 is the missing 000500: 6E 75 6D 62 65 72 3F 20 20 E5 A5 20 20 20 20 20 number? .. 000510: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000520: 20 20 20 20 20 20 20 20 20 20 20 20 20 35 36 31 561 000530: 32 20 2B 20 3F 20 2B 20 37 38 31 39 20 3D 20 31 2 + ? + 7819 = 1 000540: 39 38 30 32 20 1B 36 33 37 31 1B 35 39 38 36 1B 9802 .6371.5986. 000550: 37 34 33 39 1B 36 39 38 34 1B 71 00 57 68 61 74 7439.6984.q.What 000560: 20 69 73 20 74 68 65 20 6D 69 73 73 69 6E 67 20 is the missing 000570: 6E 75 6D 62 65 72 3F 20 20 20 20 20 20 20 20 20 number? 000580: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000590: 20 20 20 20 20 20 20 20 20 3F 20 2B 20 39 32 31 ? + 921 0005A0: 36 20 2B 20 32 37 20 2B 20 31 32 34 20 3D 20 31 6 + 27 + 124 = 1 0005B0: 32 33 36 38 20 20 1B 33 30 30 31 1B 32 37 39 35 2368 .3001.2795 0005C0: 1B 33 32 33 36 1B 32 39 38 31 1B 4F 00 20 20 20 .3236.2981.O. 0005D0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0005E0: 20 20 20 20 20 20 20 20 20 20 20 36 31 30 32 20 6102 0005F0: 2B 20 37 38 32 36 20 2B 20 31 36 37 31 20 3D 20 + 7826 + 1671 = 000600: 3F 1B 31 35 35 39 39 1B 31 34 38 A5 FE 37 39 1B ?.15599.148..79. 000610: 31 35 32 33 31 1B 31 35 36 32 31 1B 4B 00 20 20 15231.15621.K. 000620: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000630: 20 20 20 20 20 20 20 20 20 20 20 20 32 35 39 32 2592 000640: 20 2B 20 33 31 39 32 20 2B 20 3F 20 3D 20 38 30 + 3192 + ? = 80 000650: 30 36 1B 32 32 32 32 1B 33 31 32 34 1B 32 36 34 06.2222.3124.264 000660: 33 1B 32 38 31 39 1B 79 00 57 68 61 74 20 69 73 3.2819.y.What is 000670: 20 74 68 65 20 74 6F 74 61 6C 20 63 6F 73 74 20 the total cost 000680: 6F 66 20 61 20 20 20 63 6F 61 74 20 61 74 20 60 of a coat at ` 000690: 32 31 2E 32 37 2C 20 61 20 68 61 74 20 61 74 20 21.27, a hat at 0006A0: 60 33 2E 31 39 61 6E 64 20 61 20 70 61 69 72 20 `3.19and a pair 0006B0: 6F 66 20 73 68 6F 65 73 20 61 74 20 60 31 37 2E of shoes at `17. 0006C0: 32 36 3F 1B 60 34 31 2E 37 32 1B 60 33 39 2E 31 26?.`41.72.`39.1 0006D0: 32 1B 60 34 33 2E 31 32 1B 60 34 30 2E 32 32 1B 2.`43.12.`40.22. 0006E0: 58 00 46 69 6E 64 20 74 68 65 20 6D 69 73 73 69 X.Find the missi 0006F0: 6E 67 20 6E 75 6D 62 65 72 3A 20 20 20 20 20 20 ng number: 000700: 20 20 20 20 20 20 20 20 20 20 20 20 20 D8 8D 20 .. 000710: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000720: 32 3F 39 38 20 2B 20 32 32 31 20 3D 20 32 39 31 2?98 + 221 = 291 000730: 39 1B 36 1B 38 1B 33 1B 39 1B 5A 00 46 69 6E 64 9.6.8.3.9.Z.Find 000740: 20 74 68 65 20 6D 69 73 73 69 6E 67 20 6E 75 6D the missing num 000750: 62 65 72 3A 20 20 20 20 20 20 20 20 20 20 20 20 ber: 000760: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000770: 20 20 20 20 20 20 20 20 35 32 31 38 20 2B 20 34 5218 + 4 000780: 38 3F 32 20 3D 20 31 30 31 31 30 1B 39 1B 37 1B 8?2 = 10110.9.7. 000790: 36 1B 33 1B 50 00 20 20 20 20 20 20 20 20 20 20 6.3.P. 0007A0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0007B0: 20 20 20 20 34 2E 36 39 31 20 2B 20 30 2E 39 30 4.691 + 0.90 0007C0: 31 20 2B 20 35 20 3D 20 3F 1B 31 30 2E 35 39 32 1 + 5 = ?.10.592 0007D0: 1B 39 2E 35 37 32 1B 39 2E 39 33 36 1B 31 30 2E .9.572.9.936.10. 0007E0: 33 36 38 1B 7E 00 41 64 64 20 74 77 6F 20 74 68 368.~.Add two th 0007F0: 6F 75 73 61 6E 64 20 74 68 72 65 65 20 68 75 6E ousand three hun 000800: 64 72 65 64 61 6E 64 20 74 77 65 6E 74 79 20 15 dredand twenty . 000810: 13 FF FF FF FF .....
previousnext* BLOCK 0017 : TURBO LOADING DATA
HEADER
Block Name : AR16
Block Number : 2
Block last : YES
File type : Binaire
File adress start : &6800
File adress length : &00F3
File adress execution : &0000
File length file : &08F3

Length of PILOT pulse : 2511
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1321
Length of ONE bit pulse : 2389
Length of PILOT tone : 4096
Used bits in last byte : 8 OK
Data : 263 bytes
Total size : 282 bytes

Sum DATA : 2 559

Duration : 4577 ms
Pause After this block : 33 ms
Duration block + Pause : 4610 ms
Duration block + Pause : 00 h 00 m 04 s		000000: 2C 41 52 31 36 00 00 00 00 00 00 00 00 00 00 00 ,AR16........... 000010: 00 02 FF 02 F3 00 00 68 00 F3 08 00 00 00 00 00 .......h........ 000020: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000030: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000040: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000050: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000060: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000070: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000080: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000090: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000A0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000B0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000C0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000D0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000E0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000F0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000100: 00 A1 E3 FF FF FF FF .......
previousnext* BLOCK 0018 : TURBO LOADING DATA
DATA
Length of PILOT pulse : 2512
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1323
Length of ONE bit pulse : 2499
Length of PILOT tone : 4096
Used bits in last byte : 8 OK
Data : 263 bytes
Total size : 282 bytes

Sum DATA : 13 866

Duration : 4997 ms
Pause After this block : 13851 ms
Duration block + Pause : 18848 ms
Duration block + Pause : 00 h 00 m 18 s		000000: 16 74 77 6F 20 74 6F 20 66 69 76 65 20 20 20 20 .two to five 000010: 20 20 20 20 74 68 6F 75 73 61 6E 64 20 74 77 6F thousand two 000020: 20 68 75 6E 64 72 65 64 20 61 6E 64 20 20 20 20 hundred and 000030: 20 20 74 68 69 72 74 79 20 74 68 72 65 65 2E 1B thirty three.. 000040: 37 35 35 35 1B 37 33 35 32 1B 37 36 34 38 1B 37 7555.7352.7648.7 000050: 34 35 33 1B 4F 00 20 20 20 20 20 20 20 20 20 20 453.O. 000060: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000070: 20 20 20 20 38 30 30 31 20 2B 20 32 30 30 31 20 8001 + 2001 000080: 2B 20 33 31 30 30 20 3D 20 3F 1B 31 33 31 30 32 + 3100 = ?.13102 000090: 1B 31 33 32 34 33 1B 31 33 31 37 35 1B 31 33 30 .13243.13175.130 0000A0: 38 37 1B 50 00 20 20 20 20 20 20 20 20 20 20 20 87.P. 0000B0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0000C0: 20 20 20 36 2E 32 33 20 2B 20 31 2E 38 37 20 2B 6.23 + 1.87 + 0000D0: 20 30 2E 30 30 33 20 3D 20 3F 1B 38 2E 31 30 33 0.003 = ?.8.103 0000E0: 1B 37 2E 38 35 39 1B 38 2E 32 31 32 1B 38 2E 30 .7.859.8.212.8.0 0000F0: 30 32 1B 1C 00 00 00 00 00 00 00 00 00 00 00 00 02.............. 000100: 00 29 B2 FF FF FF FF .).....
previousnext* BLOCK 0019 : TURBO LOADING DATA
HEADER
Block Name : AR17
Block Number : 1
Block first : YES
File type : Binaire
File adress start : &6000
File adress length : &0800
File adress execution : &0000
File length file : &08B2

Length of PILOT pulse : 2509
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1316
Length of ONE bit pulse : 2521
Length of PILOT tone : 4097
Used bits in last byte : 8 OK
Data : 263 bytes
Total size : 282 bytes

Sum DATA : 2 222

Duration : 4572 ms
Pause After this block : 17 ms
Duration block + Pause : 4589 ms
Duration block + Pause : 00 h 00 m 04 s		000000: 2C 41 52 31 37 00 00 00 00 00 00 00 00 00 00 00 ,AR17........... 000010: 00 01 00 02 00 08 00 60 FF B2 08 00 00 00 00 00 .......`........ 000020: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000030: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000040: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000050: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000060: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000070: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000080: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000090: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000A0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000B0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000C0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000D0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000E0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000F0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000100: 00 B2 B5 FF FF FF FF .......
previousnext* BLOCK 0020 : TURBO LOADING DATA
DATA
Length of PILOT pulse : 2510
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1327
Length of ONE bit pulse : 2487
Length of PILOT tone : 4097
Used bits in last byte : 8 OK
Data : 2069 bytes
Total size : 2088 bytes

Sum DATA : 115 207

Duration : 19200 ms
Pause After this block : 2696 ms
Duration block + Pause : 21896 ms
Duration block + Pause : 00 h 00 m 21 s		000000: 16 41 52 31 37 00 00 00 00 00 00 00 19 B1 08 00 .AR17........... 000010: 53 75 62 74 72 61 63 74 69 6F 6E 20 2D 20 54 68 Subtraction - Th 000020: 48 54 55 20 20 20 20 20 20 00 00 00 00 00 00 00 HTU ....... 000030: 00 44 00 20 20 20 20 20 20 20 20 20 20 20 20 20 .D. 000040: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000050: 20 36 32 33 31 20 2D 20 33 31 30 36 20 3D 20 3F 6231 - 3106 = ? 000060: 1B 33 31 32 35 1B 39 33 33 37 1B 33 32 31 34 1B .3125.9337.3214. 000070: 33 30 38 39 1B 5C 00 20 20 20 20 20 20 20 20 20 3089.\. 000080: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000090: 20 20 20 20 20 60 39 39 39 31 2E 34 35 20 2D 20 `9991.45 - 0000A0: 60 34 32 36 39 2E 38 36 20 3D 20 3F 1B 60 35 37 `4269.86 = ?.`57 0000B0: 32 31 2E 35 39 1B 60 35 36 38 39 2E 33 34 1B 60 21.59.`5689.34.` 0000C0: 35 37 38 33 2E 38 37 1B 60 35 36 39 37 2E 32 34 5783.87.`5697.24 0000D0: 1B 82 00 44 61 76 69 64 20 62 6F 75 67 68 74 20 ...David bought 0000E0: 61 20 6B 69 74 65 20 63 6F 73 74 69 6E 67 20 20 a kite costing 0000F0: 20 60 34 2E 32 31 20 61 6E 64 20 61 20 72 65 63 `4.21 and a rec 000100: 6F C4 E0 72 64 20 63 6F 73 74 69 6E 67 20 20 20 o..rd costing 000110: 20 60 34 2E 31 32 2E 20 48 6F 77 20 6D 75 63 68 `4.12. How much 000120: 20 63 68 61 6E 67 65 20 64 69 64 20 68 65 20 67 change did he g 000130: 65 74 20 66 72 6F 6D 20 60 31 30 3F 1B 60 31 2E et from `10?.`1. 000140: 36 37 1B 60 31 2E 32 33 1B 60 31 2E 39 37 1B 60 67.`1.23.`1.97.` 000150: 32 2E 33 37 1B 44 00 20 20 20 20 20 20 20 20 20 2.37.D. 000160: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000170: 20 20 20 20 20 39 38 32 31 20 2D 20 36 37 31 38 9821 - 6718 000180: 20 3D 20 3F 1B 33 31 30 33 1B 33 31 32 31 1B 33 = ?.3103.3121.3 000190: 30 38 39 1B 33 32 31 32 1B 69 00 53 75 62 74 72 089.3212.i.Subtr 0001A0: 61 63 74 20 74 68 65 20 73 6D 61 6C 6C 65 72 20 act the smaller 0001B0: 6E 75 6D 62 65 72 20 20 20 66 72 6F 6D 20 74 68 number from th 0001C0: 65 20 6C 61 72 67 65 72 3A 20 20 20 20 20 20 20 e larger: 0001D0: 20 20 20 20 20 20 20 20 20 20 33 2E 30 35 36 20 3.056 0001E0: 61 6E 64 20 33 2E 38 32 31 1B 30 2E 37 36 35 1B and 3.821.0.765. 0001F0: 30 2E 36 34 38 1B 30 2E 38 37 33 1B 30 2E 35 34 0.648.0.873.0.54 000200: 39 1B 5D D3 BD 00 46 69 6E 64 20 74 68 65 20 6D 9.]...Find the m 000210: 69 73 73 69 6E 67 20 6E 75 6D 62 65 72 3A 20 20 issing number: 000220: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000230: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000240: 20 20 36 32 3F 36 20 2D 20 32 37 31 20 3D 20 35 62?6 - 271 = 5 000250: 39 37 35 20 20 20 20 20 1B 34 1B 36 1B 38 1B 39 975 .4.6.8.9 000260: 1B 85 00 4A 61 6D 65 73 20 68 61 64 20 31 37 33 ...James had 173 000270: 32 20 73 74 61 6D 70 73 20 69 6E 20 68 69 73 20 2 stamps in his 000280: 20 63 6F 6C 6C 65 63 74 69 6F 6E 20 61 6E 64 20 collection and 000290: 53 74 65 70 68 65 6E 20 68 61 64 20 20 20 20 32 Stephen had 2 0002A0: 30 32 33 2E 20 48 6F 77 20 6D 61 6E 79 20 6D 6F 023. How many mo 0002B0: 72 65 20 73 74 61 6D 70 73 20 64 69 64 53 74 65 re stamps didSte 0002C0: 70 68 65 6E 20 68 61 76 65 20 74 68 61 6E 20 4A phen have than J 0002D0: 61 6D 65 73 3F 1B 32 39 31 1B 32 37 34 1B 32 38 ames?.291.274.28 0002E0: 35 1B 33 30 32 1B 52 00 20 20 20 20 20 20 20 20 5.302.R. 0002F0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000300: 20 20 20 20 20 D6 EB 20 60 32 33 36 2E 38 37 20 .. `236.87 000310: 2D 20 60 31 36 37 2E 32 31 20 3D 20 3F 1B 60 36 - `167.21 = ?.`6 000320: 39 2E 36 36 1B 60 36 31 2E 33 34 1B 60 35 37 2E 9.66.`61.34.`57. 000330: 34 33 1B 60 35 38 2E 32 31 1B 4A 00 20 20 20 20 43.`58.21.J. 000340: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000350: 20 20 20 20 20 20 20 20 20 20 34 2E 37 32 31 20 4.721 000360: 2D 20 32 2E 30 30 36 20 3D 20 3F 1B 32 2E 37 31 - 2.006 = ?.2.71 000370: 35 1B 32 2E 33 31 35 1B 32 2E 35 37 33 1B 32 2E 5.2.315.2.573.2. 000380: 36 37 31 1B 41 00 20 20 20 20 20 20 20 20 20 20 671.A. 000390: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0003A0: 20 20 20 20 35 36 34 31 20 2D 20 34 38 32 36 20 5641 - 4826 0003B0: 3D 20 3F 1B 38 31 35 1B 31 30 30 33 1B 39 37 34 = ?.815.1003.974 0003C0: 1B 38 37 35 1B 51 00 20 20 20 20 20 20 20 20 20 .875.Q. 0003D0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0003E0: 20 20 20 20 20 60 31 34 32 2E 38 37 20 2D 20 60 `142.87 - ` 0003F0: 39 39 2E 31 33 20 3D 20 3F 1B 60 34 33 2E 37 34 99.13 = ?.`43.74 000400: 1B 60 34 32 2E 36 34 E5 7C 1B 60 34 32 2E 38 34 .`42.64.|.`42.84 000410: 1B 60 34 33 2E 35 34 1B 4C 00 20 20 20 20 20 20 .`43.54.L. 000420: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000430: 20 20 20 20 20 20 20 20 32 34 2E 30 31 32 20 2D 24.012 - 000440: 20 32 30 2E 31 39 37 20 3D 20 3F 1B 33 2E 38 31 20.197 = ?.3.81 000450: 35 1B 34 2E 31 32 35 1B 33 2E 39 37 35 1B 33 2E 5.4.125.3.975.3. 000460: 38 36 35 1B 4A 00 20 20 20 20 20 20 20 20 20 20 865.J. 000470: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000480: 20 20 20 20 30 2E 30 39 31 20 2D 20 30 2E 30 30 0.091 - 0.00 000490: 39 20 3D 20 3F 1B 30 2E 30 38 32 1B 30 2E 38 32 9 = ?.0.082.0.82 0004A0: 32 1B 30 2E 30 30 38 1B 30 2E 38 38 32 1B 64 00 2.0.008.0.882.d. 0004B0: 49 6E 20 61 20 73 63 68 6F 6F 6C 20 77 68 69 63 In a school whic 0004C0: 68 20 68 61 64 20 33 38 37 20 20 20 20 20 63 68 h had 387 ch 0004D0: 69 6C 64 72 65 6E 2C 20 31 39 38 20 77 65 72 65 ildren, 198 were 0004E0: 20 67 69 72 6C 73 2E 20 48 6F 77 20 6D 61 6E 79 girls. How many 0004F0: 20 62 6F 79 73 20 77 65 72 65 20 74 68 65 72 65 boys were there 000500: 3F 1B 31 38 39 1B 31 37 38 A9 87 1B 31 39 36 1B ?.189.178...196. 000510: 31 36 37 1B 48 00 20 20 20 20 20 20 20 20 20 20 167.H. 000520: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000530: 20 20 20 20 33 2E 37 20 2D 20 30 2E 30 32 39 20 3.7 - 0.029 000540: 3D 20 3F 1B 33 2E 36 37 31 1B 32 2E 37 38 39 1B = ?.3.671.2.789. 000550: 33 2E 32 31 35 1B 33 2E 34 37 37 1B 58 00 46 69 3.215.3.477.X.Fi 000560: 6E 64 20 74 68 65 20 6D 69 73 73 69 6E 67 20 6E nd the missing n 000570: 75 6D 62 65 72 3A 20 20 20 20 20 20 20 20 20 20 umber: 000580: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000590: 20 20 20 20 20 20 20 20 20 20 33 3F 31 30 20 2D 3?10 - 0005A0: 20 32 39 39 39 20 3D 20 32 31 31 1B 32 1B 34 1B 2999 = 211.2.4. 0005B0: 38 1B 36 1B 4A 00 20 20 20 20 20 20 20 20 20 20 8.6.J. 0005C0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0005D0: 20 20 20 20 35 32 2E 31 36 20 2D 20 32 37 2E 39 52.16 - 27.9 0005E0: 31 20 3D 20 3F 1B 32 34 2E 32 35 1B 32 35 2E 31 1 = ?.24.25.25.1 0005F0: 36 1B 32 34 2E 31 33 1B 32 35 2E 30 39 1B 40 00 6.24.13.25.09.@. 000600: 20 20 20 20 20 20 20 20 20 20 20 E9 D5 20 20 20 .. 000610: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000620: 39 31 32 31 20 2D 20 38 37 38 39 20 3D 20 3F 1B 9121 - 8789 = ?. 000630: 33 33 32 1B 33 35 34 1B 33 36 39 1B 32 39 38 1B 332.354.369.298. 000640: 68 00 53 75 62 74 72 61 63 74 20 74 68 65 20 73 h.Subtract the s 000650: 6D 61 6C 6C 65 72 20 6E 75 6D 62 65 72 20 20 20 maller number 000660: 66 72 6F 6D 20 74 68 65 20 6C 61 72 67 65 72 3A from the larger: 000670: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000680: 38 2E 39 38 39 20 61 6E 64 20 35 2E 36 31 37 1B 8.989 and 5.617. 000690: 33 2E 33 37 32 1B 33 2E 34 32 31 1B 33 2E 35 36 3.372.3.421.3.56 0006A0: 32 1B 33 2E 32 39 35 1B 44 00 20 20 20 20 20 20 2.3.295.D. 0006B0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0006C0: 20 20 20 20 20 20 20 20 36 31 39 32 20 2D 20 31 6192 - 1 0006D0: 31 30 31 20 3D 20 3F 1B 35 30 39 31 1B 35 33 34 101 = ?.5091.534 0006E0: 39 1B 34 39 37 34 1B 35 31 38 33 1B 4F 00 20 20 9.4974.5183.O. 0006F0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000700: 20 20 20 20 20 20 20 20 20 20 20 20 60 A1 2C 32 `.,2 000710: 39 2E 36 32 20 2D 20 60 31 2E 32 36 20 3D 20 3F 9.62 - `1.26 = ? 000720: 1B 60 32 38 2E 33 36 1B 60 32 37 2E 34 35 1B 60 .`28.36.`27.45.` 000730: 32 38 2E 34 35 1B 60 32 37 2E 39 38 1B 5D 00 41 28.45.`27.98.].A 000740: 20 66 61 72 6D 65 72 20 68 61 64 20 33 34 33 31 farmer had 3431 000750: 20 73 68 65 65 70 20 62 75 74 20 20 20 74 68 65 sheep but the 000760: 6E 20 73 6F 6C 64 20 32 33 39 2E 20 48 6F 77 20 n sold 239. How 000770: 6D 61 6E 79 20 64 69 64 20 68 65 68 61 76 65 20 many did hehave 000780: 6C 65 66 74 3F 1B 33 31 39 32 1B 33 30 33 32 1B left?.3192.3032. 000790: 33 30 36 35 1B 33 31 37 33 1B 69 00 53 75 62 74 3065.3173.i.Subt 0007A0: 72 61 63 74 20 74 68 65 20 73 6D 61 6C 6C 65 72 ract the smaller 0007B0: 20 6E 75 6D 62 65 72 20 20 20 66 72 6F 6D 20 74 number from t 0007C0: 68 65 20 6C 61 72 67 65 72 3A 20 20 20 20 20 20 he larger: 0007D0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0007E0: 20 20 20 20 20 20 20 20 35 32 30 35 20 61 6E 64 5205 and 0007F0: 20 35 32 32 31 1B 31 36 1B 31 36 30 1B 32 31 1B 5221.16.160.21. 000800: 31 32 1B 56 00 20 20 20 20 20 20 20 20 20 20 9D 12.V. . 000810: CD FF FF FF FF .....
previousnext* BLOCK 0021 : TURBO LOADING DATA
HEADER
Block Name : AR17
Block Number : 2
Block last : YES
File type : Binaire
File adress start : &6800
File adress length : &00B2
File adress execution : &0000
File length file : &08B2

Length of PILOT pulse : 2510
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1316
Length of ONE bit pulse : 2519
Length of PILOT tone : 4097
Used bits in last byte : 8 OK
Data : 263 bytes
Total size : 282 bytes

Sum DATA : 2 265

Duration : 4576 ms
Pause After this block : 19 ms
Duration block + Pause : 4595 ms
Duration block + Pause : 00 h 00 m 04 s		000000: 2C 41 52 31 37 00 00 00 00 00 00 00 00 00 00 00 ,AR17........... 000010: 00 02 FF 02 B2 00 00 68 00 B2 08 00 00 00 00 00 .......h........ 000020: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000030: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000040: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000050: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000060: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000070: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000080: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000090: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000A0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000B0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000C0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000D0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000E0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000F0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000100: 00 76 69 FF FF FF FF .vi....
previousnext* BLOCK 0022 : TURBO LOADING DATA
DATA
Length of PILOT pulse : 2510
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1322
Length of ONE bit pulse : 2490
Length of PILOT tone : 4096
Used bits in last byte : 8 OK
Data : 263 bytes
Total size : 282 bytes

Sum DATA : 10 160

Duration : 4861 ms
Pause After this block : 13644 ms
Duration block + Pause : 18505 ms
Duration block + Pause : 00 h 00 m 18 s		000000: 16 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 . 000010: 20 20 20 20 20 60 33 30 31 2E 36 32 20 2D 20 60 `301.62 - ` 000020: 31 39 38 2E 30 31 20 3D 20 3F 1B 60 31 30 33 2E 198.01 = ?.`103. 000030: 36 31 1B 60 31 30 30 2E 32 31 1B 60 31 30 31 2E 61.`100.21.`101. 000040: 34 35 1B 60 31 30 34 2E 37 35 1B 67 00 57 68 61 45.`104.75.g.Wha 000050: 74 20 69 73 20 74 68 65 20 6D 69 73 73 69 6E 67 t is the missing 000060: 20 6E 75 6D 62 65 72 3F 20 20 20 20 20 20 20 20 number? 000070: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000080: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 39 38 98 000090: 32 31 20 2D 20 3F 20 3D 20 31 38 32 32 1B 37 39 21 - ? = 1822.79 0000A0: 39 39 1B 38 30 30 33 1B 37 39 39 31 1B 38 30 30 99.8003.7991.800 0000B0: 31 1B 1C 00 00 00 00 00 00 00 00 00 00 00 00 00 1............... 0000C0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000D0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000E0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000F0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000100: 00 1B 3E FF FF FF FF ..>....
previousnext* BLOCK 0023 : TURBO LOADING DATA
HEADER
Block Name : AR18
Block Number : 1
Block first : YES
File type : Binaire
File adress start : &6000
File adress length : &0800
File adress execution : &0000
File length file : &08D4

Length of PILOT pulse : 2510
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1316
Length of ONE bit pulse : 2519
Length of PILOT tone : 4097
Used bits in last byte : 8 OK
Data : 263 bytes
Total size : 282 bytes

Sum DATA : 2 257

Duration : 4573 ms
Pause After this block : 17 ms
Duration block + Pause : 4590 ms
Duration block + Pause : 00 h 00 m 04 s		000000: 2C 41 52 31 38 00 00 00 00 00 00 00 00 00 00 00 ,AR18........... 000010: 00 01 00 02 00 08 00 60 FF D4 08 00 00 00 00 00 .......`........ 000020: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000030: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000040: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000050: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000060: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000070: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000080: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000090: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000A0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000B0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000C0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000D0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000E0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000F0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000100: 00 6C FB FF FF FF FF .l.....
previousnext* BLOCK 0024 : TURBO LOADING DATA
DATA
Length of PILOT pulse : 2510
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1330
Length of ONE bit pulse : 2491
Length of PILOT tone : 4098
Used bits in last byte : 8 OK
Data : 2069 bytes
Total size : 2088 bytes

Sum DATA : 128 848

Duration : 19498 ms
Pause After this block : 2700 ms
Duration block + Pause : 22198 ms
Duration block + Pause : 00 h 00 m 22 s		000000: 16 41 52 31 38 00 00 00 00 00 00 00 19 D3 08 00 .AR18........... 000010: 4D 75 6C 74 69 70 6C 69 63 61 74 69 6F 6E 20 2D Multiplication - 000020: 20 54 68 48 54 55 20 20 20 00 00 00 00 00 00 00 ThHTU ....... 000030: 00 40 00 20 20 20 20 20 20 20 20 20 20 20 20 20 .@. 000040: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000050: 20 35 32 31 20 78 20 36 20 3D 20 3F 1B 33 31 32 521 x 6 = ?.312 000060: 36 1B 32 39 37 36 1B 33 32 33 36 1B 33 33 34 36 6.2976.3236.3346 000070: 1B 76 00 49 66 20 65 61 63 68 20 62 6F 78 20 63 .v.If each box c 000080: 6F 6E 74 61 69 6E 65 64 20 31 33 32 20 20 20 20 ontained 132 000090: 20 61 70 70 6C 65 73 2C 20 77 68 61 74 20 69 73 apples, what is 0000A0: 20 74 68 65 20 74 6F 74 61 6C 20 20 20 20 20 6E the total n 0000B0: 75 6D 62 65 72 20 6F 66 20 61 70 70 6C 65 73 20 umber of apples 0000C0: 63 6F 6E 74 61 69 6E 65 64 20 69 6E 20 38 20 62 contained in 8 b 0000D0: 6F 78 65 73 3F 1B 31 30 35 36 1B 38 37 34 1B 39 oxes?.1056.874.9 0000E0: 32 38 1B 39 39 36 1B 6F 00 57 68 61 74 20 77 6F 28.996.o.What wo 0000F0: 75 6C 64 20 62 65 20 74 68 65 20 74 6F 74 61 6C uld be the total 000100: 20 B1 FA 63 6F 73 74 20 20 6F 66 20 34 20 74 65 ..cost of 4 te 000110: 6E 6E 69 73 20 72 61 63 6B 65 74 73 20 69 66 20 nnis rackets if 000120: 65 61 63 68 20 20 20 6F 6E 65 20 63 6F 73 74 20 each one cost 000130: 60 32 39 2E 36 35 3F 1B 60 31 31 38 2E 36 30 1B `29.65?.`118.60. 000140: 60 31 31 32 2E 36 35 1B 60 31 32 30 2E 32 30 1B `112.65.`120.20. 000150: 60 31 31 35 2E 35 30 1B 40 00 20 20 20 20 20 20 `115.50.@. 000160: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000170: 20 20 20 20 20 20 20 20 38 34 20 78 20 35 32 20 84 x 52 000180: 3D 20 3F 1B 34 33 36 38 1B 33 37 38 33 1B 33 39 = ?.4368.3783.39 000190: 36 37 1B 34 31 35 36 1B 76 00 34 33 20 6E 61 69 67.4156.v.43 nai 0001A0: 6C 73 20 61 72 65 20 6E 65 65 64 65 64 20 74 6F ls are needed to 0001B0: 20 6D 61 6B 65 20 61 20 67 75 69 6E 65 61 20 70 make a guinea p 0001C0: 69 67 27 73 20 63 61 67 65 2E 20 48 6F 77 20 6D ig's cage. How m 0001D0: 61 6E 79 20 20 20 6E 61 69 6C 73 20 77 6F 75 6C any nails woul 0001E0: 64 20 62 65 20 6E 65 65 64 65 64 20 74 6F 20 6D d be needed to m 0001F0: 61 6B 65 20 31 34 20 63 61 67 65 73 3F 1B 36 30 ake 14 cages?.60 000200: 32 1B 37 9F 30 36 34 1B 36 39 35 1B 36 33 34 1B 2.7.064.695.634. 000210: 8A 00 52 6F 62 65 72 74 20 62 6F 75 67 68 74 20 ..Robert bought 000220: 32 20 63 6F 6D 70 75 74 65 72 20 67 61 6D 65 73 2 computer games 000230: 61 74 20 60 34 2E 36 32 20 65 61 63 68 20 61 6E at `4.62 each an 000240: 64 20 33 20 72 65 63 6F 72 64 73 20 61 74 60 34 d 3 records at`4 000250: 2E 39 39 20 65 61 63 68 2E 20 48 6F 77 20 6D 75 .99 each. How mu 000260: 63 68 20 64 69 64 20 68 65 20 20 20 73 70 65 6E ch did he spen 000270: 64 20 61 6C 74 6F 67 65 74 68 65 72 3F 1B 60 32 d altogether?.`2 000280: 34 2E 32 31 1B 60 32 33 2E 36 37 1B 60 32 35 2E 4.21.`23.67.`25. 000290: 31 32 1B 60 32 34 2E 35 34 1B 93 00 46 69 6E 64 12.`24.54...Find 0002A0: 20 74 68 65 20 74 6F 74 61 6C 20 77 65 69 67 68 the total weigh 0002B0: 74 20 6F 66 20 32 20 20 20 20 74 69 6E 73 20 6F t of 2 tins o 0002C0: 66 20 73 70 61 67 68 65 74 74 69 20 65 61 63 68 f spaghetti each 0002D0: 20 20 20 20 20 20 20 20 77 65 69 67 68 69 6E 67 weighing 0002E0: 20 34 34 30 67 6D 73 20 61 6E 64 20 35 20 74 69 440gms and 5 ti 0002F0: 6E 73 20 6F 66 20 73 6F 75 70 20 65 61 63 68 20 ns of soup each 000300: 77 65 69 67 68 86 D4 69 6E 67 20 38 31 30 67 6D weigh..ing 810gm 000310: 73 2E 1B 34 2E 39 33 6B 67 1B 34 2E 37 36 6B 67 s..4.93kg.4.76kg 000320: 1B 34 2E 36 38 6B 67 1B 34 2E 38 37 6B 67 1B 92 .4.68kg.4.87kg.. 000330: 00 4D 69 63 68 61 65 6C 20 74 61 6B 65 73 20 31 .Michael takes 1 000340: 68 72 20 31 35 6D 69 6E 73 20 74 6F 20 64 6F 61 hr 15mins to doa 000350: 20 70 61 70 65 72 20 72 6F 75 6E 64 20 65 61 63 paper round eac 000360: 68 20 64 61 79 2E 20 48 6F 77 20 20 20 6C 6F 6E h day. How lon 000370: 67 20 64 6F 65 73 20 68 65 20 77 6F 72 6B 20 69 g does he work i 000380: 6E 20 61 20 36 20 64 61 79 20 20 77 65 65 6B 3F n a 6 day week? 000390: 1B 37 68 72 73 20 33 30 6D 69 6E 73 1B 36 68 72 .7hrs 30mins.6hr 0003A0: 73 20 31 35 6D 69 6E 73 1B 37 68 72 73 20 31 35 s 15mins.7hrs 15 0003B0: 6D 69 6E 73 1B 36 68 72 73 20 34 35 6D 69 6E 73 mins.6hrs 45mins 0003C0: 1B 62 00 57 68 61 74 20 69 73 20 74 68 65 20 6D .b.What is the m 0003D0: 69 73 73 69 6E 67 20 6E 75 6D 62 65 72 20 69 6E issing number in 0003E0: 20 74 68 69 73 20 73 75 6D 3F 20 20 20 20 20 20 this sum? 0003F0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000400: 20 20 20 20 20 20 20 A4 47 20 33 36 3F 32 20 78 .G 36?2 x 000410: 20 32 32 20 3D 20 38 30 35 36 34 20 1B 36 1B 38 22 = 80564 .6.8 000420: 1B 35 1B 34 1B 82 00 49 6E 20 74 68 65 20 73 63 .5.4...In the sc 000430: 68 6F 6F 6C 20 63 61 6E 74 65 65 6E 20 74 68 65 hool canteen the 000440: 72 65 20 20 20 61 72 65 20 31 36 20 74 61 62 6C re are 16 tabl 000450: 65 73 20 65 61 63 68 20 73 65 61 74 69 6E 67 20 es each seating 000460: 38 20 20 63 68 69 6C 64 72 65 6E 2E 20 48 6F 77 8 children. How 000470: 20 6D 61 6E 79 20 63 68 69 6C 64 72 65 6E 20 20 many children 000480: 20 61 72 65 20 74 68 65 72 65 20 61 6C 74 6F 67 are there altog 000490: 65 74 68 65 72 3F 1B 31 32 38 1B 31 33 32 1B 31 ether?.128.132.1 0004A0: 33 30 1B 31 32 35 1B 45 00 20 20 20 20 20 20 20 30.125.E. 0004B0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0004C0: 20 20 20 20 20 20 20 36 38 32 20 78 20 38 31 20 682 x 81 0004D0: 3D 20 3F 1B 35 35 32 34 32 1B 35 33 38 39 35 1B = ?.55242.53895. 0004E0: 35 30 32 33 37 1B 35 39 30 37 38 1B 46 00 20 20 50237.59078.F. 0004F0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000500: 20 20 20 20 20 20 20 20 20 6B 51 20 20 20 31 30 kQ 10 000510: 31 30 20 78 20 32 33 20 3D 20 3F 1B 32 33 32 33 10 x 23 = ?.2323 000520: 30 1B 32 33 37 36 35 1B 32 33 31 38 35 1B 32 33 0.23765.23185.23 000530: 34 39 30 1B 3B 00 48 6F 77 20 6D 61 6E 79 20 6D 490.;.How many m 000540: 69 6E 75 74 65 73 20 61 72 65 20 74 68 65 72 65 inutes are there 000550: 20 69 6E 20 61 20 64 61 79 3F 1B 31 34 34 30 1B in a day?.1440. 000560: 31 32 37 35 1B 31 36 37 33 1B 31 33 34 32 1B 50 1275.1673.1342.P 000570: 00 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 . 000580: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 36 6 000590: 2E 33 32 20 78 20 34 2E 30 32 20 3D 20 3F 1B 32 .32 x 4.02 = ?.2 0005A0: 35 2E 34 30 36 34 1B 32 34 2E 36 35 38 33 1B 32 5.4064.24.6583.2 0005B0: 35 2E 33 36 32 39 1B 32 35 2E 31 33 32 36 1B 47 5.3629.25.1326.G 0005C0: 00 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 . 0005D0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 30 0 0005E0: 2E 30 36 32 20 78 20 30 2E 37 20 3D 20 3F 1B 30 .062 x 0.7 = ?.0 0005F0: 2E 30 34 33 34 1B 30 2E 34 33 34 1B 34 2E 33 34 .0434.0.434.4.34 000600: 1B 34 33 2E 34 1B 48 00 20 20 20 F5 32 20 20 20 .43.4.H. .2 000610: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000620: 20 20 20 20 20 20 20 20 30 2E 30 37 36 20 78 20 0.076 x 000630: 37 20 3D 20 3F 1B 30 2E 35 33 32 1B 35 2E 33 32 7 = ?.0.532.5.32 000640: 1B 30 2E 30 35 33 32 1B 30 2E 30 30 35 33 32 1B .0.0532.0.00532. 000650: 47 00 20 20 20 20 20 20 20 20 20 20 20 20 20 20 G. 000660: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000670: 38 31 32 20 78 20 30 2E 36 20 3D 20 3F 1B 34 38 812 x 0.6 = ?.48 000680: 37 2E 32 1B 34 38 2E 37 32 1B 34 38 37 32 2E 30 7.2.48.72.4872.0 000690: 1B 34 2E 38 37 32 1B 64 00 57 68 61 74 20 69 73 .4.872.d.What is 0006A0: 20 74 68 65 20 6D 69 73 73 69 6E 67 20 6E 75 6D the missing num 0006B0: 62 65 72 20 69 6E 20 74 68 69 73 20 73 75 6D 3F ber in this sum? 0006C0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0006D0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 31 3F 1? 0006E0: 35 36 20 78 20 31 33 20 3D 20 32 31 35 32 38 20 56 x 13 = 21528 0006F0: 20 20 1B 36 1B 39 1B 37 1B 34 1B 45 00 20 20 20 .6.9.7.4.E. 000700: 20 20 20 20 20 20 20 20 20 20 20 20 20 51 95 20 Q. 000710: 20 20 20 20 20 20 20 20 20 20 20 20 20 31 38 39 189 000720: 20 78 20 39 38 20 3D 20 3F 1B 31 38 35 32 32 1B x 98 = ?.18522. 000730: 31 36 34 37 38 1B 31 35 33 39 31 1B 31 37 35 33 16478.15391.1753 000740: 39 1B 41 00 20 20 20 20 20 20 20 20 20 20 20 20 9.A. 000750: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000760: 20 20 36 31 35 20 78 20 31 35 20 3D 20 3F 1B 39 615 x 15 = ?.9 000770: 32 32 35 1B 38 37 38 35 1B 39 31 34 35 1B 39 30 225.8785.9145.90 000780: 37 35 1B 42 00 20 20 20 20 20 20 20 20 20 20 20 75.B. 000790: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0007A0: 20 20 20 35 2E 32 20 78 20 36 20 3D 20 3F 1B 33 5.2 x 6 = ?.3 0007B0: 31 2E 32 1B 33 2E 31 32 1B 33 30 2E 31 32 1B 33 1.2.3.12.30.12.3 0007C0: 2E 30 31 32 1B 4A 00 20 20 20 20 20 20 20 20 20 .012.J. 0007D0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 0007E0: 20 20 20 20 20 30 2E 30 38 36 20 78 20 30 2E 38 0.086 x 0.8 0007F0: 20 3D 20 3F 1B 30 2E 30 36 38 38 1B 30 2E 36 38 = ?.0.0688.0.68 000800: 38 1B 36 2E 38 38 1B 30 2E 30 30 36 38 38 1B B1 8.6.88.0.00688.. 000810: A4 FF FF FF FF .....
previousnext* BLOCK 0025 : TURBO LOADING DATA
HEADER
Block Name : AR18
Block Number : 2
Block last : YES
File type : Binaire
File adress start : &6800
File adress length : &00D4
File adress execution : &0000
File length file : &08D4

Length of PILOT pulse : 2515
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1318
Length of ONE bit pulse : 2528
Length of PILOT tone : 4097
Used bits in last byte : 8 OK
Data : 263 bytes
Total size : 282 bytes

Sum DATA : 2 503

Duration : 4584 ms
Pause After this block : 18 ms
Duration block + Pause : 4602 ms
Duration block + Pause : 00 h 00 m 04 s		000000: 2C 41 52 31 38 00 00 00 00 00 00 00 00 00 00 00 ,AR18........... 000010: 00 02 FF 02 D4 00 00 68 00 D4 08 00 00 00 00 00 .......h........ 000020: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000030: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000040: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000050: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000060: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000070: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000080: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000090: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000A0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000B0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000C0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000D0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000E0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000F0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000100: 00 CF B9 FF FF FF FF .......
previousnext* BLOCK 0026 : TURBO LOADING DATA
DATA
Length of PILOT pulse : 2515
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1324
Length of ONE bit pulse : 2498
Length of PILOT tone : 4096
Used bits in last byte : 8 OK
Data : 263 bytes
Total size : 282 bytes

Sum DATA : 9 867

Duration : 4897 ms
Pause After this block : 13408 ms
Duration block + Pause : 18305 ms
Duration block + Pause : 00 h 00 m 18 s		000000: 16 48 00 20 20 20 20 20 20 20 20 20 20 20 20 20 .H. 000010: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000020: 20 31 2E 31 35 20 78 20 31 30 2E 32 20 3D 20 3F 1.15 x 10.2 = ? 000030: 1B 31 31 2E 37 33 1B 31 31 37 2E 33 1B 31 2E 31 .11.73.117.3.1.1 000040: 37 33 1B 31 30 2E 37 33 1B 46 00 20 20 20 20 20 73.10.73.F. 000050: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000060: 20 20 20 20 20 20 20 20 20 37 2E 34 20 78 20 32 7.4 x 2 000070: 2E 36 20 3D 20 3F 1B 31 39 2E 32 34 1B 31 37 2E .6 = ?.19.24.17. 000080: 34 35 1B 31 34 2E 33 34 1B 31 35 2E 37 34 1B 45 45.14.34.15.74.E 000090: 00 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 . 0000A0: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 38 8 0000B0: 35 31 20 78 20 32 34 20 3D 20 3F 1B 32 30 34 32 51 x 24 = ?.2042 0000C0: 34 1B 31 36 39 37 34 1B 31 39 35 32 38 1B 32 31 4.16974.19528.21 0000D0: 35 37 34 1B 1C 00 00 00 00 00 00 00 00 00 00 00 574............. 0000E0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000F0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000100: 00 70 40 FF FF FF FF .p@....
previousnext* BLOCK 0027 : TURBO LOADING DATA
HEADER
Block Name : AR19
Block Number : 1
Block first : YES
Block last : YES
File type : Binaire
File adress start : &6000
File adress length : &0696
File adress execution : &0000
File length file : &0696

Length of PILOT pulse : 2514
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1318
Length of ONE bit pulse : 2527
Length of PILOT tone : 4096
Used bits in last byte : 8 OK
Data : 263 bytes
Total size : 282 bytes

Sum DATA : 2 462

Duration : 4588 ms
Pause After this block : 18 ms
Duration block + Pause : 4606 ms
Duration block + Pause : 00 h 00 m 04 s		000000: 2C 41 52 31 39 00 00 00 00 00 00 00 00 00 00 00 ,AR19........... 000010: 00 01 FF 02 96 06 00 60 FF 96 06 00 00 00 00 00 .......`........ 000020: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000030: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000040: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000050: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000060: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000070: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000080: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000090: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000A0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000B0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000C0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000D0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000E0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000F0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000100: 00 4F 91 FF FF FF FF .O.....
previousnext* BLOCK 0028 : TURBO LOADING DATA
DATA
Length of PILOT pulse : 2514
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1329
Length of ONE bit pulse : 2493
Length of PILOT tone : 4096
Used bits in last byte : 8 OK
Data : 1811 bytes
Total size : 1830 bytes

Sum DATA : 119 808

Duration : 17697 ms
Pause After this block : 14103 ms
Duration block + Pause : 31800 ms
Duration block + Pause : 00 h 00 m 31 s		000000: 16 41 52 31 39 00 00 00 00 00 00 00 19 95 06 00 .AR19........... 000010: 44 69 76 69 73 69 6F 6E 20 2D 20 54 68 48 54 55 Division - ThHTU 000020: 20 20 20 20 20 20 20 20 20 00 00 00 00 00 00 00 ....... 000030: 00 44 00 44 69 76 69 64 65 20 38 32 36 20 62 79 .D.Divide 826 by 000040: 20 38 20 74 6F 20 74 77 6F 20 64 65 63 69 6D 61 8 to two decima 000050: 6C 70 6C 61 63 65 73 2E 1B 31 30 33 2E 32 35 1B lplaces..103.25. 000060: 31 30 32 2E 32 33 1B 31 30 33 2E 35 34 1B 31 30 102.23.103.54.10 000070: 34 2E 33 32 1B 69 00 52 65 62 65 63 63 61 20 62 4.32.i.Rebecca b 000080: 6F 75 67 68 74 20 34 20 6A 69 67 73 61 77 73 20 ought 4 jigsaws 000090: 61 74 20 61 20 74 6F 74 61 6C 20 63 6F 73 74 20 at a total cost 0000A0: 6F 66 20 60 35 2E 30 34 2E 20 48 6F 77 20 6D 75 of `5.04. How mu 0000B0: 63 68 20 64 69 64 20 65 61 63 68 20 6F 6E 65 20 ch did each one 0000C0: 63 6F 73 74 3F 1B 60 31 2E 32 36 1B 60 31 2E 35 cost?.`1.26.`1.5 0000D0: 32 1B 60 31 2E 33 34 1B 60 31 2E 34 32 1B 73 00 2.`1.34.`1.42.s. 0000E0: 41 20 6A 75 6D 62 6F 20 62 61 67 20 63 6F 6E 74 A jumbo bag cont 0000F0: 61 69 6E 69 6E 67 20 39 20 20 20 20 20 20 70 61 aining 9 pa 000100: 63 5A 9E 6B 65 74 73 20 6F 66 20 63 72 69 73 70 cZ.kets of crisp 000110: 73 20 77 65 69 67 68 73 20 32 32 35 67 2E 48 6F s weighs 225g.Ho 000120: 77 20 6D 75 63 68 20 64 6F 65 73 20 65 61 63 68 w much does each 000130: 20 70 61 63 6B 65 74 20 20 20 20 20 77 65 69 67 packet weig 000140: 68 3F 1B 32 35 67 1B 33 30 67 1B 32 30 67 1B 33 h?.25g.30g.20g.3 000150: 35 67 1B 29 00 44 69 76 69 64 65 20 30 2E 37 32 5g.).Divide 0.72 000160: 20 62 79 20 36 1B 30 2E 31 32 1B 30 2E 30 31 32 by 6.0.12.0.012 000170: 1B 30 2E 39 31 1B 30 2E 30 39 31 1B 50 00 48 6F .0.91.0.091.P.Ho 000180: 77 20 6D 61 6E 79 20 36 35 63 6D 20 6C 65 6E 67 w many 65cm leng 000190: 74 68 73 20 6F 66 20 72 6F 70 65 20 63 6F 75 6C ths of rope coul 0001A0: 64 20 62 65 20 63 75 74 20 66 72 6F 6D 20 61 20 d be cut from a 0001B0: 31 32 2E 33 35 6D 20 20 20 20 72 6F 70 65 3F 1B 12.35m rope?. 0001C0: 31 39 1B 31 36 1B 32 39 1B 32 33 1B 66 00 49 66 19.16.29.23.f.If 0001D0: 20 32 35 20 65 71 75 61 6C 6C 79 20 73 69 7A 65 25 equally size 0001E0: 64 20 61 70 70 6C 65 73 20 20 20 20 77 65 69 67 d apples weig 0001F0: 68 20 33 20 6B 69 6C 6F 67 72 61 6D 73 20 68 6F h 3 kilograms ho 000200: 77 20 6D DC D9 75 63 68 20 20 20 20 64 6F 65 73 w m..uch does 000210: 20 65 61 63 68 20 61 70 70 6C 65 20 77 65 69 67 each apple weig 000220: 68 3F 1B 31 32 30 67 1B 31 32 67 1B 34 30 67 1B h?.120g.12g.40g. 000230: 36 30 67 1B 1F 00 44 69 76 69 64 65 20 35 33 32 60g...Divide 532 000240: 20 62 79 20 31 34 1B 33 38 1B 34 36 1B 33 35 1B by 14.38.46.35. 000250: 34 30 1B 2A 00 44 69 76 69 64 65 20 38 2E 31 32 40.*.Divide 8.12 000260: 35 20 62 79 20 35 1B 31 2E 36 32 35 1B 31 2E 32 5 by 5.1.625.1.2 000270: 35 1B 31 2E 33 36 1B 31 2E 35 35 35 1B 54 00 49 5.1.36.1.555.T.I 000280: 66 20 36 20 62 6F 78 65 73 20 6F 66 20 65 67 67 f 6 boxes of egg 000290: 73 20 63 6F 73 74 20 60 32 2E 32 38 20 68 6F 77 s cost `2.28 how 0002A0: 20 6D 75 63 68 20 77 6F 75 6C 64 20 31 20 62 6F much would 1 bo 0002B0: 78 20 6F 66 20 65 67 67 73 20 20 63 6F 73 74 3F x of eggs cost? 0002C0: 1B 33 38 70 1B 35 33 70 1B 34 33 70 1B 34 30 70 .38p.53p.43p.40p 0002D0: 1B 23 00 44 69 76 69 64 65 20 32 2E 34 20 62 79 .#.Divide 2.4 by 0002E0: 20 30 2E 38 1B 33 1B 30 2E 33 1B 30 2E 34 33 1B 0.8.3.0.3.0.43. 0002F0: 33 2E 34 1B 6C 00 49 66 20 31 35 20 69 64 65 6E 3.4.l.If 15 iden 000300: 74 69 63 61 6C 2F 9F 20 62 61 72 73 20 6F 66 20 tical/. bars of 000310: 20 20 20 20 20 20 63 68 6F 63 6F 6C 61 74 65 20 chocolate 000320: 63 6F 73 74 20 61 20 74 6F 74 61 6C 20 6F 66 20 cost a total of 000330: 20 20 20 20 60 33 2E 39 30 20 68 6F 77 20 6D 75 `3.90 how mu 000340: 63 68 20 61 72 65 20 74 68 65 79 20 65 61 63 68 ch are they each 000350: 3F 1B 32 36 70 1B 33 32 70 1B 32 35 70 1B 32 32 ?.26p.32p.25p.22 000360: 70 1B 64 00 49 66 20 52 6F 62 65 72 74 20 73 77 p.d.If Robert sw 000370: 61 6D 20 61 20 74 6F 74 61 6C 20 6F 66 20 20 20 am a total of 000380: 20 20 31 31 30 30 6D 20 69 6E 20 61 20 70 6F 6F 1100m in a poo 000390: 6C 20 32 35 6D 20 6C 6F 6E 67 20 68 6F 77 20 20 l 25m long how 0003A0: 6D 61 6E 79 20 6C 65 6E 67 74 68 73 20 64 69 64 many lengths did 0003B0: 20 68 65 20 73 77 69 6D 3F 1B 34 34 1B 36 32 1B he swim?.44.62. 0003C0: 32 34 1B 33 36 1B 1F 00 44 69 76 69 64 65 20 39 24.36...Divide 9 0003D0: 38 30 20 62 79 20 32 30 1B 34 39 1B 35 30 1B 34 80 by 20.49.50.4 0003E0: 38 1B 34 37 1B 3C 00 44 69 76 69 64 65 20 38 20 8.47.<.Divide 8 0003F0: 62 79 20 32 34 20 74 6F 20 74 77 6F 20 64 65 63 by 24 to two dec 000400: 69 6D 61 6C 20 70 6C A7 67 61 63 65 73 2E 1B 30 imal pl.gaces..0 000410: 2E 33 33 1B 33 2E 30 30 1B 30 2E 30 33 1B 33 2E .33.3.00.0.03.3. 000420: 30 33 1B 1B 00 44 69 76 69 64 65 20 31 31 32 20 03...Divide 112 000430: 62 79 20 31 36 1B 37 1B 35 1B 39 1B 38 1B 1F 00 by 16.7.5.9.8... 000440: 44 69 76 69 64 65 20 34 36 38 20 62 79 20 31 33 Divide 468 by 13 000450: 1B 33 36 1B 34 31 1B 33 37 1B 33 34 1B 6C 00 48 .36.41.37.34.l.H 000460: 6F 77 20 6D 61 6E 79 20 6C 61 70 73 20 77 6F 75 ow many laps wou 000470: 6C 64 20 72 75 6E 6E 65 72 73 20 69 6E 61 20 32 ld runners ina 2 000480: 30 30 30 6D 20 72 61 63 65 20 68 61 76 65 20 74 000m race have t 000490: 6F 20 63 6F 6D 70 6C 65 74 65 20 69 66 20 61 20 o complete if a 0004A0: 6C 61 70 20 69 73 20 61 20 64 69 73 74 61 6E 63 lap is a distanc 0004B0: 65 20 6F 66 20 20 20 20 20 34 30 30 6D 3F 1B 35 e of 400m?.5 0004C0: 1B 35 30 1B 34 1B 34 30 1B 1F 00 44 69 76 69 64 .50.4.40...Divid 0004D0: 65 20 34 36 32 20 62 79 20 31 31 1B 34 32 1B 34 e 462 by 11.42.4 0004E0: 38 1B 35 32 1B 34 30 1B 2B 00 44 69 76 69 64 65 8.52.40.+.Divide 0004F0: 20 35 2E 39 35 20 62 79 20 30 2E 30 35 1B 31 31 5.95 by 0.05.11 000500: 39 1B 31 31 2E 39 1B 31 2E 81 60 31 39 1B 31 31 9.11.9.1..`19.11 000510: 39 2E 38 39 1B 5A 00 20 20 20 20 20 20 20 20 20 9.89.Z. 000520: 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 20 000530: 20 20 20 20 20 44 69 76 69 64 65 20 33 20 62 79 Divide 3 by 000540: 20 36 20 74 6F 20 74 77 6F 20 64 65 63 69 6D 61 6 to two decima 000550: 6C 20 20 70 6C 61 63 65 73 2E 1B 30 2E 35 30 1B l places..0.50. 000560: 35 2E 35 30 1B 32 2E 30 30 1B 30 2E 30 35 1B 20 5.50.2.00.0.05. 000570: 00 44 69 76 69 64 65 20 31 31 37 38 20 62 79 20 .Divide 1178 by 000580: 31 39 1B 36 32 1B 37 38 1B 36 34 1B 36 36 1B 29 19.62.78.64.66.) 000590: 00 44 69 76 69 64 65 20 33 2E 35 20 62 79 20 30 .Divide 3.5 by 0 0005A0: 2E 30 37 1B 35 30 1B 30 2E 35 30 1B 35 30 2E 31 .07.50.0.50.50.1 0005B0: 35 1B 35 2E 30 31 35 1B 97 00 31 31 20 62 6F 74 5.5.015...11 bot 0005C0: 74 6C 65 73 20 6F 66 20 65 71 75 61 6C 20 73 69 tles of equal si 0005D0: 7A 65 20 68 6F 6C 64 20 61 20 74 6F 74 61 6C 20 ze hold a total 0005E0: 6F 66 20 31 39 2E 32 35 20 6C 69 74 72 65 73 20 of 19.25 litres 0005F0: 6F 66 20 20 20 20 6F 72 61 6E 67 65 20 73 71 75 of orange squ 000600: 61 73 68 2E 20 48 6F 77 20 6D 75 70 69 63 68 20 ash. How mupich 000610: 64 6F 65 73 20 20 65 61 63 68 20 6F 6E 65 20 68 does each one h 000620: 6F 6C 64 3F 1B 31 2E 37 35 20 6C 69 74 72 65 73 old?.1.75 litres 000630: 1B 32 2E 30 30 20 6C 69 74 72 65 73 1B 31 2E 35 .2.00 litres.1.5 000640: 30 20 6C 69 74 72 65 73 1B 31 20 6C 69 74 72 65 0 litres.1 litre 000650: 1B 27 00 44 69 76 69 64 65 20 37 32 39 20 62 79 .'.Divide 729 by 000660: 20 31 38 1B 34 30 2E 35 1B 33 35 2E 38 1B 33 39 18.40.5.35.8.39 000670: 2E 34 1B 33 37 2E 36 1B 2A 00 44 69 76 69 64 65 .4.37.6.*.Divide 000680: 20 30 2E 30 33 33 36 20 62 79 20 30 2E 30 34 1B 0.0336 by 0.04. 000690: 30 2E 38 34 1B 30 2E 30 38 34 1B 38 2E 34 1B 38 0.84.0.084.8.4.8 0006A0: 34 1B 1C 00 00 00 00 00 00 00 00 00 00 00 00 00 4............... 0006B0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0006C0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0006D0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0006E0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0006F0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000700: 00 00 00 00 00 00 00 00 00 00 00 00 00 11 78 FF ..............x. 000710: FF FF FF ...
previousnext* BLOCK 0029 : TURBO LOADING DATA
HEADER
Block Name : AR20
Block Number : 1
Block first : YES
File type : Binaire
File adress start : &6000
File adress length : &0800
File adress execution : &0000
File length file : &09C4

Length of PILOT pulse : 2515
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1318
Length of ONE bit pulse : 2530
Length of PILOT tone : 4096
Used bits in last byte : 8 OK
Data : 263 bytes
Total size : 282 bytes

Sum DATA : 2 056

Duration : 4575 ms
Pause After this block : 17 ms
Duration block + Pause : 4592 ms
Duration block + Pause : 00 h 00 m 04 s		000000: 2C 41 52 32 30 00 00 00 00 00 00 00 00 00 00 00 ,AR20........... 000010: 00 01 00 02 00 08 00 60 FF C4 09 00 00 00 00 00 .......`........ 000020: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000030: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000040: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000050: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000060: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000070: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000080: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000090: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000A0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000B0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000C0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000D0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000E0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000F0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000100: 00 04 B0 FF FF FF FF .......
previousnext* BLOCK 0030 : TURBO LOADING DATA
DATA
Length of PILOT pulse : 2515
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1331
Length of ONE bit pulse : 2492
Length of PILOT tone : 4099
Used bits in last byte : 8 OK
Data : 2069 bytes
Total size : 2088 bytes

Sum DATA : 152 168

Duration : 20129 ms
Pause After this block : 2697 ms
Duration block + Pause : 22826 ms
Duration block + Pause : 00 h 00 m 22 s		000000: 16 41 52 32 30 00 00 00 00 00 00 00 19 C3 09 00 .AR20........... 000010: 54 61 6B 65 20 41 20 43 68 61 6E 63 65 20 20 20 Take A Chance 000020: 20 20 20 20 20 20 20 20 20 00 00 00 00 00 00 00 ....... 000030: 00 55 00 48 6F 77 20 6D 75 63 68 20 69 73 20 74 .U.How much is t 000040: 68 65 20 38 20 77 6F 72 74 68 20 69 6E 20 74 68 he 8 worth in th 000050: 65 6E 75 6D 62 65 72 3A 20 36 2C 34 39 38 3F 1B enumber: 6,498?. 000060: 38 20 75 6E 69 74 73 1B 38 20 74 65 6E 73 1B 38 8 units.8 tens.8 000070: 20 68 75 6E 64 72 65 64 73 1B 38 20 74 68 6F 75 hundreds.8 thou 000080: 73 61 6E 64 73 1B 64 00 41 20 77 6F 6D 61 6E 20 sands.d.A woman 000090: 77 61 73 20 62 6F 72 6E 20 69 6E 20 31 38 33 34 was born in 1834 0000A0: 20 61 6E 64 20 20 6C 69 76 65 64 20 66 6F 72 20 and lived for 0000B0: 36 32 20 79 65 61 72 73 2E 20 49 6E 20 77 68 69 62 years. In whi 0000C0: 63 68 20 20 79 65 61 72 20 64 69 64 20 73 68 65 ch year did she 0000D0: 20 64 69 65 3F 1B 31 38 39 36 1B 31 38 38 39 1B die?.1896.1889. 0000E0: 31 38 39 32 1B 31 38 39 38 1B 49 00 48 6F 77 20 1892.1898.I.How 0000F0: 6D 61 6E 79 20 6D 69 6E 75 74 65 73 20 61 72 65 many minutes are 000100: 20 FA 04 74 68 65 72 65 20 20 20 20 62 65 74 77 ..there betw 000110: 65 65 6E 20 30 36 2E 31 33 20 61 6E 64 20 31 33 een 06.13 and 13 000120: 2E 32 31 3F 1B 34 32 38 1B 34 37 35 1B 34 31 33 .21?.428.475.413 000130: 1B 34 37 39 1B 3A 00 48 6F 77 20 6D 61 6E 79 20 .479.:.How many 000140: 70 65 6E 63 65 20 61 72 65 20 74 68 65 72 65 20 pence are there 000150: 69 6E 20 20 20 60 31 35 2E 33 38 3F 1B 31 35 33 in `15.38?.153 000160: 38 1B 35 33 38 1B 31 35 33 1B 33 38 31 35 1B 50 8.538.153.3815.P 000170: 00 48 6F 77 20 77 6F 75 6C 64 20 31 32 39 32 70 .How would 1292p 000180: 20 62 65 20 77 72 69 74 74 65 6E 20 61 73 20 70 be written as p 000190: 6F 75 6E 64 73 20 61 6E 64 20 70 65 6E 63 65 3F ounds and pence? 0001A0: 1B 60 31 32 2E 39 32 1B 60 31 32 39 2E 32 30 1B .`12.92.`129.20. 0001B0: 60 31 2E 32 39 1B 60 31 32 39 32 2E 30 30 1B 4B `1.29.`1292.00.K 0001C0: 00 55 73 69 6E 67 20 74 68 65 20 32 34 20 68 6F .Using the 24 ho 0001D0: 75 72 20 63 6C 6F 63 6B 2C 20 77 68 61 74 20 74 ur clock, what t 0001E0: 69 6D 65 20 69 73 20 39 2E 32 33 20 70 2E 6D 2E ime is 9.23 p.m. 0001F0: 3F 1B 32 31 2E 32 33 1B 31 37 2E 32 33 1B 32 30 ?.21.23.17.23.20 000200: 2E 32 33 35 21 1B 31 39 2E 32 33 1B 5F 00 57 68 .235!.19.23._.Wh 000210: 61 74 20 69 73 20 74 68 65 20 61 76 65 72 61 67 at is the averag 000220: 65 20 6F 66 20 74 68 65 20 20 20 20 66 6F 6C 6C e of the foll 000230: 6F 77 69 6E 67 20 6E 75 6D 62 65 72 73 3A 20 20 owing numbers: 000240: 20 20 20 20 20 20 20 20 20 20 20 35 33 2C 20 36 53, 6 000250: 31 2C 20 33 33 20 61 6E 64 20 38 35 3F 1B 35 38 1, 33 and 85?.58 000260: 1B 32 33 32 1B 2D 34 1B 39 36 1B 5D 00 48 6F 77 .232.-4.96.].How 000270: 20 6D 75 63 68 20 69 73 20 74 68 65 20 37 20 77 much is the 7 w 000280: 6F 72 74 68 20 69 6E 20 74 68 65 66 6F 6C 6C 6F orth in thefollo 000290: 77 69 6E 67 20 6E 75 6D 62 65 72 3A 20 37 2C 36 wing number: 7,6 0002A0: 32 35 3F 1B 37 20 74 68 6F 75 73 61 6E 64 1B 37 25?.7 thousand.7 0002B0: 20 68 75 6E 64 72 65 64 1B 37 20 74 65 6E 73 1B hundred.7 tens. 0002C0: 37 20 75 6E 69 74 73 1B 49 00 48 6F 77 20 6D 61 7 units.I.How ma 0002D0: 6E 79 20 6D 69 6E 75 74 65 73 20 61 72 65 20 74 ny minutes are t 0002E0: 68 65 72 65 20 20 20 20 62 65 74 77 65 65 6E 20 here between 0002F0: 31 30 2E 34 37 20 61 6E 64 20 32 33 2E 32 33 3F 10.47 and 23.23? 000300: 1B 37 35 36 1B 9A 2B 38 31 36 1B 36 39 36 1B 39 .756..+816.696.9 000310: 38 32 1B 98 00 41 20 66 69 6C 6D 20 61 74 20 74 82...A film at t 000320: 68 65 20 63 69 6E 65 6D 61 20 73 74 61 72 74 65 he cinema starte 000330: 64 20 20 61 74 20 32 2E 33 30 20 70 2E 6D 2E 20 d at 2.30 p.m. 000340: 61 6E 64 20 6C 61 73 74 65 64 20 20 20 20 20 20 and lasted 000350: 20 31 20 68 6F 75 72 20 61 6E 64 20 33 39 20 6D 1 hour and 39 m 000360: 69 6E 75 74 65 73 2E 20 41 74 20 77 68 61 74 74 inutes. At whatt 000370: 69 6D 65 20 64 69 64 20 69 74 20 66 69 6E 69 73 ime did it finis 000380: 68 3F 1B 34 2E 30 39 20 70 2E 6D 2E 1B 33 2E 35 h?.4.09 p.m..3.5 000390: 38 20 70 2E 6D 2E 1B 34 2E 33 39 20 70 2E 6D 2E 8 p.m..4.39 p.m. 0003A0: 1B 33 2E 34 39 20 70 2E 6D 2E 1B 90 00 41 20 74 .3.49 p.m....A t 0003B0: 72 61 69 6E 20 6C 65 61 76 65 73 20 61 74 20 31 rain leaves at 1 0003C0: 2E 34 30 20 70 2E 6D 2E 20 20 20 61 6E 64 20 74 .40 p.m. and t 0003D0: 72 61 76 65 6C 73 20 61 74 20 61 20 73 70 65 65 ravels at a spee 0003E0: 64 20 6F 66 20 20 20 20 20 36 36 6B 6D 20 70 65 d of 66km pe 0003F0: 72 20 68 6F 75 72 2E 20 48 6F 77 20 66 61 72 20 r hour. How far 000400: 68 61 73 20 69 74 20 E9 01 74 72 61 76 65 6C 6C has it ..travell 000410: 65 64 20 62 79 20 33 2E 31 30 20 70 2E 6D 2E 3F ed by 3.10 p.m.? 000420: 20 20 20 1B 39 39 20 6B 6D 1B 37 36 20 6B 6D 1B .99 km.76 km. 000430: 39 33 20 6B 6D 1B 31 30 33 20 6B 6D 1B 4B 00 55 93 km.103 km.K.U 000440: 73 69 6E 67 20 74 68 65 20 32 34 2D 68 6F 75 72 sing the 24-hour 000450: 20 63 6C 6F 63 6B 20 77 68 61 74 20 20 74 69 6D clock what tim 000460: 65 20 69 73 20 33 2E 33 38 20 70 2E 6D 2E 3F 1B e is 3.38 p.m.?. 000470: 31 35 2E 33 38 1B 31 33 2E 33 38 1B 31 34 2E 33 15.38.13.38.14.3 000480: 38 1B 31 36 2E 33 38 1B 6C 00 57 68 61 74 20 69 8.16.38.l.What i 000490: 73 20 74 68 65 20 61 76 65 72 61 67 65 20 6F 66 s the average of 0004A0: 20 74 68 65 20 20 20 20 66 6F 6C 6C 6F 77 69 6E the followin 0004B0: 67 20 6E 75 6D 62 65 72 73 3A 20 20 20 20 20 20 g numbers: 0004C0: 20 20 20 20 20 20 31 38 37 36 2C 20 31 32 30 36 1876, 1206 0004D0: 2C 20 31 31 39 38 20 61 6E 64 20 31 35 32 30 3F , 1198 and 1520? 0004E0: 1B 31 34 35 30 1B 35 38 32 30 1B 33 36 34 1B 31 .1450.5820.364.1 0004F0: 39 38 35 1B 6D 00 4F 66 20 74 68 65 20 66 6F 6C 985.m.Of the fol 000500: 6C 6F 77 69 6E 67 20 6E 75 2A 3C 6D 62 65 72 73 lowing nu*<mbers 000510: 20 77 68 69 63 68 69 73 20 74 68 65 20 73 6D 61 whichis the sma 000520: 6C 6C 65 73 74 3F 20 20 20 20 20 20 20 20 20 20 llest? 000530: 20 20 20 20 30 2E 30 33 2C 20 30 2E 33 30 20 2C 0.03, 0.30 , 000540: 20 30 2E 32 33 20 61 6E 64 20 30 2E 30 32 1B 30 0.23 and 0.02.0 000550: 2E 30 32 1B 30 2E 30 33 1B 30 2E 33 30 1B 30 2E .02.0.03.0.30.0. 000560: 32 33 1B 61 00 49 6E 20 74 68 65 20 66 6F 6C 6C 23.a.In the foll 000570: 6F 77 69 6E 67 20 6E 75 6D 62 65 72 20 68 6F 77 owing number how 000580: 20 20 20 6D 75 63 68 20 69 73 20 74 68 65 20 36 much is the 6 000590: 20 77 6F 72 74 68 3A 20 39 38 36 32 3F 1B 36 20 worth: 9862?.6 0005A0: 74 65 6E 73 1B 36 20 75 6E 69 74 73 1B 36 20 68 tens.6 units.6 h 0005B0: 75 6E 64 72 65 64 73 1B 36 20 74 68 6F 75 73 61 undreds.6 thousa 0005C0: 6E 64 73 1B C5 00 4D 61 6E 64 79 20 77 61 73 20 nds...Mandy was 0005D0: 62 6F 72 6E 20 6F 6E 20 36 74 68 20 4F 63 74 6F born on 6th Octo 0005E0: 62 65 72 2C 31 39 37 33 20 61 6E 64 20 4A 75 6C ber,1973 and Jul 0005F0: 69 61 20 77 61 73 20 62 6F 72 6E 20 6F 6E 20 36 ia was born on 6 000600: 74 68 46 65 62 72 75 61 72 79 2C 19 D2 20 31 39 thFebruary,.. 19 000610: 37 38 2E 20 48 6F 77 20 6D 75 63 68 20 6F 6C 64 78. How much old 000620: 65 72 74 68 61 6E 20 4A 75 6C 69 61 20 69 73 20 erthan Julia is 000630: 4D 61 6E 64 79 3F 1B 34 20 79 65 61 72 73 20 61 Mandy?.4 years a 000640: 6E 64 20 34 20 6D 6F 6E 74 68 73 1B 35 20 79 65 nd 4 months.5 ye 000650: 61 72 73 20 61 6E 64 20 34 20 6D 6F 6E 74 68 73 ars and 4 months 000660: 1B 35 20 79 65 61 72 73 20 61 6E 64 20 36 20 6D .5 years and 6 m 000670: 6F 6E 74 68 73 1B 35 20 79 65 61 72 73 20 61 6E onths.5 years an 000680: 64 20 38 20 6D 6F 6E 74 68 73 1B 6A 00 49 6E 20 d 8 months.j.In 000690: 74 68 65 20 66 6F 6C 6C 6F 77 69 6E 67 20 73 65 the following se 0006A0: 71 75 65 6E 63 65 20 66 69 6E 64 74 68 65 20 6D quence findthe m 0006B0: 69 73 73 69 6E 67 20 6E 75 6D 62 65 72 3A 20 20 issing number: 0006C0: 20 20 20 20 20 20 20 20 20 31 37 38 36 2C 20 31 1786, 1 0006D0: 38 33 38 2C 20 31 38 39 30 20 3F 20 31 39 39 34 838, 1890 ? 1994 0006E0: 1B 31 39 34 32 1B 31 39 33 35 1B 31 39 35 31 1B .1942.1935.1951. 0006F0: 31 39 32 39 1B 6A 00 57 68 61 74 20 69 73 20 74 1929.j.What is t 000700: 68 65 20 61 76 65 72 61 67 65 20 6F 66 52 99 20 he average ofR. 000710: 74 68 65 20 20 20 20 66 6F 6C 6C 6F 77 69 6E 67 the following 000720: 20 6E 75 6D 62 65 72 73 3A 20 20 20 20 20 20 20 numbers: 000730: 20 20 20 20 20 31 36 32 2C 20 31 35 32 2C 20 36 162, 152, 6 000740: 32 31 2C 20 38 30 39 20 61 6E 64 20 32 30 31 1B 21, 809 and 201. 000750: 33 38 39 1B 34 38 36 1B 31 39 34 35 1B 31 39 34 389.486.1945.194 000760: 1B 49 00 48 6F 77 20 6D 61 6E 79 20 6D 69 6E 75 .I.How many minu 000770: 74 65 73 20 61 72 65 20 74 68 65 72 65 20 20 20 tes are there 000780: 20 62 65 74 77 65 65 6E 20 30 38 2E 34 33 20 61 between 08.43 a 000790: 6E 64 20 31 33 2E 32 37 3F 1B 32 38 34 1B 31 36 nd 13.27?.284.16 0007A0: 32 1B 33 34 34 1B 32 32 36 1B 74 00 4F 66 20 74 2.344.226.t.Of t 0007B0: 68 65 20 66 6F 6C 6C 6F 77 69 6E 67 20 6E 75 6D he following num 0007C0: 62 65 72 73 20 77 68 69 63 68 69 73 20 74 68 65 bers whichis the 0007D0: 20 73 6D 61 6C 6C 65 73 74 3A 20 20 20 20 20 20 smallest: 0007E0: 20 20 20 20 20 20 20 20 30 2E 30 30 36 2C 20 30 0.006, 0 0007F0: 2E 30 36 30 2C 20 30 2E 36 30 30 20 61 6E 64 20 .060, 0.600 and 000800: 30 2E 36 30 36 1B 30 2E 30 30 36 1B 30 2E 30 2D 0.606.0.006.0.0- 000810: F3 FF FF FF FF .....
previousnext* BLOCK 0031 : TURBO LOADING DATA
HEADER
Block Name : AR20
Block Number : 2
Block last : YES
File type : Binaire
File adress start : &6800
File adress length : &01C4
File adress execution : &0000
File length file : &09C4

Length of PILOT pulse : 2514
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1316
Length of ONE bit pulse : 2527
Length of PILOT tone : 4099
Used bits in last byte : 8 OK
Data : 263 bytes
Total size : 282 bytes

Sum DATA : 2 558

Duration : 4582 ms
Pause After this block : 18 ms
Duration block + Pause : 4600 ms
Duration block + Pause : 00 h 00 m 04 s		000000: 2C 41 52 32 30 00 00 00 00 00 00 00 00 00 00 00 ,AR20........... 000010: 00 02 FF 02 C4 01 00 68 00 C4 09 00 00 00 00 00 .......h........ 000020: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000030: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000040: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000050: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000060: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000070: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000080: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000090: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000A0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000B0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000C0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000D0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000E0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0000F0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000100: 00 F9 EB FF FF FF FF .......
previousnext* BLOCK 0032 : TURBO LOADING DATA
DATA
Length of PILOT pulse : 2512
Length of SYNC First pulse : 1230
Length of SYNC Second pulse : 1230
Length of ZERO bit pulse : 1328
Length of ONE bit pulse : 2492
Length of PILOT tone : 4097
Used bits in last byte : 8 OK
Data : 521 bytes
Total size : 540 bytes

Sum DATA : 31 899

Duration : 7147 ms
Pause After this block : 65535 ms
Duration block + Pause : 72682 ms
Duration block + Pause : 00 h 01 m 12 s		000000: 16 36 30 1B 30 2E 36 30 30 1B 30 2E 36 30 36 1B .60.0.600.0.606. 000010: 5E 00 48 6F 77 20 6D 75 63 68 20 69 73 20 74 68 ^.How much is th 000020: 65 20 35 20 77 6F 72 74 68 20 69 6E 20 74 68 65 e 5 worth in the 000030: 66 6F 6C 6C 6F 77 69 6E 67 20 6E 75 6D 62 65 72 following number 000040: 3A 20 38 35 30 32 3F 1B 35 20 68 75 6E 64 72 65 : 8502?.5 hundre 000050: 64 73 1B 35 20 75 6E 69 74 73 1B 35 20 74 65 6E ds.5 units.5 ten 000060: 73 1B 35 20 74 68 6F 75 73 61 6E 64 73 1B 69 00 s.5 thousands.i. 000070: 46 69 6E 64 20 74 68 65 20 6D 69 73 73 69 6E 67 Find the missing 000080: 20 6E 75 6D 62 65 72 20 69 6E 20 74 68 65 66 6F number in thefo 000090: 6C 6C 6F 77 69 6E 67 20 73 65 71 75 65 6E 63 65 llowing sequence 0000A0: 3A 20 20 20 20 20 20 20 20 20 20 20 32 35 38 2C : 258, 0000B0: 20 35 33 39 2C 20 38 32 30 2C 20 3F 2C 20 31 33 539, 820, ?, 13 0000C0: 38 32 1B 31 31 30 31 1B 31 30 39 39 1B 31 30 39 82.1101.1099.109 0000D0: 33 1B 31 31 31 35 1B 72 00 57 68 69 63 68 20 69 3.1115.r.Which i 0000E0: 73 20 74 68 65 20 6C 61 72 67 65 73 74 20 6F 66 s the largest of 0000F0: 20 74 68 65 20 20 20 66 6F 6C 6C 6F 77 69 6E 67 the following 000100: 20 35 2D 6E 75 6D 62 65 72 73 3A 20 20 20 20 20 5-numbers: 000110: 20 20 20 20 20 20 20 30 2E 30 38 39 2C 20 30 2E 0.089, 0. 000120: 30 30 38 39 2C 20 30 2E 37 39 2C 20 30 2E 30 37 0089, 0.79, 0.07 000130: 39 3F 1B 30 2E 37 39 1B 30 2E 30 38 39 1B 30 2E 9?.0.79.0.089.0. 000140: 30 30 38 39 1B 30 2E 30 37 39 1B 4C 00 55 73 69 0089.0.079.L.Usi 000150: 6E 67 20 74 68 65 20 32 34 2D 68 6F 75 72 20 63 ng the 24-hour c 000160: 6C 6F 63 6B 20 77 68 61 74 20 20 74 69 6D 65 20 lock what time 000170: 69 73 20 31 30 2E 34 39 20 70 2E 6D 2E 3F 1B 32 is 10.49 p.m.?.2 000180: 32 2E 34 39 1B 32 33 2E 34 39 1B 32 30 2E 34 39 2.49.23.49.20.49 000190: 1B 32 31 2E 34 39 1B 2F 00 32 31 28 35 36 20 2B .21.49./.21(56 + 0001A0: 20 34 37 20 2D 20 35 33 29 20 2B 20 33 31 20 3D 47 - 53) + 31 = 0001B0: 20 3F 1B 31 30 38 31 1B 36 38 34 1B 31 36 38 33 ?.1081.684.1683 0001C0: 1B 32 30 30 31 1B 1C 00 00 00 00 00 00 00 00 00 .2001........... 0001D0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0001E0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 0001F0: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ................ 000200: 00 00 00 9B 02 FF FF FF FF .........
previoustop
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